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algebraDifficulty: Basicalgebrainequality
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不等式bùděngshì

inequality
3 min read
Updated October 29, 2025
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Core Concept

An inequality is a mathematical statement that uses inequality symbols (>, <, ≥, ≤) to express the relationship between two numbers or expressions.

Basic Inequality Symbols

  • a>ba > b: aa is greater than bb
  • a<ba < b: aa is less than bb
  • a≥ba \geq b: aa is greater than or equal to bb
  • a≤ba \leq b: aa is less than or equal to bb
  • a≠ba \neq b: aa is not equal to bb

Properties of Inequalities

1. Transitivity

a>b,b>c⇒a>ca > b, b > c \Rightarrow a > c

2. Addition Property

a>b⇒a+c>b+ca > b \Rightarrow a + c > b + c

3. Multiplication Property

  • When c>0c > 0: a>b⇒ac>bca > b \Rightarrow ac > bc
  • When c<0c < 0: a>b⇒ac<bca > b \Rightarrow ac < bc (inequality reverses!)

Common Types of Inequalities

Linear Inequality

2x+3>7⇒x>22x + 3 > 7 \Rightarrow x > 2

Quadratic Inequality

x2−5x+6<0⇒2<x<3x^2 - 5x + 6 < 0 \Rightarrow 2 < x < 3

Rational Inequality

x−1x+2>0⇒x<−2 or x>1\frac{x-1}{x+2} > 0 \Rightarrow x < -2 \text{ or } x > 1

Absolute Value Inequality

∣x∣<a⇒−a<x<a(a>0)|x| < a \Rightarrow -a < x < a \quad (a > 0)

CSCA Practice Problems

💡 Note: The following practice problems are designed based on the CSCA exam syllabus and Chinese standardized test formats to help students familiarize themselves with question types and problem-solving approaches.

Example 1: Basic (Difficulty ★★☆☆☆)

Solve the inequality: 3x−5<73x - 5 < 7

Solution: 3x<123x < 12 x<4x < 4

Answer: x<4x < 4 or (−∞,4)(-\infty, 4)


Example 2: Intermediate (Difficulty ★★★☆☆)

Solve the inequality: x2−3x−4≤0x^2 - 3x - 4 \leq 0

Solution:

Step 1: Factor x2−3x−4=(x−4)(x+1)x^2 - 3x - 4 = (x-4)(x+1)

Step 2: Find critical points x=−1x = -1 or x=4x = 4

Step 3: Number line method

  • When x<−1x < -1: (x−4)(x+1)>0(x-4)(x+1) > 0
  • When −1≤x≤4-1 \leq x \leq 4: (x−4)(x+1)≤0(x-4)(x+1) \leq 0 ✓
  • When x>4x > 4: (x−4)(x+1)>0(x-4)(x+1) > 0

Answer: −1≤x≤4-1 \leq x \leq 4 or [−1,4][-1, 4]

Common Mistakes

❌ Mistake 1: Forgetting to reverse when multiplying by negative

Wrong: −2x>4-2x > 4, divide both sides by −2-2 to get x>−2x > -2 ✗

Correct: −2x>4-2x > 4, divide both sides by −2-2 to get x<−2x < -2 ✓

❌ Mistake 2: Absolute value inequality error

Wrong: ∣x∣>2|x| > 2 has solution −2<x<2-2 < x < 2 ✗

Correct: ∣x∣>2|x| > 2 has solution x<−2x < -2 or x>2x > 2 ✓

Study Tips

  1. ✅ Master properties, especially reversing when multiplying/dividing by negatives
  2. ✅ Use number line method for quadratic inequalities
  3. ✅ Convert rational inequalities to polynomial form
  4. ✅ Use case analysis for absolute value inequalities

💡 Exam Tip: Inequalities are essential CSCA content, accounting for about 25% of algebra problems. Master all types!

How the real exam tests it

Questions from real CSCA papers that test this term. Work each one out before you open the answer.

  1. CSCA Math December 2025 Past Paper
    Given a>ba>b, which statement is true?
    • A.5a>5b5a>5b
    • B.1a<1b\frac{1}{a}<\frac{1}{b}
    • C.a2>b2a^2>b^2
    • D.sin⁡a>sin⁡b\sin a>\sin b
    Show answer & solution

    Answer: A

    Answer: A Multiplying both sides of a>ba>b by the positive number 5 preserves the inequality, so 5a>5b5a>5b. Choose A.
    See it in the full CSCA Math December 2025 Past Paper
  2. CSCA Math January 2026 Past Paper
    Let a,b,ca , b , c be three real numbers. Which of the following statements is correct? ( )
    • A.If a>ba > b, then ac>bca c > b c
    • B.If a>ba > b, then a+c>b+ca + c > b + c
    • C.If ac>bca c > b c, then a>ba > b
    • D.If a>ba > b, then a2>b2a ^ { 2 } > b ^ { 2 }
    Show answer & solution

    Answer: B

    Which inequality property is correct? If a>b\mathrm { a } > \mathrm { b }, adding the same number c to both sides preserves the inequality: a+c>b+c\mathrm { a } + \mathrm { c } > \mathrm { b } + \mathrm { c }.
    Take the full CSCA Math January 2026 Past Paper — timed & graded
  3. CSCA Math March 2026 Past Paper
    Given a>b\mathrm { a } > \mathrm { b }, which of the following must be true?
    • A.a3>b3a ^ { 3 } > b ^ { 3 }
    • B.∣a∣>∣b∣| \mathrm { a } | > | \mathrm { b } |
    • C.a2>b2a ^ { 2 } > b ^ { 2 }
    • D.∣a∣<∣b∣| \mathrm { a } | < | \mathrm { b } |
    Show answer & solution

    Answer: A

    y=x3y = x ^ { 3 } is strictly increasing on R\mathbb { R }. If a>ba > b then a3>b3a ^ { 3 } > b ^ { 3 }. Options B, C, D can be disproved by counterexamples.
    Take the full CSCA Math March 2026 Past Paper — timed & graded

Practice Exercises

Practice to reinforce your understanding