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Next exam on November 14 – 15, 2026:
All concepts

Function Monotonicity

函数的单调性

The definition of monotonicity and reading monotonic intervals of standard functions such as power and quadratic functions.

4 real-exam questions · 4 sittings19 in mock papers13 practice

Formulas

  • Monotonicity Criteria

    Definition
    x1<x2⇒f(x1)<f(x2) (increasing),x1<x2⇒f(x1)>f(x2) (decreasing)x_{1}<x_{2}\Rightarrow f(x_{1})<f(x_{2})\ \text{(increasing)},\qquad x_{1}<x_{2}\Rightarrow f(x_{1})>f(x_{2})\ \text{(decreasing)}

    Applies when:x₁, x₂ taken from the same monotonic interval D

How the real exam tests it

Questions from real CSCA papers that test this concept. Work each one out before you open the answer.

  1. CSCA Math December 2025 Past Paper
    Which of the following functions is increasing?
    • A.y=log⁡0.5xy=\log_{0.5}x
    • B.y=(13)xy=\left(\frac{1}{3}\right)^x
    • C.y=2x+1y=2x+1
    • D.y=sin⁡xy=\sin x
    Show answer & solution

    Answer: C

    Answer: C y=2x+1y=2x+1 is a linear function with positive slope, so it is increasing. Choose C.
    See it in the full CSCA Math December 2025 Past Paper
  2. CSCA Math April 2026 Past Paper
    Which function is decreasing on (−∞,+∞)( - \infty , + \infty ) ?
    • A.y=−x+5y = - x + 5
    • B.y=x3y = x ^ { 3 }
    • C.y=x2+1y = x ^ { 2 } + 1
    • D.y=−1xy = - \frac { 1 } { x }
    Show answer & solution

    Answer: A

    (A) Linear with slope −1<0- 1 < 0, decreasing on all of R✓\mathbb { R } \checkmark. (B) x3x ^ { 3 } is increasing on R\mathbb { R }; (C) parabola is not monotonic; (D) undefined at x=0x = 0, so not on all of R\mathbb { R }; moreover on each piece (−∞,0)( - \infty , 0 ) and (0,+∞)( 0 , + \infty ) it is in fact increasing, since y′=1x2>0y ^ { \prime } = \frac { 1 } { x ^ { 2 } } > 0.
    Take the full CSCA Math April 2026 Past Paper — timed & graded
  3. CSCA Math June 2026 Past Paper
    Which of the following functions is monotonically decreasing?
    • A.y=e−xy = e^{-x}
    • B.y=x2−1y = x^2 - 1
    • C.y=100xy = 100^x
    • D.y=cos⁡xy = \cos x
    Show answer & solution

    Answer: A

    y=e−x=(1e)xy = e^{-x} = \left( \frac{1}{e} \right)^x with base 1e<1\frac{1}{e} < 1 is monotonically decreasing, so (A) is correct. y=x2−1y = x^2 - 1 decreases on (−∞,0)(-\infty, 0) and increases on (0,+∞)(0, +\infty), so it is not monotonic; y=100xy = 100^x has base greater than 1 and is increasing; y=cos⁡xy = \cos x is periodic and not monotonic on its domain. Choose (A).
    Take the full CSCA Math June 2026 Past Paper — timed & graded

Real-exam evidence

Recorded past-paper appearances are listed below; online verification is labelled separately.

4 questions across 4 sittings1 of 4 sittings available to verify free online
  • CSCA Math June 2026 Past Paper1 questionreading page not yet public
  • CSCA Math April 2026 Past Paper1 questionreading page not yet public
  • CSCA Math January 2026 Past Paper1 questionreading page not yet public
  • CSCA Math December 2025 Past Paper1 questionView question 10 and answer free (full paper)

19 questions across 13 mock papers — our own papers, so a coverage signal rather than real-exam evidence

13 related practice questions availablePractise free: FunctionPractise free: Elementary Function

Sitting evidence comes from the CSCA past papers on record; questions whose original paper is missing are excluded, and sprint papers are deliberately not counted.

Glossary

Related concepts