Skip to main content
返回术语表
algebra难度:基础algebraequationquadratic
Share

二次方程èrcì fāngchéng

quadratic equation
4 分钟阅读
更新于 2025-10-29
已完成

Core Concept

A quadratic equation is a polynomial equation where the highest power of the variable is 2. It is one of the most fundamental equation types in algebra.

Standard Form

ax2+bx+c=0(a0)ax^2 + bx + c = 0 \quad (a \neq 0)

where:

  • aa is the coefficient of x2x^2 (cannot be 0)
  • bb is the coefficient of xx
  • cc is the constant term
  • xx is the variable

Solution Methods

Method 1: Factoring

When the equation can be factored, this is the most direct approach.

Example: x25x+6=0x^2 - 5x + 6 = 0

Step 1: Factor (x2)(x3)=0(x - 2)(x - 3) = 0

Step 2: Set each factor to zero x2=0 or x3=0x - 2 = 0 \text{ or } x - 3 = 0

Answer: x=2x = 2 or x=3x = 3

Method 2: Completing the Square

Transform the equation into a perfect square.

Example: x2+6x+5=0x^2 + 6x + 5 = 0

Step 1: Rearrange x2+6x=5x^2 + 6x = -5

Step 2: Complete the square x2+6x+9=5+9x^2 + 6x + 9 = -5 + 9 (x+3)2=4(x + 3)^2 = 4

Step 3: Take square root x+3=±2x + 3 = \pm 2

Answer: x=1x = -1 or x=5x = -5

Method 3: Quadratic Formula

This universal method works for all quadratic equations:

x=b±b24ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}

where Δ=b24ac\Delta = b^2 - 4ac is called the discriminant.

Discriminant Analysis

  • Δ>0\Delta > 0: Two distinct real roots
  • Δ=0\Delta = 0: Two equal real roots (repeated root)
  • Δ<0\Delta < 0: No real roots (two complex conjugate roots)

Vieta's Formulas

If x1x_1 and x2x_2 are roots of ax2+bx+c=0ax^2 + bx + c = 0, then:

x1+x2=bax_1 + x_2 = -\frac{b}{a} (sum of roots)

x1x2=cax_1 \cdot x_2 = \frac{c}{a} (product of roots)

Real-World Applications

Application 1: Area Problem

Problem: A rectangular plot has length 4m more than width. Area is 60m². Find dimensions.

Solution: Let width = xx, then length = x+4x + 4

x(x+4)=60x(x + 4) = 60 x2+4x60=0x^2 + 4x - 60 = 0 (x+10)(x6)=0(x + 10)(x - 6) = 0

Answer: Width = 6m, Length = 10m (discard negative value)

Application 2: Projectile Motion

Problem: Object thrown upward with height h=20t5t2h = 20t - 5t^2 (meters). When does it hit ground?

Solution: Set h=0h = 0 20t5t2=020t - 5t^2 = 0 5t(4t)=05t(4 - t) = 0

Answer: t=4t = 4 seconds (t=0t = 0 is launch time)

Application 3: Profit Maximization

Problem: Product priced at xx sells (100x)(100-x) units daily. Cost is $40/unit. Find optimal price.

Profit function: P=(x40)(100x)=x2+140x4000P = (x - 40)(100 - x) = -x^2 + 140x - 4000

Maximum: At vertex x=1402(1)=70x = -\frac{140}{2(-1)} = 70

Answer: Price at $70 maximizes profit

CSCA Practice Problems

💡 Note: The following practice problems are designed based on the CSCA exam syllabus and Chinese standardized test formats to help students familiarize themselves with question types and problem-solving approaches.

Example 1: Basic (Difficulty ★★☆☆☆)

Solve by factoring: x27x+12=0x^2 - 7x + 12 = 0

Options:

  • A. x=2x = 2 or x=5x = 5
  • B. x=3x = 3 or x=4x = 4
  • C. x=1x = 1 or x=12x = 12
  • D. x=3x = -3 or x=4x = -4

Solution: x27x+12=(x3)(x4)=0x^2 - 7x + 12 = (x - 3)(x - 4) = 0 x=3 or x=4x = 3 \text{ or } x = 4

Answer: B


Example 2: Intermediate (Difficulty ★★★☆☆)

If x26x+k=0x^2 - 6x + k = 0 has two equal real roots, find kk.

Solution:

Equal roots means Δ=0\Delta = 0: Δ=(6)24(1)(k)=0\Delta = (-6)^2 - 4(1)(k) = 0 364k=036 - 4k = 0 k=9k = 9

Answer: k=9k = 9


Example 3: Advanced (Difficulty ★★★★☆)

If x1x_1, x2x_2 are roots of x23x1=0x^2 - 3x - 1 = 0, find x12+x22x_1^2 + x_2^2 without solving.

Solution:

By Vieta's formulas: x1+x2=3,x1x2=1x_1 + x_2 = 3, \quad x_1 x_2 = -1

Using identity: x12+x22=(x1+x2)22x1x2=92(1)=11x_1^2 + x_2^2 = (x_1 + x_2)^2 - 2x_1x_2 = 9 - 2(-1) = 11

Answer: 1111

Common Mistakes

❌ Mistake 1: Forgetting a0a \neq 0

Wrong: 0x2+3x+2=00x^2 + 3x + 2 = 0 is a quadratic equation ✗

Correct: When a=0a = 0, it becomes a linear equation ✓

❌ Mistake 2: Wrong sign in quadratic formula

Wrong: x=b±b2+4ac2ax = \frac{-b \pm \sqrt{b^2 + 4ac}}{2a}

Correct: x=b±b24ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}

❌ Mistake 3: Vieta's formula sign error

Wrong: x1+x2=bax_1 + x_2 = \frac{b}{a}

Correct: x1+x2=bax_1 + x_2 = -\frac{b}{a}

❌ Mistake 4: Not checking for extraneous solutions

Correction: In real-world problems, verify solutions make physical sense (e.g., lengths can't be negative).

Study Tips

  1. Master all three methods: Factoring is fastest, completing square shows concept, formula is universal
  2. Discriminant is key: Always calculate Δ\Delta to determine root types
  3. Vieta's formulas are tested: Practice finding expressions without solving
  4. Check real-world answers: Discard unreasonable solutions

💡 Exam Tip: Quadratic equations are core CSCA algebra content, accounting for about 60% of equation problems. Memorize the formula and Vieta's formulas!

相关术语

前置知识 - 建议先学习

相关术语 - 一起学习效果更好

进阶学习 - 掌握后可以学这些

对比学习 - 容易混淆,注意区别