Velocity and Acceleration

How the real exam tests it

Questions from real CSCA papers that test this concept. Work each one out before you open the answer.

1. CSCA Physics December 2025 Past Paper
   As shown in the figure, an object moves from point $A$ through point $B$ to point $C$ along two semicircles with radius $R = 6 \mathrm {~m}$, taking a time of $t = 4 \mathrm {~s}$. The magnitude of its average velocity is ().
   • A．$6 \mathrm {~m} / \mathrm { s }$
   • B．$12 \mathrm {~m} / \mathrm { s }$
   • C．$6 \pi \mathrm {~m} / \mathrm { s }$
   • D．$3 \pi \mathrm {~m} / \mathrm { s }$
   Show answer & solution

   Answer: A

   1 Displacement is the straight line from A to C. The two semicircles each have diameter $2 R = 12 \mathrm {~m}$, so the displacement is $x = 4 R = 24 \mathrm {~m}$. 2 Average velocity $= x / t = 24 \mathrm {~m} / 4 \mathrm {~s} = 6 \mathrm {~m} / \mathrm { s }$, option A. 3 Note: the path length is $2 \pi R = 12 \pi \mathrm {~m}$, so $3 \pi \mathrm {~m} / \mathrm { s }$ (option D) is the average speed, not the average velocity.
   See it in the full CSCA Physics December 2025 Past Paper
2. CSCA Physics March 2026 Past Paper
   The x-t graph for a toy car in linear motion is shown. Which statement is correct?
   • A．Displacement from $0 - 4 \mathrm {~s}$ is 8 m
   • B．Velocity from $0 - 4 \mathrm {~s}$ is $1.0 \mathrm {~m} / \mathrm { s }$
   • C．Average velocity from $0 - 5 \mathrm {~s}$ is $0.8 \mathrm {~m} / \mathrm { s }$
   • D．Velocity from $4 - 5 \mathrm {~s}$ is $0.8 \mathrm {~m} / \mathrm { s }$
   Show answer & solution

   Answer: B

   From graph: $0 - 4 \mathrm {~s} , x$ goes from 0 to 4 m linearly. A: displacement is 4 m , not 8 . $B : v = 4 / 4 = 1.0 \mathrm {~m} / \mathrm { s }$, correct. C: at 5 s position returns to 0 , average velocity $= 0 / 5 = 0$. D: $4 - 5 \mathrm {~s}$, displacement $= 4 \mathrm {~m}$ in 1 s , speed $= 4 \mathrm {~m} / \mathrm { s }$. Answer: B.
   Take the full CSCA Physics March 2026 Past Paper — timed & graded
3. CSCA Physics April 2026 Past Paper
   As shown in the figure, an object travels along a path consisting of two semicircles end-to-end (each of radius 4 m ) from $A$ through $B$ to $C$. Points $A , B , C$ are collinear along the east-west direction. The travel takes 2 s . The magnitude of the average velocity is
   • A．$4 \mathrm {~m} / \mathrm { s }$
   • B．$0 \mathrm {~m} / \mathrm { s }$
   • C．$2 \mathrm {~m} / \mathrm { s }$
   • D．$8 \mathrm {~m} / \mathrm { s }$
   Show answer & solution

   Answer: D

   Each semicircle has diameter $2 R = 8 \mathrm {~m}$, so $| A B | = | B C | = 8 \mathrm {~m}$. Because $A$, $B , C$ are collinear, the total displacement is $| A C | = 16 \mathrm {~m}$. Average velocity $= \frac { | A C | } { t } = \frac { 16 } { 2 } = 8 \mathrm {~m} / \mathrm { s }$.
   Take the full CSCA Physics April 2026 Past Paper — timed & graded