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三角恒等式sānjiǎo héngděngshì

trigonometric identities
5 min read
Updated November 2, 2025
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Core Concept

Trigonometric Identities are equations involving trigonometric functions that are true for all values in their domain. Mastering these identities is key to learning trigonometry.

Fundamental Identities

Pythagorean Identities

sin⁡2α+cos⁡2α=1\sin^2\alpha + \cos^2\alpha = 1 1+tan⁡2α=sec⁡2α1 + \tan^2\alpha = \sec^2\alpha

Quotient Identities

tan⁡α=sin⁡αcos⁡α\tan\alpha = \frac{\sin\alpha}{\cos\alpha}

Reduction Formulas

Negative Angles

sin⁡(−α)=−sin⁡α\sin(-\alpha) = -\sin\alpha cos⁡(−α)=cos⁡α\cos(-\alpha) = \cos\alpha

Complementary Angles

sin⁡(π2−α)=cos⁡α\sin\left(\frac{\pi}{2} - \alpha\right) = \cos\alpha cos⁡(π2−α)=sin⁡α\cos\left(\frac{\pi}{2} - \alpha\right) = \sin\alpha

Supplementary Angles

sin⁡(π−α)=sin⁡α\sin(\pi - \alpha) = \sin\alpha cos⁡(π−α)=−cos⁡α\cos(\pi - \alpha) = -\cos\alpha

Sum and Difference Formulas

Sine

sin⁡(α±β)=sin⁡αcos⁡β±cos⁡αsin⁡β\sin(\alpha \pm \beta) = \sin\alpha\cos\beta \pm \cos\alpha\sin\beta

Cosine

cos⁡(α±β)=cos⁡αcos⁡β∓sin⁡αsin⁡β\cos(\alpha \pm \beta) = \cos\alpha\cos\beta \mp \sin\alpha\sin\beta

Tangent

tan⁡(α±β)=tan⁡α±tan⁡β1∓tan⁡αtan⁡β\tan(\alpha \pm \beta) = \frac{\tan\alpha \pm \tan\beta}{1 \mp \tan\alpha\tan\beta}

Double Angle Formulas

Sine

sin⁡2α=2sin⁡αcos⁡α\sin 2\alpha = 2\sin\alpha\cos\alpha

Cosine

cos⁡2α=cos⁡2α−sin⁡2α=2cos⁡2α−1=1−2sin⁡2α\cos 2\alpha = \cos^2\alpha - \sin^2\alpha = 2\cos^2\alpha - 1 = 1 - 2\sin^2\alpha

Power-Reducing Formulas: cos⁡2α=1+cos⁡2α2\cos^2\alpha = \frac{1 + \cos 2\alpha}{2} sin⁡2α=1−cos⁡2α2\sin^2\alpha = \frac{1 - \cos 2\alpha}{2}

Tangent

tan⁡2α=2tan⁡α1−tan⁡2α\tan 2\alpha = \frac{2\tan\alpha}{1 - \tan^2\alpha}

Auxiliary Angle Formula

asin⁡x+bcos⁡x=a2+b2sin⁡(x+φ)a\sin x + b\cos x = \sqrt{a^2 + b^2}\sin(x + \varphi)

where tan⁡φ=ba\tan\varphi = \frac{b}{a}

CSCA Practice Problems

[Example 1] Basic (Difficulty ★★☆☆☆)

Simplify: sin⁡2α+cos⁡2α+tan⁡2α\sin^2\alpha + \cos^2\alpha + \tan^2\alpha

Solution: sin⁡2α+cos⁡2α+tan⁡2α=1+tan⁡2α=sec⁡2α\sin^2\alpha + \cos^2\alpha + \tan^2\alpha = 1 + \tan^2\alpha = \sec^2\alpha

Answer: sec⁡2α\sec^2\alpha


[Example 2] Intermediate (Difficulty ★★★☆☆)

Given sin⁡α=35\sin\alpha = \frac{3}{5}, α∈(0,π2)\alpha \in (0, \frac{\pi}{2}), find sin⁡2α\sin 2\alpha.

Solution:

cos⁡α=1−sin⁡2α=45\cos\alpha = \sqrt{1 - \sin^2\alpha} = \frac{4}{5}

sin⁡2α=2sin⁡αcos⁡α=2×35×45=2425\sin 2\alpha = 2\sin\alpha\cos\alpha = 2 \times \frac{3}{5} \times \frac{4}{5} = \frac{24}{25}

Answer: 2425\frac{24}{25}

Common Misconceptions

❌ Misconception 1: Wrong reduction formula

Wrong: sin⁡(π−α)=−sin⁡α\sin(\pi - \alpha) = -\sin\alpha

Correct: sin⁡(π−α)=sin⁡α\sin(\pi - \alpha) = \sin\alpha

❌ Misconception 2: Confusing sum formulas

Wrong: sin⁡(α+β)=sin⁡α+sin⁡β\sin(\alpha + \beta) = \sin\alpha + \sin\beta

Correct: sin⁡(α+β)=sin⁡αcos⁡β+cos⁡αsin⁡β\sin(\alpha + \beta) = \sin\alpha\cos\beta + \cos\alpha\sin\beta

Study Tips

  1. ✅ Categorize: Basic, reduction, sum/difference, double angle
  2. ✅ Understand derivation: Don't just memorize
  3. ✅ Practice: Reinforce through exercises
  4. ✅ Connect formulas: Many can be derived from each other

💡 Exam Tip: Trigonometric identities are core to trigonometry, mandatory in CSCA! Mastering formulas is key to problem-solving.

Practice Exercises

Practice to reinforce your understanding