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Kinematics - Practice Questions (40)

Question 1: 1. The ball falls from a height of 3 meters, is bounced back by the floor in the opposite direction,...

1. The ball falls from a height of 3 meters, is bounced back by the floor in the opposite direction, and is caught at a height of 1 meter.

  • A. A. Displacement is 2 meters in a downward direction
  • B. B. Displacement 1 meter, direction up
  • C. C. The distance traveled is 4 meters in a downward direction
  • D. D. The distance traveled is 2 meters and the distance is scalar

Answer: A

Solution: The ball dropped from a height of 3 m by the floor bounced back to a height of 1 m, the length of the trajectory is the distance, equal to 4 m, distance is a scalar, there is no direction; from the start to the end of the length of the directed line segment is the size of the displacement, equal to 2 m, the direction of the downward. Therefore, choose A.

Question 2: 2. As shown in the figure, the point $O$ is the origin of the $x$ axis, $O A = A B = O C = C D = 1 \...

2. As shown in the figure, the point $O$ is the origin of the $x$ axis, $O A = A B = O C = C D = 1 \mathrm {~m}$. A mass moving on the $x$ axis starts from the point $A$ and moves along the $x$ axis in the positive direction to the point $B$, and then returns to move in the negative direction along the $x$ axis. The motion is in the negative direction of the $x$ axis. The following statements are true about the motion of the mass point ![](/images/questions/phys-kinematics/image-001.jpg)

  • A. A. 2 m from $A \rightarrow B \rightarrow C$.
  • B. B. Displacement from $A \rightarrow B \rightarrow C$ is 2 m.
  • C. C. Displacement from $A \rightarrow B \rightarrow O$ - 3 m
  • D. D. 3 m from $A \rightarrow B \rightarrow O$.

Answer: D

Solution: A. According to the meaning of the question, the mass point moves from $A \rightarrow B$ along the positive direction of the $x$ axis for $1 \mathrm {~m} , B \rightarrow C$ and along the negative direction of the $x$ axis for 3 m, the distance traveled from $A \rightarrow B \rightarrow C$ is $4 \mathrm {~m} , ~ \mathrm {~A}$ incorrect. The distance traveled from $4 \mathrm {~m} , ~ \mathrm {~A}$ is $4 \mathrm {~m} , ~ \mathrm {~A}$ wrong; B. The displacement from $A \rightarrow B \rightarrow C$ is a directed line segment pointing from $A$ to $C$, which is 2 m in the negative direction of the $x$ axis, i.e., the displacement is $- 2 \mathrm {~m} , ~ \mathrm {~B}$. ERROR ; CD. Similarly, the mass point from $A \rightarrow B \rightarrow O$ first along the $x$ axis in the positive direction of 1 m, then along the $x$ axis in the negative direction of the movement of 2 m, then from the $A \rightarrow B \rightarrow O$ of the journey is 3 m, the displacement of the $A \rightarrow B \rightarrow O$ is the $x$ axis of the positive direction of the $x$ axis by The distance from $A \rightarrow B \rightarrow O$ is 3 m, and the displacement is the directed line segment from $A$ to $O$, and the displacement is -1 m. C is incorrect, and D is correct.

Question 3: 3. Of the following physical quantities, the following are vectors

3. Of the following physical quantities, the following are vectors

  • A. A. centripetal acceleration
  • B. B. accomplishment
  • C. C. power (output)
  • D. D. gravitational potential energy (physics)

Answer: A

Solution: Centripetal acceleration is a physical quantity that has both magnitude and direction and is a vector quantity, while work, power and gravitational potential energy have only magnitude and no direction and are scalar quantities.

Question 4: 4. The following sets of physical quantities are all scalars.

4. The following sets of physical quantities are all scalars.

  • A. A. Time, displacement, velocity
  • B. B. Distance, time, rate
  • C. C. Average speed, velocity, rate, acceleration, force
  • D. D. Velocity, velocity change, acceleration, force

Answer: B

Solution: A. Time is a scalar quantity and displacement and velocity are vectors, A is incorrect; B. Distance, time, and rate are scalars, B is correct; C. Rate is a scalar quantity and average speed, velocity, acceleration, and force are vectors, C is incorrect; D. velocity, change in velocity, acceleration, and force are all vectors, D is incorrect.

Question 5: 5. The following physical quantities: (1) velocity, (2) displacement, (3) distance traveled, (4) for...

5. The following physical quantities: (1) velocity, (2) displacement, (3) distance traveled, (4) force, (5) mass, (6) time, and (7) temperature. Of these, the one that is all vector quantities is

  • A. A. (1) (2) (3)
  • B. B. (5) (6) (7)
  • C. C. (1) (2) (4)
  • D. D. (3) (4) (6)

Answer: C

Solution: Vectors are physical quantities that have both magnitude and direction, velocity, displacement, and force are all vectors. Scalars are physical quantities that have only magnitude and no direction, distance, mass, time, and temperature are scalars, so C is correct and ABD is wrong. Therefore, C is correct and ABD is wrong.

Question 6: 6. On Galileo's study of the laws of free-fall motion by means of the inclined plane experiment, the...

6. On Galileo's study of the laws of free-fall motion by means of the inclined plane experiment, the following statements are correct

  • A. A. Galileo conjectured that the speed of motion was proportional to time and verified this directly with experiments
  • B. B. Galileo's ideal inclined plane experiment had no basis in fact, just scientific abstraction
  • C. C. In his experiments, Galileo used a combination of abstract thinking, mathematical reasoning and scientific experimentation
  • D. D. Galileo directly proved experimentally that free-fall motion is uniformly accelerated linear motion and measured the value of the acceleration of gravity

Answer: C

Solution: Galileo guessed that the speed of free-fall motion is proportional to the falling time, and did not directly verify, but in the inclined plane experiment on the basis of idealized reasoning, so A error. In Galileo's study of the relationship between force and motion, it is on the basis of the inclined plane experiment, the successful design of the ideal inclined plane experiment, he is based on actual experiments, to seize the objective facts of the main factors, ignoring the secondary factors, so as to be able to more profoundly reveal the laws of nature. Therefore, the ideal experiment is an extension of the actual experiment, not the actual experiment, is based on the actual facts of the logical scientific inference, so B error, C correct. Galileo arrived at the core idea of the law of free-fall motion is a combination of reliable experiments and logical reasoning, idealized reasoning, proved that the free-fall motion is a uniformly accelerated straight-line motion, so D is wrong; Therefore, choose C.

Question 7: 7. The following physical quantities are vectors

7. The following physical quantities are vectors

  • A. A. electromotive force
  • B. B. input voltage
  • C. C. electric field strength
  • D. D. resistive

Answer: C

Solution: A. Potential is a scalar quantity, so A is wrong; B. Voltage is a scalar quantity, so B is wrong ; C. Electric field strength is a vector, so C is correct; D. Resistance is a scalar quantity, so D is wrong;

Question 8: 8. The displacement of an object as a function of time is $x = 4 t - 2 t ^ { 2 } ( \mathrm {~m} )$ a...

8. The displacement of an object as a function of time is $x = 4 t - 2 t ^ { 2 } ( \mathrm {~m} )$ and the initial velocity and acceleration of its motion are respectively ( ) $- 4 \mathrm {~m} / \mathrm { s } ^ { 2 }$

  • A. A. $4 \mathrm {~m} / \mathrm { s }$,
  • B. B. $4 \mathrm {~m} / \mathrm { s } , 2 \mathrm {~m} / \mathrm { s } ^ { 2 }$
  • C. C. $4 \mathrm {~m} / \mathrm { s } , - 2 \mathrm {~m} / \mathrm { s } ^ { 2 }$
  • D. D. $0 , 4 \mathrm {~m} / \mathrm { s } ^ { 2 }$

Answer: A

Solution: According to the displacement time formula for uniformly variable linear motion, we have $$ s = v _ { 0 } t + \frac { 1 } { 2 } a t ^ { 2 } = 4 t - 2 t ^ { 2 } $$ Solve for $$ \begin{gathered} v _ { 0 } = 4 \mathrm {~m} / \mathrm { s } \\ a = - 4 \mathrm {~m} / \mathrm { s } ^ { 2 } \end{gathered} $$

Question 9: 9. The following physical quantities are vector quantities

9. The following physical quantities are vector quantities

  • A. A. lengths
  • B. B. mass (in physics)
  • C. C. average speed
  • D. D. resilience

Answer: D

Solution: ABC. Length, mass, average rate are only size and no direction, is a scalar quantity, so ABC is wrong; D. Elastic force has both size and direction, belongs to the vector, so D is correct;

Question 10: 10. The following statements are correct

10. The following statements are correct

  • A. A. When studying a player's technical movements during a basketball game, you can think of them as prime points
  • B. B. In the 1000 meter race held on a standard track and field, Yang's time was recorded as 4 minutes and 10 seconds, with 1000 m referring to the displacement of
  • C. C. The rate of change of an athlete's speed during a 100-meter sprint is large
  • D. D. The first session is from 8:00-8:40 a.m. and lasts 40 minutes, where $8 : 40$ refers to the moment

Answer: D

Solution: A. When studying an athlete's technical movements, it is necessary to focus on the athlete's posture, which is related to his or her shape and therefore cannot be considered as a prime point.A. Wrong; B. In the 1000-meter race held in a standard track and field, Yang ran two and a half laps of a 400-meter loop, so 1000 m refers to the distance traveled, and displacement refers to the directed line segment at the beginning and end positions. b. Error; C. The speed of the athlete in the 100-meter sprint is very large, which does not mean that the speed change is fast. Usually, when the athlete sprints at the end of the race, he passes through the race at a uniform speed and the acceleration is zero. C is wrong; D. 8:40 refers to the moment when the first class is dismissed. d is correct.

Question 11: 11. On July 29, 2021 Beijing time, China's Zhang Yufei won the women's 200-meter butterfly race at t...

11. On July 29, 2021 Beijing time, China's Zhang Yufei won the women's 200-meter butterfly race at the Tokyo Olympics with a time of 2 minutes 03 seconds (the international standard swimming pool is 50 meters long). The following statement is correct. ![](/images/questions/phys-kinematics/image-002.jpg)

  • A. A. "2 minutes 03 seconds" refers to the time interval.
  • B. B. Kary Zhang's average speed in the 200 meter freestyle is $1.62 \mathrm {~m} / \mathrm { s }$.
  • C. C. When studying Zhang Yufei's technical movements, you can think of Zhang Yufei as a prime point
  • D. D. During swimming, using the water in the pool as a reference system, Fay Zhang is stationary

Answer: A

Solution: A. "2 minutes 03 seconds" is the whole time, refers to the time interval, A is correct; B.The international standard swimming pool is 50 meters long, and when the swimmer returns to the origin after 200 meters, the displacement is 0, according to the definition of average speed. $$ v = \frac { \Delta x } { \Delta t } = 0 $$ The average speed of Zhang Yufei's 200-meter freestyle swim is 0, B error; C.When studying Zhang Yufei's technical maneuvers, Zhang Yufei cannot be regarded as a prime point, C is wrong; D.During the swimming process, using the water in the pool as the reference system, Zhang Yufei is in motion, D error.

Question 12: 12. The following statements about vectors and scalars are correct

12. The following statements about vectors and scalars are correct

  • A. A. Vectors are physical quantities that have magnitude and direction
  • B. B. Scalars are physical quantities that have magnitude and direction
  • C. C. Velocity, time, and acceleration are all vectors
  • D. D. Mass, displacement, and rate are all scalars

Answer: A

Solution: A. Vectors are physical quantities that have both magnitude and direction and follow the parallelogram rule when added together, option A is correct; B. Scalars are physical quantities that have magnitude and no direction, and when added together they are algebraic sums, option B is incorrect; C. Velocity and acceleration are physical quantities that have both magnitude and direction and are vectors, while time is a scalar quantity, option C is wrong; D. Mass and rate are physical quantities that have both magnitude and direction and are scalars, but displacement is a vector quantity that has both magnitude and direction, option D is wrong.

Question 13: 13. In the future, "capsule high-speed rail" is expected to become a new mode of transportation. The...

13. In the future, "capsule high-speed rail" is expected to become a new mode of transportation. The "capsule high-speed rail" utilizes the magnetic levitation technology to "float" the train in the vacuum pipe, and because there is no friction, its running speed can reach $5000 \mathrm {~km} / \mathrm { h }$ at the highest. Engineers tested the "Capsule High Speed Rail" in a straight line from $A$ city to $B$ city, traveling 121.7 kilometers in 6 minutes and 13 seconds. Then ( ![](/images/questions/phys-kinematics/image-003.jpg)

  • A. A. $5000 \mathrm {~km} / \mathrm { h }$ is the average speed
  • B. B. 6 minutes, 13 seconds is the moment.
  • C. C. "Capsule high-speed rail" train subjected to gravity in a vacuum tube
  • D. D. When calculating the average speed of the "Capsule High Speed Rail" train from the city of $A$ to the city of $B$, it should not be viewed as a mass.

Answer: C

Solution: $A$, the maximum running speed can reach $5000 \mathrm {~km} / \mathrm { h }$, which is the speed at a certain moment, and it is an instantaneous speed, so $A$ is wrong; B. 6 minutes and 13 seconds corresponds to a process, which is a time interval, so $B$ is wrong; C. The "capsule high-speed rail" train is still subject to gravity in the vacuum pipe, so $C$ is correct; $D$, study "capsule high-speed rail" train from $A$ city to $B$ city of the average speed of the train, the size of the train can be negligible, it can be regarded as a mass, so [$B$ is correct. INLINE_FORMULA_8]] is wrong;

Question 14: 14. $A$ and $B$ are two waymarks away from each other $s , 一$ A train starts from $A$ to $B$ in a st...

14. $A$ and $B$ are two waymarks away from each other $s , 一$ A train starts from $A$ to $B$ in a straight line motion at $B$ with acceleration $A$. The train starts from $B$ to $B$ in a straight line and travels from $A$ to $B$ with an acceleration rate of $t$, the train will be $\frac { t } { 2 }$ away from the $B$ train at $B$. $B$, then the distance from the point $B$ is ( ).

  • A. A. $\frac { 3 s } { 4 }$
  • B. B. $\frac { s } { 4 }$
  • C. C. $\frac { s } { 2 }$
  • D. D. $\frac { \sqrt { 2 } s } { 2 }$

Answer: A

Solution: Uniformly variable linear motion with zero initial velocity, the ratio of displacements in consecutive equal adjacent times is $1 : 3$, and let the first $\frac { t } { 2 }$ time be displacement is $x$, then after $\frac { t } { 2 }$ displacement is $3 x$, then there are $$ x + 3 x = s $$ The solution is $$ x = \frac { s } { 4 } $$ The distance from point $B$ is $\frac { 3 } { 4 } s$, so A is correct.

Question 15: 15. A linear coordinate system is established using Chang'an Street in Beijing as the $x$ axis, with...

15. A linear coordinate system is established using Chang'an Street in Beijing as the $x$ axis, with a positive direction to the east and the center of Chang'an Street opposite the center of Tian'anmen Square as the coordinate origin $O$. A car is initially 3 km west of the origin and a few minutes later travels 2 km east of the origin. The coordinates of the initial and final positions of the automobile are ( )

  • A. A. 3km 2km
  • B. B. - $3 \mathrm {~km} \quad 2 \mathrm {~km}$
  • C. C. $3 \mathrm {~km} \quad - 2 \mathrm {~km}$
  • D. D. $- 3 \mathrm {~km} \quad - 2 \mathrm {~km}$

Answer: B

Solution: The positive direction of the coordinate axis is to the east, then the position east of the coordinate origin is positive, west of the coordinate origin is negative, the car is initially west of the origin and 3 km away from the origin, so the initial position is - 3 km, and similarly the final position is 2 km.

Question 16: 16. Regarding Galileo's study of free fall, the following statements are correct ( )

16. Regarding Galileo's study of free fall, the following statements are correct ( )

  • A. A. The initial velocity of a free-falling body is zero
  • B. B. Believes that heavy objects fall faster and light objects fall slower
  • C. C. Suggests that "free fall" is the simplest form of uniform linear motion.
  • D. D. Use of inclined surfaces to "dilute" the effect of gravity and facilitate the measurement of displacements

Answer: A

Solution: ABC. Galileo believed that heavy objects and light objects fall the same speed, and proposed "free fall" is one of the simplest initial speed of zero uniformly variable linear motion, so A is correct, BC is wrong; D. The use of inclined plane "dilute" the effect of gravity, is to facilitate the measurement of time, so D error.

Question 17: 17. When a car brakes on a horizontal surface, its displacement versus time is $x = 24 t - 6 t ^ { 2...

17. When a car brakes on a horizontal surface, its displacement versus time is $x = 24 t - 6 t ^ { 2 }$, and its acceleration is of the magnitude ()

  • A. A. $- 10 \mathrm {~m} / \mathrm { s } ^ { 2 }$
  • B. B. $- 12 \mathrm {~m} / \mathrm { s } ^ { 2 }$
  • C. C. $- 14 \mathrm {~m} / \mathrm { s } ^ { 2 }$
  • D. D. $12 \mathrm {~m} / \mathrm { s } ^ { 2 }$

Answer: D

Solution: From the displacement-time relationship of uniformly variable linear motion $$ x = v _ { 0 } t + \frac { 1 } { 2 } a t ^ { 2 } = 24 t - 6 t ^ { 2 } $$ it is known that $$ v _ { 0 } = 24 \mathrm {~m} / \mathrm { s } , a = - 12 \mathrm {~m} / \mathrm { s } ^ { 2 } $$ So the acceleration of the car is $12 \mathrm {~m} / \mathrm { s } ^ { 2 }$, so D is correct.

Question 18: 18. The following physical quantities are vector quantities

18. The following physical quantities are vector quantities

  • A. A. timing
  • B. B. power (output)
  • C. C. electric field strength
  • D. D. electrical charge

Answer: C

Solution: A. Time is only length (size), no direction, and is a scalar quantity, A error; B. Power is a scalar quantity with only magnitude and no direction; C. The electric field strength has both magnitude and direction, and is a vector quantity, C is correct; D. Charge has only magnitude and no direction, and is a scalar quantity, D is wrong.

Question 19: 19. There is an observatory at $O$ in the lake, and a boat has been traveling from $O$ to the east a...

19. There is an observatory at $O$ in the lake, and a boat has been traveling from $O$ to the east at $36 \mathrm {~km} / \mathrm { h }$ for 20 minutes. It then travels north for 9 km at the same speed in a straight line.

  • A. A. The displacement of the boat relative to the observer at $O$ is 21 km.
  • B. B. Observers at $O$ are always stationary with respect to the boat
  • C. C. The boat cannot be stationary relative to another observer on the lakeshore
  • D. D. The average speed of the boat during this process is approximately $25.7 \mathrm {~km} / \mathrm { h }$

Answer: D

Solution: AB . The boat moves 12 km to the east and 9 km to the north with respect to the point $O$, and the total displacement is 15 km by the rule of parallelogram, so A and B are wrong; C. Relative to the other observer on the lake shore, if he is in the same state of motion as the boat, then it is possible to be relatively stationary, so C is wrong; D. The boat traveling time is $\frac { 7 } { 12 } \mathrm {~h}$, the average speed is $$ \bar { v } = \frac { x } { t } = \frac { 15 } { 7 } \mathrm {~km} / \mathrm { h } \approx 25.7 \mathrm {~km} / \mathrm { h } $$ Therefore, D is correct.

Question 20: 20. The following statements about the acceleration of an object in motion are correct (

20. The following statements about the acceleration of an object in motion are correct (

  • A. A. The greater the speed, the greater the acceleration
  • B. B. The greater the change in velocity, the greater the acceleration
  • C. C. The greater the terminal velocity, the greater the acceleration
  • D. D. The faster the speed change, the greater the acceleration

Answer: D

Solution: Acceleration is defined as the amount of change in velocity per unit time, $\mathrm { a } = \frac { \Delta v } { \Delta \mathrm { t } }$. physical quantity that reflects how fast the velocity is changing. According to $\mathrm { a } = \frac { \Delta v } { \Delta \mathrm { t } }$, if the speed is large, the change of speed is not necessarily large, and the acceleration is not necessarily large. Therefore, A is wrong. B. According to $\mathrm { a } = \frac { \Delta v } { \Delta \mathrm { t } }$, a large change in velocity does not necessarily mean a large acceleration. Therefore, B is wrong. C. If the terminal velocity is large, the change in velocity is not necessarily large and the acceleration is not necessarily large. Therefore, C is wrong. D. Acceleration is a physical quantity reflecting the speed of change of speed, the speed change is fast, the acceleration is big. Therefore, D is correct. Comment: The key to solving this problem is to understand the definition of acceleration: acceleration is equal to the amount of change in velocity per unit of time, $\mathrm { a } = \frac { \Delta v } { \Delta \mathrm { t } }$ . As well as the physical meaning of acceleration: reflecting the speed of change.

Question 21: 21. The time that elapses from the moment a person realizes a situation to the moment he or she acts...

21. The time that elapses from the moment a person realizes a situation to the moment he or she acts accordingly is called reaction time. We can use the following experiment to measure our reaction time. Please a student with two fingers pinch the top of the wooden ruler, you use a hand in the lower part of the wooden ruler to do the preparation of holding the wooden ruler, but any part of the hand in the beginning do not touch the wooden ruler. When you see the student let go of the hand, you immediately hold the wooden ruler, according to the height of the wooden ruler fell, you can calculate your reaction time. If the ruler falls about 11 cm in a measurement, you can tell that your reaction time this time is about ![](/images/questions/phys-kinematics/image-004.jpg)

  • A. A. 0.2 s
  • B. B. 0.15 s
  • C. C. 0.1 s
  • D. D. 0.05 s

Answer: B

Solution: From the question, the height at which the wooden ruler fell in the reflected time $\mathrm { H } = 11 \mathrm {~cm}$ From the laws of free-fall motion: $H = \frac { 1 } { 2 } g t ^ { 2 } , t = \sqrt { \frac { 2 H } { g } }$ Substitute the data to get $t \approx 0.15 \mathrm {~s}$

Question 22: 22 . On a rainy day, Mr. Li stood by the window and saw a steady stream of rainwater dripping from t...

22 . On a rainy day, Mr. Li stood by the window and saw a steady stream of rainwater dripping from the eaves of the house. As shown in the figure, he found that when the 1st drop fell to the ground, the 4th drop just formed, and visually measured the $3 , 4$ height difference between the two drops is about 40 cm, assuming that the time interval between the formation of the two neighboring droplets is the same, then the height of the eave off the ground is about ![](/images/questions/phys-kinematics/image-005.jpg)

  • A. A. 5.5 m
  • B. B. 4.5 m
  • C. C. 3.5 m
  • D. D. 2.5 m

Answer: C

Solution: According to the proportionality relationship, the ratio of the distance between neighboring drops from the top to the bottom is $1 : 3 : 5 : 7 : 9$, and the distance between 3 and 4 drops is $40 \mathrm {~cm} = 0.4 \mathrm {~m}$, so the total height is $\mathrm { H } = ( 1 + 3 + 5 ) \times 0.4 = 3.6 \mathrm {~m}$.The C option is the closest. Therefore, C is correct and ABD is wrong. Points : The key to solving this problem is to master the initial velocity of 0 uniformly accelerated linear motion, the displacement ratio is $1 : 3 : 5 : 7$ in consecutive equal time intervals. As well as mastering the free-fall motion displacement time formula $\mathrm { H } = \frac { 1 } { 2 } \mathrm { gt } ^ { 2 }$.

Question 23: 23. The following physical quantities are vectors

23. The following physical quantities are vectors

  • A. A. tempo
  • B. B. timing
  • C. C. kinetic
  • D. D. mass (in physics)

Answer: A

Solution: Vectors are physical quantities that have both magnitude and direction, such as velocity, force, acceleration, displacement, etc., while scalars have only magnitude and no direction, such as rate, time, mass, kinetic energy, etc., so A is correct.

Question 24: 24.Electric bicycles are popular among middle school students for their fashion, convenience and spe...

24.Electric bicycles are popular among middle school students for their fashion, convenience and speed. But the traffic accidents caused by electric bicycles are also increasing year by year. Learning traffic safety knowledge, consciously abide by traffic regulations is to ensure that students traffic safety is one of the important measures. According to the regulations of the speed limit of electric bicycles in the city $20 \mathrm {~km} / \mathrm { h }$ . The following statement is correct ![](/images/questions/phys-kinematics/image-006.jpg)

  • A. A. E-bike speed limit $20 \mathrm {~km} / \mathrm { h }$, referring to the average speed
  • B. B. E-bike speed limit $20 \mathrm {~km} / \mathrm { h }$, referring to the instantaneous speed
  • C. C. The speed of mutual collision at the time of the traffic accident refers to the average speed
  • D. D. The speed at which a section of road is traveled refers to the instantaneous speed

Answer: B

Solution: A, B: The speed limit $20 \mathrm {~km} / \mathrm { h }$ for e-bikes means that the maximum speed of e-bikes is the instantaneous speed, so A is wrong and B is correct; C: When a traffic accident occurs, the speed of mutual collision refers to the instantaneous speed at the moment of collision, so C is wrong; D: the speed of traveling in a section refers to the average speed, so D is wrong.

Question 25: 25. As shown in the figure is a trackless train in the mall, the train is known to be composed of a ...

25. As shown in the figure is a trackless train in the mall, the train is known to be composed of a number of sections of the same carriages, the gap between the carriages is not counted, there is a child standing on the ground to remain stationary and the first section of the head of the carriages are aligned with the train started from rest to do a uniformly accelerated straight-line motion, the following statement is correct ![](/images/questions/phys-kinematics/image-007.jpg)

  • A. A. The ratio of the time that cars 4, 5 and 6 pass the children is $2 : \sqrt { 5 } : \sqrt { 6 }$
  • B. B. The ratio of time passed by children in cars 4, 5 and 6 is 7:9:11.
  • C. C. The ratio of the velocities at the end of the 4th, 5th, and 6th cars through the children's instant is $4 : 5 : 6$
  • D. D. The ratio of the velocities at the end of the 4th, 5th, and 6th cars through the children's instant is $2 : \sqrt { 5 } : \sqrt { 6 }$

Answer: D

Solution: AB. According to the time relationship for equal displacements of uniformly accelerated motion with zero initial velocity, the $1 , 2 , 3 , 4$ 5, 6 ..... The ratio of the time that the $1 : ( \sqrt { 2 } - 1 ) : ( \sqrt { 3 } - \sqrt { 2 } ) : ( 2 - \sqrt { 3 } ) : ( \sqrt { 5 } - 2 ) : ( \sqrt { 6 } - \sqrt { 5 } ) \cdots \cdots$ car passes the children is $1 : ( \sqrt { 2 } - 1 ) : ( \sqrt { 3 } - \sqrt { 2 } ) : ( 2 - \sqrt { 3 } ) : ( \sqrt { 5 } - 2 ) : ( \sqrt { 6 } - \sqrt { 5 } ) \cdots \cdots$, i.e., the ratio of the time that the $4 , 5 , 6$ car passes the children is $( 2 - \sqrt { 3 } ) : ( \sqrt { 5 } - 2 ) : ( \sqrt { 6 } - \sqrt { 5 } )$, which is incorrect in option AB; CD. $$ v ^ { 2 } = 2 a L $$ The ratio of the velocities at the end of the 4th, 5th, and 6th cars through the children's instant is obtained as $$ \sqrt { 2 a \cdot 4 L } : \sqrt { 2 a \cdot 5 L } : \sqrt { 2 a \cdot 6 L } = 2 : \sqrt { 5 } : \sqrt { 6 } $$ Option C is incorrect and D is correct.

Question 26: 26. The following statements are correct ( )

26. The following statements are correct ( )

  • A. A. In the study of the Earth's revolution around the Sun, the Earth cannot be considered as a prime point
  • B. B. The average rate of an object is equal to the ratio of displacement to time
  • C. C. In unidirectional linear motion, the distance traveled by an object is greater than the displacement
  • D. D. The direction of an object's average velocity must be the same as the direction of its displacement.

Answer: D

Solution: A. In the study of the Earth's revolution around the Sun, it is not necessary to study the attitude of the Earth, so the Earth can be regarded as a mass, so A error; B. The average rate of a body is equal to the ratio of distance traveled to time, so B is wrong; C. In one-way linear motion, the distance traveled by the object is equal to the size of the displacement, so C error; D. According to $$ \bar { v } = \frac { x } { t } $$ D. According to $$ \bar { v } = \frac { x } { t } $$, the direction of the average speed of the body must be the same as the direction of its displacement, so D is correct.

Question 27: 27. Alpine skiing, which originated in the Alpine region, is also known as "Alpine skiing" or "mount...

27. Alpine skiing, which originated in the Alpine region, is also known as "Alpine skiing" or "mountain skiing". A skier sliding down the slope to reach the level of the piste began to do the initial speed of $10 \mathrm {~m} / \mathrm { s }$, acceleration of $4 \mathrm {~m} / \mathrm { s } ^ { 2 }$ uniformly decelerated straight-line motion, then the athlete in the level of the piste at the beginning of the $3 s$ within the movement of the displacement is () ![](/images/questions/phys-kinematics/image-008.jpg)

  • A. A. 15 m
  • B. B. 12.5 m
  • C. C. 12 m
  • D. D. 10 m

Answer: B

Solution: The time at which a person stops in uniformly decelerating motion is $$ t _ { 0 } = \frac { v _ { 0 } } { a } = \frac { 10 } { 4 } \mathrm {~s} = 2.5 \mathrm {~s} $$ Then the displacement of the motion in the first 3 s is equal to the displacement in 2.5 s $$ x _ { 3 } = x _ { 2.5 } = \frac { v _ { 0 } } { 2 } t _ { 0 } = \frac { 10 } { 2 } \times 2.5 \mathrm {~m} = 12.5 \mathrm {~m} $$

Question 28: 28. The following statements are correct ( )

28. The following statements are correct ( )

  • A. A. A person walking on a boat drifting downstream may be stationary if the riverbank is used as a reference system
  • B. B. An object moving in a straight line must have a displacement equal to the distance it traveled in that time.
  • C. C. When studying the arc-spin balls sent by a table tennis player in a match, the table tennis ball can be considered as a prime point
  • D. D. A lesson lasts 40 minutes. 40 minutes means the end of the lesson.

Answer: A

Solution: A. If the riverbank is the reference system, if the person in the boat with the boat size equal to the speed, reverse motion, then the person is stationary relative to the riverbank, so A is correct; B. Do one-way linear motion of the object, the size of its displacement with the time it passes through the distance equal, option B is wrong; C. The size of the table tennis ball can not be ignored when studying the arc-spinning ball issued by the table tennis player in the game, the table tennis ball can not be regarded as a prime point, option C is wrong; D. A lesson lasts 40 minutes. 40 minutes means the time of each lesson.

Question 29: 29. The following statements are correct ( )

29. The following statements are correct ( )

  • A. A. Any object with a small volume can be considered as a prime point
  • B. B. Any regularly shaped object must have its center of gravity at the geometric center
  • C. C. A student waited for a quarter of an hour in front of the school after school before the bus came, this "quarter of an hour" refers to the moment
  • D. D. Only in unidirectional linear motion is the magnitude of displacement equal to the distance traveled

Answer: D

Solution: A. As long as the shape and size of the object has no effect on the study of the problem or the effect is negligible when the object can be treated as a point of mass, so large objects can also be treated as a point of mass, for example, when the Earth revolves around the sun, the Earth can be regarded as a point of mass, so A error; B. The center of gravity of an object with a regular shape and a uniform mass distribution is at the geometric center of the object. So just have a regular shape of the object center of gravity is not necessarily in the geometric center, so B error; C.A student waited for a quarter of an hour at the school gate after school before the bus came, the "quarter of an hour" refers to the length of time, is the time, so C error; D. In the unidirectional linear motion, the direction of the object's movement has not changed, the size of the displacement is equal to the distance, so D is correct.

Question 30: A mass moves 2.25 revolutions along a circle of radius $R$. The following statements about the displ...

A mass moves 2.25 revolutions along a circle of radius $R$. The following statements about the displacement and distance traveled by the mass are correct.

  • A. A. Both the distance and displacement size are $4.5 \pi R$
  • B. B. The magnitude of the distance and displacement are $\sqrt { 2 } R$
  • C. C. The distance traveled is ${ } ^ { 4.5 \pi R }$ and the size of the displacement is $\sqrt { 2 } R$.
  • D. D. The distance traveled is $0.5 \pi R$ and the size of the displacement is $\sqrt { 2 } R$.

Answer: C

Solution: The distance is the length of the path, and the displacement is the length of the directed line segment from the starting point to the end point; the mass point moves 2.25 times along the circle with radius $R$, then the distance is $$ s = 2.25 \times 2 \pi R = 4.5 \pi R $$ Displacement $$ x = \sqrt { 2 } R $$

Question 31: 31. A team of researchers has invented a self-driving logistics vehicle with a path designed as a ci...

31. A team of researchers has invented a self-driving logistics vehicle with a path designed as a circle with a radius of 100 m. The vehicle starts from a certain point and returns to the starting point for the first time after 10 min. The vehicle starts from a certain point and returns to the starting point for the first time in 10 minutes. The correct description of the displacement and distance traveled by the vehicle in the process is

  • A. A. Displacement is always greater than distance traveled
  • B. B. The magnitude of the displacement and the distance traveled are always equal
  • C. C. The magnitude of the displacement is always less than the distance traveled
  • D. D. The magnitude of the displacement increases with the motion of the car

Answer: C

Solution: ABC . Since the self-driving logistics vehicle moves in a curve, the size of the displacement is always smaller than the distance traveled, so AB is wrong and C is correct; D. The size of the displacement is equal to the length of the line segment from the initial position to the final position, and the self-driving logistics vehicle eventually returns to the starting point, so the size of the displacement of the self-driving logistics vehicle increases and then decreases with the motion of the vehicle, so D is wrong.

Question 32: 32. In severe winters, there is ice under the eaves of a house, which can be seen as a mass (as show...

32. In severe winters, there is ice under the eaves of a house, which can be seen as a mass (as shown in the figure). People walking under the eaves of the house to prevent the ice cream hit his head, so there must be a sense of safety precautions. Assuming that the ice cream to do free-fall motion, ice cream last 1 s falling height of 25 m, the size of the acceleration of gravity $g = 10 \mathrm {~m} / \mathrm { s } ^ { 2 }$, then the ice cream free fall of the total time is ![](/images/questions/phys-kinematics/image-009.jpg)

  • A. A. 3s
  • B. B. 3.2 s
  • C. C. 3.6 s
  • D. D. 3.8 s

Answer: A

Solution: The height of the ice cream falling in the last 1 s is 25 m, then the velocity in the middle of the last 1 s is $$ v = \frac { 25 } { 1 } \mathrm {~m} / \mathrm { s } = 25 \mathrm {~m} / \mathrm { s } $$ According to the law of free-fall motion $$ v = g ( t - 0.5 ) $$ Then the total time of free fall of ice cream $$ t = \frac { 25 } { 10 } \mathrm {~s} + 0.5 \mathrm {~s} = 3 \mathrm {~s} $$

Question 33: 33. Cars should be kept at a safe distance from the car in front of them, usually, the safe distance...

33. Cars should be kept at a safe distance from the car in front of them, usually, the safe distance is related to the reaction time of the driver and the speed of the car. A student measures his reaction time when driving a car on a closed, straight road: the car travels at a speed of $v _ { 1 }$ at a constant speed, and records the displacement from the time when he sees the deceleration signal to the time when the car stops $x _ { 1 }$; then he travels at a speed of $v _ { 2 }$ at a constant speed at a different speed, and records the displacement from the time when he sees the deceleration signal to the time when the car stops $v _ { 2 }$. The displacement $x _ { 2 }$ from the time the deceleration signal is seen to the time the car comes to a stop is recorded, assuming that the reaction time is the same for both experiments and that the acceleration is the same and constant. The reaction time of the student can be measured as

  • A. A. $\frac { v _ { 2 } ^ { 2 } x _ { 1 } - v _ { 1 } ^ { 2 } x _ { 2 } } { v _ { 1 } v _ { 2 } ^ { 2 } - v _ { 2 } v _ { 2 } ^ { 2 } }$
  • B. B. $\frac { 2 \left( v _ { 1 } x _ { 2 } - v _ { 2 } x _ { 1 } \right) } { v _ { 1 } v _ { 2 } }$
  • C. C. $\frac { 2 \left( v _ { 2 } x _ { 2 } - v _ { 1 } x _ { 1 } \right) } { v _ { 1 } v _ { 2 } }$
  • D. D. $\frac { v _ { 2 } ^ { 2 } x _ { 1 } - v _ { 1 } ^ { 2 } x _ { 2 } } { v _ { 2 } v _ { 1 } ^ { 2 } - v _ { 1 } v _ { 1 } ^ { 2 } }$

Answer: A

Solution: Let the reaction time of the driver be $t$, and the magnitude of the acceleration of the uniformly decelerating motion be $a$, and from the kinematics equation we have $$ \begin{aligned} & x _ { 1 } = v _ { 1 } t + \frac { v _ { 1 } ^ { 2 } } { 2 a } \\ & x _ { 2 } = v _ { 2 } t + \frac { v _ { 2 } ^ { 2 } } { 2 a } \end{aligned} $$ The joint solution is $$ t = \frac { v _ { 2 } ^ { 2 } x _ { 1 } - v _ { 1 } ^ { 2 } x _ { 2 } } { v _ { 1 } v _ { 2 } ^ { 2 } - v _ { 2 } v _ { 2 } ^ { 2 } } $$

Question 34: 34. Experienced drivers see the red light from afar and do not emergency braking but adjust the gas ...

34. Experienced drivers see the red light from afar and do not emergency braking but adjust the gas pedal slowly decelerate, so that the car rushed to the intersection just when the green light is on, when the green light is on, the driver controls the gas pedal so that the car to do uniformly accelerated straight-line motion to start accelerating as a starting point for timekeeping, $0 \sim 5 \mathrm {~s}$ within the $x - t$ car's $x - t$ image is shown in the figure. The $0 \sim 5 \mathrm {~s}$ image of the car is shown in the figure, and after 6 s the car keeps the speed at the end of 6 s in uniform linear motion. The following statement is correct ( ) ![](/images/questions/phys-kinematics/image-010.jpg)

  • A. A. The car passes through a displacement of 30 m in $0 \sim 4 \mathrm {~s}$.
  • B. B. The magnitude of the acceleration of a car moving in a uniformly accelerated straight line is $4 \mathrm {~m} / \mathrm { s } ^ { 2 }$
  • C. C. The magnitude of the speed of the car in uniform linear motion is $16 \mathrm {~m} / \mathrm { s }$
  • D. D. The average speed of the car in $0 \sim 6 \mathrm {~s}$ has a magnitude of $16 \mathrm {~m} / \mathrm { s }$

Answer: C

Solution: AB. Let $t = 0$ time the speed of the car is $v _ { 0 }$, the acceleration of the car to do uniform acceleration straight line motion is $a$; According to the image can be seen that the car displacement in 5 s is 45 m, according to the relationship between displacement and time $$ x = v _ { 0 } t + \frac { 1 } { 2 } a t ^ { 2 } $$ can be obtained $$ 45 = 5 v _ { 0 } + \frac { 1 } { 2 } a \times 5 ^ { 2 } $$ Similarly, the displacement in 2s is 12 m, i.e. $$ 12 = 2 v _ { 0 } + \frac { 1 } { 2 } a \times 2 ^ { 2 } $$ The joint solution is $$ v _ { 0 } = 4 \mathrm {~m} / \mathrm { s } , a = 2 \mathrm {~m} / \mathrm { s } ^ { 2 } $$ So the displacement of the object in 4 s is $$ x = 4 \times 4 + \frac { 1 } { 2 } \times 2 \times 4 ^ { 2 } \mathrm {~m} = 32 \mathrm {~m} $$ Therefore, AB is wrong; C.After 6 s, the car is in uniform linear motion with a velocity of $$ v = v _ { 0 } + a t = 4 + 2 \times 6 \mathrm {~m} / \mathrm { s } = 16 \mathrm {~m} / \mathrm { s } $$ Therefore, C is correct; D.The size of the average speed is $$ \bar { v } = \frac { v _ { 0 } + v } { 2 } = 10 \mathrm {~m} / \mathrm { s } $$ Therefore, D is incorrect.

Question 35: 35. The following statements describing motion are correct

35. The following statements describing motion are correct

  • A. A. If the velocity of an object changes, its acceleration must not be zero.
  • B. B. "Faster and faster" means that the acceleration of the object is increasing.
  • C. C. If the direction of an object's velocity changes, then the direction of its acceleration changes as well
  • D. D. The acceleration of the object increases and so does the change in velocity

Answer: A

Solution: A. By the defining formula of acceleration $a = \frac { \Delta v } { \Delta t }$, it is known that the speed changes, that is, $\Delta v \neq 0$, then $a \neq 0$, so A is correct; B. "Going faster and faster" means that the object's rate of motion is increasing, so B is wrong; C. The direction of the object speed changes, the direction of acceleration does not necessarily change, such as the object from the opposite direction of deceleration to the positive direction of the acceleration process, the direction of speed changes, the direction of acceleration did not change, so C error; D. From the definition of acceleration $a = \frac { \Delta v } { \Delta t }$, it can be seen that the acceleration of an object increases, which can only mean that $\frac { \Delta v } { \Delta t }$ increases. D. If ${ } _ { \Delta t }$ does not change, then the change in velocity will also increase, so D is wrong.

Question 36: 36. As shown in the figure is a giant recreational equipment, can take more than twenty people in th...

36. As shown in the figure is a giant recreational equipment, can take more than twenty people in the ring-shaped cockpit set in the firm straight column, by the elevator to send up dozens of meters high, and then let the cockpit free fall. When it reaches a certain position, the braking system is activated and it just stops when it reaches the ground. Knowing that the height of the cockpit at the start of its fall is 75 m and that the fall time is $5 \mathrm {~s} , g$ take $10 \mathrm {~m} / \mathrm { s } ^ { 2 }$, the following statements are correct. ![](/images/questions/phys-kinematics/image-011.jpg)

  • A. A. The free fall time of the cockpit is 2 s
  • B. B. The braking distance (deceleration phase distance) should be more than half of the total drop distance
  • C. C. The acceleration of the cockpit after the braking system is activated is $15 \mathrm {~m} / \mathrm { s } ^ { 2 }$
  • D. D. The displacement in the last second of the free-fall phase is 7.5 m.

Answer: C

Solution: A. Let the speed during braking be $v$, then the $v - t$ image is shown in Figure ![](/images/questions/phys-kinematics/image-012.jpg) From the ${ } ^ { v - t }$ image we know that $$ h = \frac { v } { 2 } t $$ Solve for $$ v = 30 \mathrm {~m} / \mathrm { s } $$ Then the free fall time $$ t = \frac { v } { g } = 3 \mathrm {~s} $$ Therefore, A is wrong; B. The distance of free fall $$ h _ { 1 } = \frac { v ^ { 2 } } { 2 g } = 45 \mathrm {~m} $$ Then the braking distance $$ h _ { 2 } = h - h _ { 1 } = 30 \mathrm {~m} $$ can be obtained $$ h _ { 2 } < \frac { h } { 2 } $$ ## Therefore, B is wrong; C. Let the magnitude of the acceleration of the motion after braking be $a$ , then $$ a = \frac { v ^ { 2 } } { 2 h _ { 2 } } $$ ## can be obtained $$ a = 15 \mathrm {~m} / \mathrm { s } ^ { 2 } $$ ## Therefore, C is correct; D. Displacement in the last second of the free-fall phase $$ x = \frac { 1 } { 2 } g t ^ { 2 } - \frac { 1 } { 2 } g ( t - 2 ) ^ { 2 } $$ Solution. $$ x = 25 \mathrm {~m} $$ Therefore, D is wrong.

Question 37: A small stone falls freely from point $a$ in the air and passes through points $b$ and $c$, regardle...

A small stone falls freely from point $a$ in the air and passes through points $b$ and $c$, regardless of air resistance. It is known that its velocity is $v$ when it passes through point $c$ and $1.5 v$ when it passes through point $c$. Then the ratio of the displacement of the $a b$ segment to the $b c$ segment is ( )

  • A. A. $2 : 3$
  • B. B. $4 : 5$
  • C. C. $3 : 2$
  • D. D. $4 : 9$

Answer: B

Solution: The ratio of the $a b$ segment to the $b c$ segment displacement is $$ x _ { 1 } : x _ { 2 } = \frac { v ^ { 2 } - 0 } { 2 g } : \frac { ( 1.5 v ) ^ { 2 } - v ^ { 2 } } { 2 g } = 4 : 5 $$

Question 38: 38. As shown in the figure, the object moves in the direction of the arrow of the $A B C D E$ trajec...

38. As shown in the figure, the object moves in the direction of the arrow of the $A B C D E$ trajectory, and the time taken to move along the $A B , A B C , A B C D , A B C D E$ four segments of the trajectory is $1 \mathrm {~s} , 2 \mathrm {~s} , 3 \mathrm {~s} , 4 \mathrm {~s}$ respectively. The following statement is correct ( ) ![](/images/questions/phys-kinematics/image-013.jpg)

  • A. A. The average velocity of the object in the $A B C$ segment is $\frac { 1 + \sqrt { 2 } } { 2 } \mathrm {~m} / \mathrm { s }$.
  • B. B. The magnitude of the object's average velocity over 4 s is $0.75 \mathrm {~m} / \mathrm { s }$
  • C. C. The average speed of the CD segment is equal to the average speed of the DE segment.
  • D. D. The instantaneous velocity of the object at $B$ is equal to the average velocity of the $A B C$ segment.

Answer: B

Solution: A. Displacement in the $A B C$ segment $$ S _ { A C } = \sqrt { 1 ^ { 2 } + 2 ^ { 2 } } \mathrm {~m} = \sqrt { 5 } \mathrm {~m} $$ Therefore, the average velocity of the object in the $A B C$ segment has a magnitude of $$ \bar { v } _ { A C } = \frac { S _ { A C } } { t _ { A C } } = \frac { \sqrt { 5 } } { 2 } \mathrm {~m} / \mathrm { s } $$ A is wrong; B. The displacement of the object in $4 s$ is $$ \bar { v } _ { A C } = \frac { S _ { A C } } { t _ { A C } } = \frac { \sqrt { 5 } } { 2 } \mathrm {~m} / \mathrm { s } $$. $$ S _ { A E } = 3 \mathrm {~m} $$ Therefore, the average speed of the object in 4 s is $$ \bar { v } _ { A E } = \frac { S _ { A E } } { t _ { A E } } = 0.75 \mathrm {~m} / \mathrm { s } $$ B Correct; C. Average velocity is a vector quantity that has both magnitude and direction. The average velocity of the $C D$ segment is in a different direction than the average velocity of the $D E$ segment, so the average velocities of the two segments are not the same; C is incorrect; D. Since the specific motion of the object is not known, it is impossible to determine whether the instantaneous velocity of the object at $B$ is equal to the average velocity of the $A B C$ segment, D is wrong.

Question 39: 39. The Romance of the Three Kingdoms" is popular, Zhuge Liang is brilliant, Zhang Fei is brave, in ...

39. The Romance of the Three Kingdoms" is popular, Zhuge Liang is brilliant, Zhang Fei is brave, in the entry of Sichuan, Zhuge Liang and Zhang Fei high-five for the oath agreed to the first to the sobriety water pass for the win. Zhuge Liang and Zhang Fei at the same time from $O$ point, as shown in the figure, route A is Zhang Fei's marching routes, route B is Zhuge Liang's marching routes, $A$ point is the Fushuiguan, on the way to Zhang Fei, "righteously release Yan Yan," all the way unimpeded! The first to the Fushui Pass. The following statement is correct ( ) ![](/images/questions/phys-kinematics/image-014.jpg) (1) the average speed of the two armies are equal (2) Zhang Fei's average speed is greater than Zhuge Liang's average speed (3) The distance traveled by the two armies is not equal (4) Zhang Fei's instantaneous rate is always greater than Zhuge Liang's instantaneous rate

  • A. A. (1) (4)
  • B. B. (2) (3)
  • C. C. (2) (4)
  • D. D. (1) (3)

Answer: B

Solution: (1) (2) The two armies have the same starting and ending points, then the displacements are equal and Zhang Fei arrives first, according to the $$ \bar { v } = \frac { x } { t } $$ Zhang Fei's average speed is greater than Zhuge Liang's average speed, (1) Wrong (2) Correct; (3) The distance is the length of the track, then the distance is not equal, (3) is correct; (4) the movement is not clear can not judge the relationship between the size of the instantaneous rate at each moment during the movement, (4) error;

Question 40: 40. An object in uniformly accelerated straight-line motion passes through two points $A , B$ at a d...

40. An object in uniformly accelerated straight-line motion passes through two points $A , B$ at a distance of $x$ with velocities of $v$ and $7 v$, and the time of motion from $A$ to $B$ is $t$, then the following statement is correct ( ). _4]] to $B$ in $t$, then the following statement is correct ( ) High School Physics Assignment, October 29, 2025

  • A. A. After $A B$ the speed at the middle moment is $4 v$
  • B. B. The velocity through the midpoint of the $A B$ displacement is $4 v$
  • C. C. Before $\frac { t } { 2 }$ time passes with fewer displacements than after $\frac { t } { 2 }$ time passes with fewer displacements $2 v t$
  • D. D. Before $\frac { t } { 2 }$ time passes with fewer displacements than after $\frac { t } { 2 }$ time passes with fewer displacements $2.5 \mathrm { v } t$

Answer: A

Solution:
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Kinematics

运动学

40 Practice Questions

Practice with Chinese questions to prepare for the CSCA exam. You can toggle translations while practicing.

Topic Overview

Kinematics is the branch of physics that describes the motion of objects without considering the forces causing the motion. It focuses on concepts like In the CSCA exam, questions often involve analyzing graphs (position-time, velocity-time), solving problems of constant acceleration, and understanding vector properties of motion quantities. In the CSCA exam, questions often involve analyzing graphs (position-time, velocity-time, solving problems of constant acceleration, and understanding vector properties of motion quantities. Mastery of kinematic equations is essential for success . .

Questions:40

Key Points

  • 1Defining and calculating displacement, velocity, and acceleration.
  • 2Applying the equations of motion for constant acceleration.
  • 3Interpreting and drawing position-time and velocity-time graphs.
  • 4Distinguishing between scalar and vector quantities in motion.

Study Tips

Practice sketching motion graphs for different scenarios; it visually reinforces the relationships between displacement, velocity, and acceleration.

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