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判别式pànbiéshì

discriminant
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更新于 2025-01-24
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Core Concept

The discriminant of a quadratic equation ax2+bx+c=0ax^2 + bx + c = 0 is defined as:

Δ=b24ac\Delta = b^2 - 4ac

The discriminant determines the nature (type and number) of the roots of the quadratic equation.

Root Analysis

DiscriminantNumber of Real RootsNature of Roots
Δ>0\Delta > 0TwoTwo distinct real roots
Δ=0\Delta = 0OneOne repeated real root (double root)
Δ<0\Delta < 0ZeroTwo complex conjugate roots

Case 1: Δ>0\Delta > 0 (Two Distinct Real Roots)

The roots are: x1=b+Δ2a,x2=bΔ2ax_1 = \frac{-b + \sqrt{\Delta}}{2a}, \quad x_2 = \frac{-b - \sqrt{\Delta}}{2a}

Case 2: Δ=0\Delta = 0 (One Repeated Root)

The root is: x=b2ax = -\frac{b}{2a}

The parabola is tangent to the x-axis at this point.

Case 3: Δ<0\Delta < 0 (No Real Roots)

The roots are complex: x=b±Δ2a=b±iΔ2ax = \frac{-b \pm \sqrt{\Delta}}{2a} = \frac{-b \pm i\sqrt{|\Delta|}}{2a}

The parabola does not intersect the x-axis.

Graphical Interpretation

For the quadratic function f(x)=ax2+bx+cf(x) = ax^2 + bx + c:

  • Δ>0\Delta > 0: Parabola crosses x-axis at two points
  • Δ=0\Delta = 0: Parabola touches x-axis at exactly one point (vertex)
  • Δ<0\Delta < 0: Parabola does not touch x-axis

CSCA Practice Problems

💡 Note: The following practice problems are designed based on the CSCA exam syllabus.

Example 1: Basic (Difficulty ★★☆☆☆)

Determine the nature of roots for x24x+4=0x^2 - 4x + 4 = 0.

Solution: Δ=(4)24(1)(4)=1616=0\Delta = (-4)^2 - 4(1)(4) = 16 - 16 = 0

Since Δ=0\Delta = 0, there is one repeated root.

Answer: One repeated real root: x=2x = 2


Example 2: Intermediate (Difficulty ★★★☆☆)

For what values of kk does x2+kx+9=0x^2 + kx + 9 = 0 have two equal real roots?

Solution:

For equal roots, we need Δ=0\Delta = 0: Δ=k24(1)(9)=k236=0\Delta = k^2 - 4(1)(9) = k^2 - 36 = 0 k2=36k^2 = 36 k=±6k = \pm 6

Answer: k=6k = 6 or k=6k = -6


Example 3: Advanced (Difficulty ★★★★☆)

Find the range of mm such that x2+2x+m=0x^2 + 2x + m = 0 has two distinct negative roots.

Solution:

Let x1,x2x_1, x_2 be the roots. We need:

  1. Two distinct real roots: Δ>0\Delta > 0
  2. Both roots negative: x1+x2<0x_1 + x_2 < 0 AND x1x2>0x_1 \cdot x_2 > 0

From Vieta's formulas:

  • x1+x2=2<0x_1 + x_2 = -2 < 0 ✓ (always satisfied)
  • x1x2=m>0x_1 \cdot x_2 = m > 0

From discriminant: Δ=44m>0\Delta = 4 - 4m > 0 1m>01 - m > 0 m<1m < 1

Combining: 0<m<10 < m < 1

Answer: m(0,1)m \in (0, 1)


Example 4: Advanced (Difficulty ★★★★☆)

If ax2+bx+c=0ax^2 + bx + c = 0 (a0a \neq 0) has roots x1x_1 and x2x_2, express x1x2|x_1 - x_2| in terms of aa, bb, cc.

Solution:

(x1x2)2=(x1+x2)24x1x2(x_1 - x_2)^2 = (x_1 + x_2)^2 - 4x_1x_2

By Vieta's formulas: (x1x2)2=(ba)24ca=b2a24ca=b24aca2=Δa2(x_1 - x_2)^2 = \left(-\frac{b}{a}\right)^2 - 4 \cdot \frac{c}{a} = \frac{b^2}{a^2} - \frac{4c}{a} = \frac{b^2 - 4ac}{a^2} = \frac{\Delta}{a^2}

Therefore: x1x2=Δa=b24aca|x_1 - x_2| = \frac{\sqrt{\Delta}}{|a|} = \frac{\sqrt{b^2 - 4ac}}{|a|}

Answer: x1x2=b24aca|x_1 - x_2| = \dfrac{\sqrt{b^2 - 4ac}}{|a|}

Applications

1. Line-Curve Intersection

To find how many times a line intersects a parabola:

  1. Substitute the line equation into the parabola equation
  2. Get a quadratic equation
  3. Use discriminant to count intersection points

2. Tangency Conditions

A line is tangent to a parabola when Δ=0\Delta = 0.

Example: For y=x2y = x^2 and y=kx1y = kx - 1 to be tangent: x2=kx1x^2 = kx - 1 x2kx+1=0x^2 - kx + 1 = 0 Δ=k24=0\Delta = k^2 - 4 = 0 k=±2k = \pm 2

Common Mistakes

❌ Mistake 1: Sign Error in Formula

Wrong: Δ=b2+4ac\Delta = b^2 + 4ac

Correct: Δ=b24ac\Delta = b^2 - 4ac

❌ Mistake 2: Forgetting to Consider All Conditions

When finding roots with specific properties (both positive, both negative, etc.), you must check:

  • Discriminant condition (Δ\Delta)
  • Sum of roots condition
  • Product of roots condition

❌ Mistake 3: Confusing Equal Roots with No Roots

Wrong: Δ=0\Delta = 0 means no real roots ✗

Correct: Δ=0\Delta = 0 means one repeated real root; Δ<0\Delta < 0 means no real roots ✓

Study Tips

  1. Memorize the formula: Δ=b24ac\Delta = b^2 - 4ac
  2. Connect to graphs: Visualize parabola crossing/touching/missing x-axis
  3. Combine with Vieta: Many problems need both discriminant and Vieta's formulas
  4. Check all conditions: For constrained roots, check Δ\Delta, sum, and product

💡 Exam Tip: The discriminant appears in many CSCA problems about root existence. Always check Δ\Delta first when a problem mentions "real roots" or "no real roots"!