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化学用语与方程式 - Practice Questions (37)

Question 1: 1.一氧化二氮 ${ } ^ { \left( \mathrm { N } _ { 2 } \mathrm { O } \right) }$ 是一种麻醉剂,少量吸入后可迅速镇痛,且不会损伤心、肺、肝、...

1.一氧化二氮 ${ } ^ { \left( \mathrm { N } _ { 2 } \mathrm { O } \right) }$ 是一种麻醉剂,少量吸入后可迅速镇痛,且不会损伤心、肺、肝、肾 等重要脏器。一氧化二氮 $\left( \mathrm { N } _ { 2 } \mathrm { O } \right) _ { \text {中氮元素的化合价为( )} }$

  • A. A. - 1
  • B. B. - 2
  • C. C. + 1
  • D. D. + 2

Answer: C

Solution: 一氧化二氮中氧元素一般显 - 2 价,设氮元素的化合价是 $x$ ,根据在化合物中正负化合价代数和为零,可得: $2 x + ( - 2 ) = 0$ ,则 $x = + 1$ 价。故选:C。

Question 2: 2 .下列化学基本用语中表示正确的是( ) <img class="imgSvg" id = "mi1mzfvmlf7f2kus5mf" src="data:image/svg+xml;base64...

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  • A. A. $\mathrm { CCl } _ { 4 }$ 的电子式:
  • B. B. HClO 的结构式 : $\mathrm { H } - \mathrm { Cl } - \mathrm { O }$
  • C. C. $\mathrm { CO } _ { 2 }$ 的分子结构模型: $\square$ D.${ } ^ { 34 } \mathrm {~S} ^ { 2 - }$ 的结构示意图 :
  • D. D. $\mathrm { CO } _ { 2 }$ 的分子结构模型: $\square$ D.${ } ^ { 34 } \mathrm {~S} ^ { 2 - }$

Answer: D

Solution: A.氯原子最外层有 7 个电子,四个氯原子分别与碳原子形成 1 对共用电子对,四氯化碳中 Cl 原子最外层也是 8 电子结构, A 错误; B. HClO 中 O 原子与 $\mathrm { Cl } 、 \mathrm { H }$ 原子分别共用一对电子,结构式为 $\mathrm { H } - \mathrm { O } - \mathrm { Cl }$ ,B 错误 ; C.C 原子的半径应大于 O 原子,模型错误,C 错误; D.${ } ^ { 34 } \mathrm {~S}$ 原子核外有 16 个电子,得到两个电子形成 ${ } ^ { 34 } \mathrm {~S} ^ { 2 - }$ ,结构示意图为 $( + 16 )$ 考攵) $\left. { } ^ { 8 } \right| _ { \mid } ^ { 8 }$ ,D正确;综上所述答案为D。

Question 3: 3.正确掌握好化学用语是学好化学的基础,下列有关表述正确的是( ) ![](/images/questions/chem-nomenclature/image-001.jpg) ![](/ima...

3.正确掌握好化学用语是学好化学的基础,下列有关表述正确的是( ) ![](/images/questions/chem-nomenclature/image-001.jpg) ![](/images/questions/chem-nomenclature/image-002.jpg) <img class="imgSvg" id = "mi1mzfvqq3sqgls7l1" src="data:image/svg+xml;base64,<svg id="smiles-mi1mzfvqq3sqgls7l1" xmlns="http://www.w3.org/2000/svg" viewBox="0 0 147 104.99999999999365" style="width: 146.99999999999363px; height: 104.99999999999365px; overflow: visible;"><defs><linearGradient id="line-mi1mzfvqq3sqgls7l1-1" gradientUnits="userSpaceOnUse" x1="73.49999999999683" y1="52.49999999999683" x2="104.99999999999366" y2="52.50001413730401"><stop stop-color="currentColor" offset="20%"></stop><stop stop-color="currentColor" offset="100%"></stop></linearGradient><linearGradient id="line-mi1mzfvqq3sqgls7l1-3" gradientUnits="userSpaceOnUse" x1="42" y1="52.49998586268964" x2="73.49999999999683" y2="52.49999999999683"><stop stop-color="currentColor" offset="20%"></stop><stop stop-color="currentColor" offset="100%"></stop></linearGradient><linearGradient id="line-mi1mzfvqq3sqgls7l1-5" gradientUnits="userSpaceOnUse" x1="73.49999999999683" y1="52.49999999999683" x2="73.500014137304" y2="21"><stop stop-color="currentColor" offset="20%"></stop><stop stop-color="currentColor" offset="100%"></stop></linearGradient><linearGradient id="line-mi1mzfvqq3sqgls7l1-7" gradientUnits="userSpaceOnUse" x1="73.49998586268964" y1="83.99999999999365" x2="73.49999999999683" y2="52.49999999999683"><stop stop-color="currentColor" offset="20%"></stop><stop stop-color="currentColor" offset="100%"></stop></linearGradient></defs><mask id="text-mask-mi1mzfvqq3sqgls7l1"><rect x="0" y="0" width="100%" height="100%" fill="white"></rect><circle cx="104.99999999999366" cy="52.50001413730401" r="7.875" fill="black"></circle><circle cx="73.49999999999683" cy="52.49999999999683" r="7.875" fill="black"></circle><circle cx="42" cy="52.49998586268964" r="7.875" fill="black"></circle><circle cx="73.500014137304" cy="21" r="7.875" fill="black"></circle><circle cx="73.49998586268964" cy="83.99999999999365" r="7.875" fill="black"></circle></mask><style>
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  • A. A. 乙烯的结构式: $\mathrm { CH } _ { 2 } = \mathrm { CH } _ { 2 }$
  • B. B. 甲烷的空间填充模型:
  • C. C. 硫原子的结构示意图:
  • D. D. 四氯化碳的电子式:

Answer: C

Solution: A.图示为乙烯的结构简式,结构式为 <img class="imgSvg" id = "mi1mzfx2ww1z8l82l5h" src="data:image/svg+xml;base64,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"/> ,A 错误 ; B.图示为甲烷的球棍模型,空间填充满型为 ![](/images/questions/chem-nomenclature/image-003.jpg) B 错误 ; C.图示为硫原子的结构示意图,C正确; D.图示中每个氯原子周围应该有 8 个电子,D错误;

Question 4: 5.下列有关化学用语表示正确的是

5.下列有关化学用语表示正确的是

  • A. A. $\mathrm { Cl } ^ { - }$的结构示意图:(+17) 288
  • B. B. ${ } ^ { 2 } \mathrm { H } _ { 2 }$ 的摩尔质量: $2 \mathrm {~g} \cdot \mathrm {~mol} ^ { - 1 }$
  • C. C. 漂白粉有效成分的化学式: NaClO
  • D. D. NaOH 电离方程式 : $\mathrm { NaOH } = \mathrm { Na } ^ { + } + \mathrm { O } ^ { 2 - } + \mathrm { H } ^ { + }$

Answer: A

Solution: A. $\mathrm { Cl } ^ { - }$的核电荷数为 17 ,核外电子数为 18 ,其结构示意图为 (+17) $\begin{aligned} & 1 ) \\ & 288 \\ & 11 ) \end{aligned}$ ,A正确; B.${ } ^ { 2 } \mathrm { H } _ { 2 }$ 的摩尔质量为 $4 \mathrm {~g} \cdot \mathrm {~mol} ^ { - 1 }$ ,B 错误 ; C.漂白粉有效成分的化学式为 $\mathrm { Ca } ( \mathrm { ClO } ) _ { 2 }$ ,C 错误; D. NaOH 电离方程式: $\mathrm { NaOH } = \mathrm { Na } ^ { + } + \mathrm { OH } ^ { - }$,D 错误。 答案选 A。

Question 5: 6 .下列表示不正确的是 ![](/images/questions/chem-nomenclature/image-004.jpg)

6 .下列表示不正确的是 ![](/images/questions/chem-nomenclature/image-004.jpg)

  • A. A. 苯的实验式: $\mathrm { C } _ { 6 } \mathrm { H } _ { 6 }$
  • B. B. 乙醛的结构简式: $\mathrm { CH } _ { 3 } \mathrm { CHO }$
  • C. C. 氨基的电子式:$\underset { \bullet } { \stackrel { H } { N } } : \mathrm { H }$
  • D. D. 乙烷的球棍模型:

Answer: A

Solution: A.苯的分子式为: $\mathrm { C } _ { 6 } \mathrm { H } _ { 6 }$ ,其实验式为: $\mathrm { CH } , \mathrm { A }$ 错误; B.乙醛含有醛基,其结构简式为: $\mathrm { CH } _ { 3 } \mathrm { CHO }$ ,B 正确; C.氮原子的最外层电子数为 5 ,氢原子电子数为 1 ,则氨基的电子式为:$\underset { . } { \stackrel { H } { \mathrm { H } } } : \mathrm { H }$ ,C正确; D.乙烷结构简式为: $\mathrm { CH } _ { 3 } \mathrm { CH } _ { 3 }$ ,其球棍模型为: ![](/images/questions/chem-nomenclature/image-005.jpg) D正确;

Question 6: 7.化学用语可以表示化学过程。下列化学用语书写正确的是 ![](/images/questions/chem-nomenclature/image-006.jpg)

7.化学用语可以表示化学过程。下列化学用语书写正确的是 ![](/images/questions/chem-nomenclature/image-006.jpg)

  • A. A. $\mathrm { NH } _ { 3 }$ 的电子式 :$\underset { \mathrm { H } : } { \stackrel { \mathrm { H } } { \mathrm { N } } } : \mathrm { H }$
  • B. B. $\mathrm { S } ^ { 2 - }$ 的结构示意图 :
  • C. C. Si位于第三周期第VI A族
  • D. D. $\mathrm { NaHSO } _ { 4 }$ 在水中的电离方程式: $\mathrm { NaHSO } _ { 4 } = \mathrm { Na } ^ { + } + \mathrm { HSO } _ { 4 } ^ { - }$

Answer: B

Solution: A.N原子周围有 8 个电子, $\mathrm { NH } _ { 3 }$ 的电子式应为:$\underset { \mathrm { H } : ( \underset { . } { \mathrm { N } } : \mathrm { H } } { \stackrel { \mathrm { H } } { \mathrm { H } } } , \mathrm { A }$ 错误; B.S是16号元素,的结构示意图为:(+16) 288 ,B正确; $\mathrm { S } ^ { 2 - }$ C.Si是14号元素,位于第三周期IV A 族,C 错误; D. $\mathrm { NaHSO } _ { 4 }$ 在水中的电离方程式应为 $\mathrm { NaHSO } _ { 4 } = \mathrm { Na } ^ { + } + \mathrm { H } ^ { + } + \mathrm { SO } _ { 4 } ^ { 2 - }$ ,D 错误 ;

Question 7: 8.化学科学需要借助化学专用语言来描述。下列有关化学用语表示错误的是 <img class="imgSvg" id = "mi1mzfvsp36nxcywo6p" src="data:imag...

8.化学科学需要借助化学专用语言来描述。下列有关化学用语表示错误的是 <img class="imgSvg" id = "mi1mzfvsp36nxcywo6p" src="data:image/svg+xml;base64,<svg id="smiles-mi1mzfvsp36nxcywo6p" xmlns="http://www.w3.org/2000/svg" viewBox="0 0 193 105.00003672978717" style="width: 193.11920087681457px; height: 105.00003672978717px; overflow: visible;"><defs><linearGradient id="line-mi1mzfvsp36nxcywo6p-1" gradientUnits="userSpaceOnUse" x1="123.83939005463054" y1="36.75005509469861" x2="151.11920087681457" y2="21.00007345960293"><stop stop-color="currentColor" offset="20%"></stop><stop stop-color="currentColor" offset="100%"></stop></linearGradient><linearGradient id="line-mi1mzfvsp36nxcywo6p-3" gradientUnits="userSpaceOnUse" x1="118.16937096926715" y1="65.10005127761923" x2="118.16938793403575" y2="39.900051277624954"><stop stop-color="currentColor" offset="20%"></stop><stop stop-color="currentColor" offset="100%"></stop></linearGradient><linearGradient id="line-mi1mzfvsp36nxcywo6p-5" gradientUnits="userSpaceOnUse" x1="123.83936884866978" y1="68.25005509469146" x2="123.83939005463054" y2="36.75005509469861"><stop stop-color="currentColor" offset="20%"></stop><stop stop-color="currentColor" offset="100%"></stop></linearGradient><linearGradient id="line-mi1mzfvsp36nxcywo6p-7" gradientUnits="userSpaceOnUse" x1="96.55960043840724" y1="21.000036729801437" x2="123.83939005463054" y2="36.75005509469861"><stop stop-color="currentColor" offset="20%"></stop><stop stop-color="currentColor" offset="100%"></stop></linearGradient><linearGradient id="line-mi1mzfvsp36nxcywo6p-9" gradientUnits="userSpaceOnUse" x1="96.55955802648577" y1="84.00003672978717" x2="123.83936884866978" y2="68.25005509469146"><stop stop-color="currentColor" offset="20%"></stop><stop stop-color="currentColor" offset="100%"></stop></linearGradient><linearGradient id="line-mi1mzfvsp36nxcywo6p-11" gradientUnits="userSpaceOnUse" x1="74.84276739275889" y1="40.085386149380696" x2="96.66661605050608" y2="27.485400841304127"><stop stop-color="currentColor" offset="20%"></stop><stop stop-color="currentColor" offset="100%"></stop></linearGradient><linearGradient id="line-mi1mzfvsp36nxcywo6p-13" gradientUnits="userSpaceOnUse" x1="69.27978961622325" y1="36.75001836489716" x2="96.55960043840724" y2="21.000036729801437"><stop stop-color="currentColor" offset="20%"></stop><stop stop-color="currentColor" offset="100%"></stop></linearGradient><linearGradient id="line-mi1mzfvsp36nxcywo6p-15" gradientUnits="userSpaceOnUse" x1="74.84275067756633" y1="64.91465807045954" x2="96.66658237054493" y2="77.51467276237726"><stop stop-color="currentColor" offset="20%"></stop><stop stop-color="currentColor" offset="100%"></stop></linearGradient><linearGradient id="line-mi1mzfvsp36nxcywo6p-17" gradientUnits="userSpaceOnUse" x1="69.2797684102625" y1="68.25001836489001" x2="96.55955802648577" y2="84.00003672978717"><stop stop-color="currentColor" offset="20%"></stop><stop stop-color="currentColor" offset="100%"></stop></linearGradient><linearGradient id="line-mi1mzfvsp36nxcywo6p-19" gradientUnits="userSpaceOnUse" x1="69.2797684102625" y1="68.25001836489001" x2="69.27978961622325" y2="36.75001836489716"><stop stop-color="currentColor" offset="20%"></stop><stop stop-color="currentColor" offset="100%"></stop></linearGradient><linearGradient id="line-mi1mzfvsp36nxcywo6p-21" gradientUnits="userSpaceOnUse" x1="42" y1="21" x2="69.27978961622325" y2="36.75001836489716"><stop stop-color="currentColor" offset="20%"></stop><stop stop-color="currentColor" offset="100%"></stop></linearGradient></defs><mask id="text-mask-mi1mzfvsp36nxcywo6p"><rect x="0" y="0" width="100%" height="100%" fill="white"></rect><circle cx="42" cy="21" r="7.875" fill="black"></circle></mask><style>
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  • A. A. 羟基的电子式:${ } _ { \mathrm { g } \mathrm { g } } ^ { \mathrm { g } \mathrm { g } } : \mathrm { H }$
  • B. B. 丙醇的化学式: $\mathrm { C } _ { 3 } \mathrm { H } _ { 8 } \mathrm { O }$
  • C. C. 甲酸乙酯的结构简式: $\mathrm { HCOOCH } _ { 2 } \mathrm { CH } _ { 3 }$
  • D. D. 间甲基苯酚 :

Answer: A

Solution: A.羟基的电子式:${ } _ { \mathrm { g } \mathrm { g } } ^ { \mathrm { g } \mathrm { g } } \mathrm { H }$ ,故 A 错误 ; B.丙醇的化学式(分子式): $\mathrm { C } _ { 3 } \mathrm { H } _ { 8 } \mathrm { O }$ ,故 B 正确; C.甲酸乙酯的结构简式: $\mathrm { HCOOCH } _ { 2 } \mathrm { CH } _ { 3 }$ ,故C正确; D.间甲基苯酚,甲基和羟基在间位, <img class="imgSvg" id = "mi1mzfx55aaunrwbbgv" src="data:image/svg+xml;base64,<svg id="smiles-mi1mzfx55aaunrwbbgv" xmlns="http://www.w3.org/2000/svg" viewBox="0 0 193 105.00003672978717" style="width: 193.11920087681457px; height: 105.00003672978717px; overflow: visible;"><defs><linearGradient id="line-mi1mzfx55aaunrwbbgv-1" gradientUnits="userSpaceOnUse" x1="123.83939005463054" y1="36.75005509469861" x2="151.11920087681457" y2="21.00007345960293"><stop stop-color="currentColor" offset="20%"></stop><stop stop-color="currentColor" offset="100%"></stop></linearGradient><linearGradient id="line-mi1mzfx55aaunrwbbgv-3" gradientUnits="userSpaceOnUse" x1="118.16937096926715" y1="65.10005127761923" x2="118.16938793403575" y2="39.900051277624954"><stop stop-color="currentColor" offset="20%"></stop><stop stop-color="currentColor" offset="100%"></stop></linearGradient><linearGradient id="line-mi1mzfx55aaunrwbbgv-5" gradientUnits="userSpaceOnUse" x1="123.83936884866978" y1="68.25005509469146" x2="123.83939005463054" y2="36.75005509469861"><stop stop-color="currentColor" offset="20%"></stop><stop stop-color="currentColor" offset="100%"></stop></linearGradient><linearGradient id="line-mi1mzfx55aaunrwbbgv-7" gradientUnits="userSpaceOnUse" x1="96.55960043840724" y1="21.000036729801437" x2="123.83939005463054" y2="36.75005509469861"><stop stop-color="currentColor" offset="20%"></stop><stop stop-color="currentColor" offset="100%"></stop></linearGradient><linearGradient id="line-mi1mzfx55aaunrwbbgv-9" gradientUnits="userSpaceOnUse" x1="96.55955802648577" y1="84.00003672978717" x2="123.83936884866978" y2="68.25005509469146"><stop stop-color="currentColor" offset="20%"></stop><stop stop-color="currentColor" offset="100%"></stop></linearGradient><linearGradient id="line-mi1mzfx55aaunrwbbgv-11" gradientUnits="userSpaceOnUse" x1="74.84276739275889" y1="40.085386149380696" x2="96.66661605050608" y2="27.485400841304127"><stop stop-color="currentColor" offset="20%"></stop><stop stop-color="currentColor" offset="100%"></stop></linearGradient><linearGradient id="line-mi1mzfx55aaunrwbbgv-13" gradientUnits="userSpaceOnUse" x1="69.27978961622325" y1="36.75001836489716" x2="96.55960043840724" y2="21.000036729801437"><stop stop-color="currentColor" offset="20%"></stop><stop stop-color="currentColor" offset="100%"></stop></linearGradient><linearGradient id="line-mi1mzfx55aaunrwbbgv-15" gradientUnits="userSpaceOnUse" x1="74.84275067756633" y1="64.91465807045954" x2="96.66658237054493" y2="77.51467276237726"><stop stop-color="currentColor" offset="20%"></stop><stop stop-color="currentColor" offset="100%"></stop></linearGradient><linearGradient id="line-mi1mzfx55aaunrwbbgv-17" gradientUnits="userSpaceOnUse" x1="69.2797684102625" y1="68.25001836489001" x2="96.55955802648577" y2="84.00003672978717"><stop stop-color="currentColor" offset="20%"></stop><stop stop-color="currentColor" offset="100%"></stop></linearGradient><linearGradient id="line-mi1mzfx55aaunrwbbgv-19" gradientUnits="userSpaceOnUse" x1="69.2797684102625" y1="68.25001836489001" x2="69.27978961622325" y2="36.75001836489716"><stop stop-color="currentColor" offset="20%"></stop><stop stop-color="currentColor" offset="100%"></stop></linearGradient><linearGradient id="line-mi1mzfx55aaunrwbbgv-21" gradientUnits="userSpaceOnUse" x1="42" y1="21" x2="69.27978961622325" y2="36.75001836489716"><stop stop-color="currentColor" offset="20%"></stop><stop stop-color="currentColor" offset="100%"></stop></linearGradient></defs><mask id="text-mask-mi1mzfx55aaunrwbbgv"><rect x="0" y="0" width="100%" height="100%" fill="white"></rect><circle cx="42" cy="21" r="7.875" fill="black"></circle></mask><style>
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Question 8: 9.化学科学需要借助化学专用语言来描述,下列有关化学用语正确的是 <img class="imgSvg" id = "mi1mzfvuu94ks3qk2pd" src="data:image/sv...

9.化学科学需要借助化学专用语言来描述,下列有关化学用语正确的是 <img class="imgSvg" id = "mi1mzfvuu94ks3qk2pd" src="data:image/svg+xml;base64,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  • A. A. $\mathrm { CO } _ { 2 }$ 的电子式:$\ddot { \mathrm { O } } : \ddot { \mathrm { C } } : \ddot { \mathrm { O } } :$
  • B. B. $\mathrm { CH } _ { 4 }$ 分子的比例模型:
  • C. C. $\mathrm { NH } _ { 4 } \mathrm { Cl }$ 的电子式: $\left[ \underset { \ddot { \mathrm { H } } } { \stackrel { \mathbf { H } } { = } } \mathbf { H } ^ { + } \mathbf { C l } ^ { - } \right.$
  • D. D. 原子核内有 10 个中子的氧原子:${ } _ { 8 } ^ { 18 } \mathrm { O }$

Answer: D

Solution: 试题分析: A 不正确,应该是:$\ddot { \mathrm { O } } : \mathbf { x } _ { \mathbf { x } } ^ { \mathbf { x } } \mathrm { C } \mathbf { x } : \ddot { \mathrm { O } } :$ ; B 不正确,这应该是球棍模型; C 不正确,应该是 $\left[ \begin{array} { c } \mathrm { H } : \underset { \ddot { \mathrm { H } } } { \ddot { \mathrm { N } } } : \mathrm { H } \end{array} \right] ^ { + } [ : \ddot { \mathrm { C } 1 } : ] ^ { - }$,所以答案选 D。 考点:考查常见化学用语的正误判断 点评:该题是中等难度的试题,也是高考中的常见题型与重要的考点。该题基础性强,难易适中,主要是考查学生对常见化学用语的熟悉掌握程度。该类试题需要明确的是常见的化学用语主要包括元素符号、化学式、化合价、电子式、原子结构示意图、结构式、结构简式以及方程式和各种模型等,需要学生熟练记住。

Question 9: 10.下列化学用语表达正确的是

10.下列化学用语表达正确的是

  • A. A. $\mathrm { CH } _ { 4 }$ 的电子式: $\mathrm { H } : \stackrel { \text { H } } { \underset { \rightarrow } { \ddot { C } } } : \mathrm { H }$
  • B. B. 丙烷的分子式: $\mathrm { CH } _ { 3 } \mathrm { CHCH } _ { 2 }$
  • C. C. 乙醛的结构简式: $\mathrm { CH } _ { 3 } \mathrm { COH }$
  • D. D. 丙烯的结构简式: $\mathrm { CH } _ { 3 } \mathrm { CHCH } _ { 2 }$

Answer: A

Solution: $\mathrm { A } . \mathrm { CH } _ { 4 }$ 中碳原子形成 4 个 $\mathrm { C } - \mathrm { H }$ 键,电子式为 $\mathrm { H } : \stackrel { \text { H } } { \stackrel { \mathrm { H } } { \mathrm { C } } } : \mathrm { H } , \mathrm { A }$ 正确; H B.丙烷的结构简式为 $\mathrm { CH } _ { 3 } \mathrm { CH } _ { 2 } \mathrm { CH } _ { 3 }$ ,分子式为 $\mathrm { C } _ { 3 } \mathrm { H } _ { 8 }$ ,B 错误 ; C.乙醛的结构简式为 $\mathrm { CH } _ { 3 } \mathrm { CHO }$ ,C 错误; D.丙烯的结构简式为 $\mathrm { CH } _ { 3 } \mathrm { CH } = \mathrm { CH } _ { 2 } , \mathrm { D }$ 错误;

Question 10: 11.下列化学用语表达正确的是 ![](/images/questions/chem-nomenclature/image-007.jpg)

11.下列化学用语表达正确的是 ![](/images/questions/chem-nomenclature/image-007.jpg)

  • A. A. $\mathrm { CH } _ { 4 }$ 分子的空间充填模型:
  • B. B. 氟原子的结构示意图 :+$+ 9 ) 28$
  • C. C. 具有 6 个质子和 8 个中子的核素符号:${ } _ { 6 } ^ { 12 } \mathrm { C } 8$
  • D. D. 乙烯的官能团:C=C

Answer: A

Solution: A. $\mathrm { CH } _ { 4 }$ 是正四面体形分子,分子的空间填充模型: ![](/images/questions/chem-nomenclature/image-008.jpg) B.氟原子不带电,原子最外层有 7 个电子,B 不正确; C.具有 6 个质子的元素为 C,含有 8 个中子,则质量数为 14 ,故具有 6 个质子和 8 个中子的核素符号:${ } ^ { 14 } \mathrm { C }$ ,C 不正确; D.乙烯的官能团: <img class="imgSvg" id = "mi1mzfx655vfte8ckvp" src="data:image/svg+xml;base64,PHN2ZyBpZD0ic21pbGVzLW1pMW16Zng2NTV2ZnRlOGNrdnAiIHhtbG5zPSJodHRwOi8vd3d3LnczLm9yZy8yMDAwL3N2ZyIgdmlld0JveD0iMCAwIDE2NiAxMjAuNzQ5OTgxNjM1MDgxNDEiIHN0eWxlPSJ3aWR0aDogMTY1LjgzOTM5MDA1NDYzMDU0cHg7IGhlaWdodDogMTIwLjc0OTk4MTYzNTA4MTQxcHg7IG92ZXJmbG93OiB2aXNpYmxlOyI+PGRlZnM+PGxpbmVhckdyYWRpZW50IGlkPSJsaW5lLW1pMW16Zng2NTV2ZnRlOGNrdnAtMSIgZ3JhZGllbnRVbml0cz0idXNlclNwYWNlT25Vc2UiIHgxPSI5Ni41NTk2MDA0Mzg0MDcyNyIgeTE9IjUyLjQ5OTk5OTk5OTk5Mjg2NiIgeDI9IjEyMy44MzkzOTAwNTQ2MzA1NCIgeTI9IjY4LjI1MDAxODM2NDg5MDA0Ij48c3RvcCBzdG9wLWNvbG9yPSJjdXJyZW50Q29sb3IiIG9mZnNldD0iMjAlIj48L3N0b3A+PHN0b3Agc3RvcC1jb2xvcj0iY3VycmVudENvbG9yIiBvZmZzZXQ9IjEwMCUiPjwvc3RvcD48L2xpbmVhckdyYWRpZW50PjxsaW5lYXJHcmFkaWVudCBpZD0ibGluZS1taTFtemZ4NjU1dmZ0ZThja3ZwLTMiIGdyYWRpZW50VW5pdHM9InVzZXJTcGFjZU9uVXNlIiB4MT0iOTYuNTU5NjAwNDM4NDA3MjciIHkxPSI1Mi40OTk5OTk5OTk5OTI4NjYiIHgyPSI5Ni41NTk2MjE2NDQzNjgwNCIgeTI9IjIxIj48c3RvcCBzdG9wLWNvbG9yPSJjdXJyZW50Q29sb3IiIG9mZnNldD0iMjAlIj48L3N0b3A+PHN0b3Agc3RvcC1jb2xvcj0iY3VycmVudENvbG9yIiBvZmZzZXQ9IjEwMCUiPjwvc3RvcD48L2xpbmVhckdyYWRpZW50PjxsaW5lYXJHcmFkaWVudCBpZD0ibGluZS1taTFtemZ4NjU1dmZ0ZThja3ZwLTUiIGdyYWRpZW50VW5pdHM9InVzZXJTcGFjZU9uVXNlIiB4MT0iNzQuODQyNzY3MzkyNzU4ODciIHkxPSI3MS41ODUzNDk0MTk1NzIxMyIgeDI9Ijk2LjY2NjYxNjA1MDUwNjEiIHkyPSI1OC45ODUzNjQxMTE0OTU1NiI+PHN0b3Agc3RvcC1jb2xvcj0iY3VycmVudENvbG9yIiBvZmZzZXQ9IjIwJSI+PC9zdG9wPjxzdG9wIHN0b3AtY29sb3I9ImN1cnJlbnRDb2xvciIgb2Zmc2V0PSIxMDAlIj48L3N0b3A+PC9saW5lYXJHcmFkaWVudD48bGluZWFyR3JhZGllbnQgaWQ9ImxpbmUtbWkxbXpmeDY1NXZmdGU4Y2t2cC03IiBncmFkaWVudFVuaXRzPSJ1c2VyU3BhY2VPblVzZSIgeDE9IjY5LjI3OTc4OTYxNjIyMzI1IiB5MT0iNjguMjQ5OTgxNjM1MDg4NTYiIHgyPSI5Ni41NTk2MDA0Mzg0MDcyNyIgeTI9IjUyLjQ5OTk5OTk5OTk5Mjg2NiI+PHN0b3Agc3RvcC1jb2xvcj0iY3VycmVudENvbG9yIiBvZmZzZXQ9IjIwJSI+PC9zdG9wPjxzdG9wIHN0b3AtY29sb3I9ImN1cnJlbnRDb2xvciIgb2Zmc2V0PSIxMDAlIj48L3N0b3A+PC9saW5lYXJHcmFkaWVudD48bGluZWFyR3JhZGllbnQgaWQ9ImxpbmUtbWkxbXpmeDY1NXZmdGU4Y2t2cC05IiBncmFkaWVudFVuaXRzPSJ1c2VyU3BhY2VPblVzZSIgeDE9IjQyIiB5MT0iNTIuNDk5OTYzMjcwMTkxMzkiIHgyPSI2OS4yNzk3ODk2MTYyMjMyNSIgeTI9IjY4LjI0OTk4MTYzNTA4ODU2Ij48c3RvcCBzdG9wLWNvbG9yPSJjdXJyZW50Q29sb3IiIG9mZnNldD0iMjAlIj48L3N0b3A+PHN0b3Agc3RvcC1jb2xvcj0iY3VycmVudENvbG9yIiBvZmZzZXQ9IjEwMCUiPjwvc3RvcD48L2xpbmVhckdyYWRpZW50PjxsaW5lYXJHcmFkaWVudCBpZD0ibGluZS1taTFtemZ4NjU1dmZ0ZThja3ZwLTExIiBncmFkaWVudFVuaXRzPSJ1c2VyU3BhY2VPblVzZSIgeDE9IjY5LjI3OTc2ODQxMDI2MjQ4IiB5MT0iOTkuNzQ5OTgxNjM1MDgxNDEiIHgyPSI2OS4yNzk3ODk2MTYyMjMyNSIgeTI9IjY4LjI0OTk4MTYzNTA4ODU2Ij48c3RvcCBzdG9wLWNvbG9yPSJjdXJyZW50Q29sb3IiIG9mZnNldD0iMjAlIj48L3N0b3A+PHN0b3Agc3RvcC1jb2xvcj0iY3VycmVudENvbG9yIiBvZmZzZXQ9IjEwMCUiPjwvc3RvcD48L2xpbmVhckdyYWRpZW50PjwvZGVmcz48bWFzayBpZD0idGV4dC1tYXNrLW1pMW16Zng2NTV2ZnRlOGNrdnAiPjxyZWN0IHg9IjAiIHk9IjAiIHdpZHRoPSIxMDAlIiBoZWlnaHQ9IjEwMCUiIGZpbGw9IndoaXRlIj48L3JlY3Q+PC9tYXNrPjxzdHlsZT4KICAgICAgICAgICAgICAgIC5lbGVtZW50LW1pMW16Zng2NTV2ZnRlOGNrdnAgewogICAgICAgICAgICAgICAgICAgIGZvbnQ6IDE0cHggSGVsdmV0aWNhLCBBcmlhbCwgc2Fucy1zZXJpZjsKICAgICAgICAgICAgICAgICAgICBhbGlnbm1lbnQtYmFzZWxpbmU6ICdtaWRkbGUnOwogICAgICAgICAgICAgICAgfQogICAgICAgICAgICAgICAgLnN1Yi1taTFtemZ4NjU1dmZ0ZThja3ZwIHsKICAgICAgICAgICAgICAgICAgICBmb250OiA4LjRweCBIZWx2ZXRpY2EsIEFyaWFsLCBzYW5zLXNlcmlmOwogICAgICAgICAgICAgICAgfQogICAgICAgICAgICA8L3N0eWxlPjxnIG1hc2s9InVybCgjdGV4dC1tYXNrLW1pMW16Zng2NTV2ZnRlOGNrdnApIj48bGluZSB4MT0iOTYuNTU5NjAwNDM4NDA3MjciIHkxPSI1Mi40OTk5OTk5OTk5OTI4NjYiIHgyPSIxMjMuODM5MzkwMDU0NjMwNTQiIHkyPSI2OC4yNTAwMTgzNjQ4OTAwNCIgc3R5bGU9InN0cm9rZS1saW5lY2FwOnJvdW5kO3N0cm9rZS1kYXNoYXJyYXk6bm9uZTtzdHJva2Utd2lkdGg6MS4yNiIgc3Ryb2tlPSJ1cmwoJyNsaW5lLW1pMW16Zng2NTV2ZnRlOGNrdnAtMScpIj48L2xpbmU+PGxpbmUgeDE9Ijk2LjU1OTYwMDQzODQwNzI3IiB5MT0iNTIuNDk5OTk5OTk5OTkyODY2IiB4Mj0iOTYuNTU5NjIxNjQ0MzY4MDQiIHkyPSIyMSIgc3R5bGU9InN0cm9rZS1saW5lY2FwOnJvdW5kO3N0cm9rZS1kYXNoYXJyYXk6bm9uZTtzdHJva2Utd2lkdGg6MS4yNiIgc3Ryb2tlPSJ1cmwoJyNsaW5lLW1pMW16Zng2NTV2ZnRlOGNrdnAtMycpIj48L2xpbmU+PGxpbmUgeDE9Ijc0Ljg0Mjc2NzM5Mjc1ODg3IiB5MT0iNzEuNTg1MzQ5NDE5NTcyMTMiIHgyPSI5Ni42NjY2MTYwNTA1MDYxIiB5Mj0iNTguOTg1MzY0MTExNDk1NTYiIHN0eWxlPSJzdHJva2UtbGluZWNhcDpyb3VuZDtzdHJva2UtZGFzaGFycmF5Om5vbmU7c3Ryb2tlLXdpZHRoOjEuMjYiIHN0cm9rZT0idXJsKCcjbGluZS1taTFtemZ4NjU1dmZ0ZThja3ZwLTUnKSI+PC9saW5lPjxsaW5lIHgxPSI2OS4yNzk3ODk2MTYyMjMyNSIgeTE9IjY4LjI0OTk4MTYzNTA4ODU2IiB4Mj0iOTYuNTU5NjAwNDM4NDA3MjciIHkyPSI1Mi40OTk5OTk5OTk5OTI4NjYiIHN0eWxlPSJzdHJva2UtbGluZWNhcDpyb3VuZDtzdHJva2UtZGFzaGFycmF5Om5vbmU7c3Ryb2tlLXdpZHRoOjEuMjYiIHN0cm9rZT0idXJsKCcjbGluZS1taTFtemZ4NjU1dmZ0ZThja3ZwLTcnKSI+PC9saW5lPjxsaW5lIHgxPSI0MiIgeTE9IjUyLjQ5OTk2MzI3MDE5MTM5IiB4Mj0iNjkuMjc5Nzg5NjE2MjIzMjUiIHkyPSI2OC4yNDk5ODE2MzUwODg1NiIgc3R5bGU9InN0cm9rZS1saW5lY2FwOnJvdW5kO3N0cm9rZS1kYXNoYXJyYXk6bm9uZTtzdHJva2Utd2lkdGg6MS4yNiIgc3Ryb2tlPSJ1cmwoJyNsaW5lLW1pMW16Zng2NTV2ZnRlOGNrdnAtOScpIj48L2xpbmU+PGxpbmUgeDE9IjY5LjI3OTc2ODQxMDI2MjQ4IiB5MT0iOTkuNzQ5OTgxNjM1MDgxNDEiIHgyPSI2OS4yNzk3ODk2MTYyMjMyNSIgeTI9IjY4LjI0OTk4MTYzNTA4ODU2IiBzdHlsZT0ic3Ryb2tlLWxpbmVjYXA6cm91bmQ7c3Ryb2tlLWRhc2hhcnJheTpub25lO3N0cm9rZS13aWR0aDoxLjI2IiBzdHJva2U9InVybCgnI2xpbmUtbWkxbXpmeDY1NXZmdGU4Y2t2cC0xMScpIj48L2xpbmU+PC9nPjxnPjx0ZXh0IHg9IjEyMy44MzkzOTAwNTQ2MzA1NCIgeT0iNjguMjUwMDE4MzY0ODkwMDQiIGNsYXNzPSJkZWJ1ZyIgZmlsbD0iI2ZmMDAwMCIgc3R5bGU9IgogICAgICAgICAgICAgICAgZm9udDogNXB4IERyb2lkIFNhbnMsIHNhbnMtc2VyaWY7CiAgICAgICAgICAgICI+PC90ZXh0Pjx0ZXh0IHg9Ijk2LjU1OTYwMDQzODQwNzI3IiB5PSI1Mi40OTk5OTk5OTk5OTI4NjYiIGNsYXNzPSJkZWJ1ZyIgZmlsbD0iI2ZmMDAwMCIgc3R5bGU9IgogICAgICAgICAgICAgICAgZm9udDogNXB4IERyb2lkIFNhbnMsIHNhbnMtc2VyaWY7CiAgICAgICAgICAgICI+PC90ZXh0Pjx0ZXh0IHg9Ijk2LjU1OTYyMTY0NDM2ODA0IiB5PSIyMSIgY2xhc3M9ImRlYnVnIiBmaWxsPSIjZmYwMDAwIiBzdHlsZT0iCiAgICAgICAgICAgICAgICBmb250OiA1cHggRHJvaWQgU2Fucywgc2Fucy1zZXJpZjsKICAgICAgICAgICAgIj48L3RleHQ+PHRleHQgeD0iNjkuMjc5Nzg5NjE2MjIzMjUiIHk9IjY4LjI0OTk4MTYzNTA4ODU2IiBjbGFzcz0iZGVidWciIGZpbGw9IiNmZjAwMDAiIHN0eWxlPSIKICAgICAgICAgICAgICAgIGZvbnQ6IDVweCBEcm9pZCBTYW5zLCBzYW5zLXNlcmlmOwogICAgICAgICAgICAiPjwvdGV4dD48dGV4dCB4PSI0MiIgeT0iNTIuNDk5OTYzMjcwMTkxMzkiIGNsYXNzPSJkZWJ1ZyIgZmlsbD0iI2ZmMDAwMCIgc3R5bGU9IgogICAgICAgICAgICAgICAgZm9udDogNXB4IERyb2lkIFNhbnMsIHNhbnMtc2VyaWY7CiAgICAgICAgICAgICI+PC90ZXh0Pjx0ZXh0IHg9IjY5LjI3OTc2ODQxMDI2MjQ4IiB5PSI5OS43NDk5ODE2MzUwODE0MSIgY2xhc3M9ImRlYnVnIiBmaWxsPSIjZmYwMDAwIiBzdHlsZT0iCiAgICAgICAgICAgICAgICBmb250OiA1cHggRHJvaWQgU2Fucywgc2Fucy1zZXJpZjsKICAgICAgICAgICAgIj48L3RleHQ+PC9nPjwvc3ZnPg=="/> ,D 不正确 ;

Question 11: 12 .下列表示或说法正确的是 ![](/images/questions/chem-nomenclature/image-009.jpg)

12 .下列表示或说法正确的是 ![](/images/questions/chem-nomenclature/image-009.jpg)

  • A. A. 硫原子结构示意图 :
  • B. B. $\mathrm { CS } _ { 2 }$ 的球棍模型 :
  • C. C. 甲酸甲酯的最简式: $\mathrm { CH } _ { 2 } \mathrm { O }$
  • D. D. 氯化钙的分子式: $\mathrm { CaCl } _ { 2 }$

Answer: C

Solution: A.根据硫原子的原子序数是 16 判断,核内质子数是 16 ,核外电子数也是 16 ,故 A 不正确; B.根据杂化类型判断,二硫化碳中碳采用 sp 杂化,空间构型是直线型,故 B 不正确; C.根据甲酸甲酯的结构简式为 $\mathrm { HCOOCH } _ { 3 }$ ,最简式为 $\mathrm { CH } _ { 2 } \mathrm { O }$ ,故 C 正确; D.氯化钙是离子化合物,不是由分子构成,故 D 不正确;

Question 12: 13.下列化学用语或说法表达错误的是

13.下列化学用语或说法表达错误的是

  • A. A. 甲基的结构简式:$- \mathrm { CH } _ { 3 }$
  • B. B. 苯分子的最简式:CH
  • C. C. 正戊烷的碳链是直线形
  • D. D. 化学式 $\mathrm { CH } _ { 2 } \mathrm { Br } _ { 2 }$ 只能表示一种物质

Answer: C

Solution: A.甲基的结构简式:$- \mathrm { CH } _ { 3 }$ , A 正确; B.苯分子的化学式为: $\mathrm { C } _ { 6 } \mathrm { H } _ { 6 }$ ,苯分子的最简式: CH ,B 正确; C.正戊烷分子中的 5 个 C 原子是可以共面的-呈锯齿形排列,只是不能共线,C 错误; D.化学式 $\mathrm { CH } _ { 2 } \mathrm { Br } _ { 2 }$ 只能表示一种物质,不存在同分异构体,D正确;

Question 13: 14.下列化学用语正确的是 <img class="imgSvg" id = "mi1mzfvwvjmfvkggpre" src="data:image/svg+xml;base64,PHN2ZyB...

14.下列化学用语正确的是 <img class="imgSvg" id = "mi1mzfvwvjmfvkggpre" src="data:image/svg+xml;base64,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"/>

  • A. A. 乙烯的电子式:
  • B. B. 甲烷的结构式: $\mathrm { CH } _ { 4 }$
  • C. C. 乙酸分子的比例模型:
  • D. D. 乙烷分子的球棍模型:

Answer: C

Solution:

Question 14: 15. $\mathrm { CO } _ { 2 }$ 加氢转化为燃料是实现 $\mathrm { CO } _ { 2 }$ 减排的一个重要策略,我国科学家在调控 $\mathrm { CO } ...

15. $\mathrm { CO } _ { 2 }$ 加氢转化为燃料是实现 $\mathrm { CO } _ { 2 }$ 减排的一个重要策略,我国科学家在调控 $\mathrm { CO } _ { 2 }$ 加氢反应的选择性方面取得新进展,其过程的示意图如下。下列分析正确的是() ![](/images/questions/chem-nomenclature/image-010.jpg)

  • A. A. 该过程中, $\mathrm { H } _ { 2 }$ 分子中极性键发生断裂
  • B. B. $\mathrm { CO } _ { 2 }$ 的电子式为 $\because \mathrm { C } : \mathrm { O } :$
  • C. C. 该反应中 $\mathrm { CO } _ { 2 }$ 作还原剂
  • D. D. 该反应的化学方程式为 $\mathrm { CO } _ { 2 } + 4 \mathrm { H } _ { 2 } \xlongequal { \text { 催化剂 } } \mathrm { CH } _ { 4 } + 2 \mathrm { H } _ { 2 } \mathrm { C }$

Answer: D

Solution: A.该过程中发生化学反应 $\mathrm { CO } _ { 2 } + 4 \mathrm { H } _ { 2 } \xlongequal { \text { 催化剂 } } \mathrm { CH } _ { 4 } + 2 \mathrm { H } _ { 2 } \mathrm { O }$ ,化学反应旧键断裂新键形成,但是 $\mathrm { H } _ { 2 }$ 分子中是非极性键发生断裂, A 错误; B. $\mathrm { CO } _ { 2 }$ 的电子式为 $\ddot { \mathbf { g } } = \mathbf { c } = \mathbf { = } \ddot { \mathbf { o } }$ , B 错误; C.该反应 $\mathrm { CO } _ { 2 }$ 中的碳元素化合价由 + 4 价变为 - 4 价,化合价降低,作氧化剂,C错误; D.根据上面分析,该反应的化学方程式为: $\mathrm { CO } _ { 2 } + 4 \mathrm { H } _ { 2 } \xlongequal { \text { 催化剂 } } \mathrm { CH } _ { 4 } + 2 \mathrm { H } _ { 2 } \mathrm { O }$ ,D正确;

Question 15: 17.下列化学用语或图示表达错误的是() ![](/images/questions/chem-nomenclature/image-011.jpg)

17.下列化学用语或图示表达错误的是() ![](/images/questions/chem-nomenclature/image-011.jpg)

  • A. A. $\mathrm { SO } _ { 3 } ^ { 2 - }$ 的价层电子对互斥(VSEPR)模型:
  • B. B. $\mathrm { NF } _ { 3 }$ 的电子式::$\underset { . \ddot { \mathrm { F } } : \ddot { \mathrm { F } } : \ddot { \mathrm { F } } : } { \ddot { \mathrm { F } } : }$
  • C. C. HCl 分子中 $\sigma$ 键的形成 $: \stackrel { \mathrm { H } } { \bullet } \rightarrow + \overbrace { } ^ { \mathrm { Cl } } \rightarrow \overbrace { } ^ { \mathrm { H } } \rightarrow \overbrace { } ^ { \mathrm { Cl } }$
  • D. D. 基态锗(Ge)原子的价电子排布式为: $4 s ^ { 2 } 4 p ^ { 2 }$

Answer: B

Solution: A. $\mathrm { SO } _ { 3 } ^ { 2 - }$ 的中心原子 S 原子的价层电子对数为 $3 + \frac { 1 } { 2 } ( 6 + 2 - 2 \times 3 ) = 4$ ,VSEPR 模型为四面体形, A 正确; B.${ } ^ { N F _ { 3 } }$ 中 $N$ 的最外层电子数为 5 个,形成 3 个电子对后还有一个孤电子对,${ } ^ { N F _ { 3 } }$ 的电子式 $: \ddot { \mathrm { F } } : \ddot { \mathrm { N } } : \ddot { \mathrm { F } } :$, B 错误 ; C. HCl 分子内为 $\mathrm { s } - \mathrm { p }$ 的 $\sigma$ 键,形成图示正确,C 正确; D.锗(Ge)为第四周期第 IVA 族,价电子排布式为: $4 \mathrm {~s} ^ { 2 } 4 \mathrm { p } ^ { 2 }$ ,D 正确;

Question 16: 19.下列表述或说法正确的是()

19.下列表述或说法正确的是()

  • A. A. 比例模型 既可以表示甲烷分子,也可以表示四氯化碳分子
  • B. B. - OH 与 $\cdot \mathrm { O } _ { \bullet \bullet } \mathbf { H } \quad$ 都表示羟基
  • C. C. 乙醛的结构简式为: $\mathrm { CH } _ { 3 } \mathrm { COH }$
  • D. D. 苯的最简式: $( \mathrm { CH } ) _ { 6 }$

Answer: B

Solution: A、Cl 原子半径大于 C 原子,四氯化碳分子比例模型不正确,比例模型应符合原子的大小,故 A 错误 ; B、 - OH 为羟基的结构简式,$\quad \ddot { \mathrm { O } } : \mathrm { H }$ 为羟基的电子式,故 B 正确; C、乙醛分子中含有醛基(- CHO ),结构简式为: $\mathrm { CH } _ { 3 } \mathrm { CHO }$ ,故 C 错误; D、最简式又叫实验式,它是表示分子中各元素原子数目的最简整数比的式子,苯的最简式为 CH,故 D 错误。

Question 17: 20.下列化学用语不正确的是() ![](/images/questions/chem-nomenclature/image-012.jpg)

20.下列化学用语不正确的是() ![](/images/questions/chem-nomenclature/image-012.jpg)

  • A. A. 苯的比例模型:
  • B. B. 丙烷的球棍模型 :
  • C. C. 中子数为 20 的 ${ } ^ { \mathrm { Cl } }$ 的核素:${ } ^ { 20 } \mathrm { Cl }$
  • D. D. 次氯酸的结构式: $\mathrm { H } - \mathrm { O } - \mathrm { Cl }$

Answer: C

Solution: A.苯为平面结构,苯分子中存在 6 个 H 和 6 个 C ,所有碳碳键完全相同,苯的比 例模型为 ![](/images/questions/chem-nomenclature/image-013.jpg) ,故 A 正确 ; B.用小球和小棍表示的模型为球棍模型,丙烷的结构简式为 $\mathrm { CH } _ { 3 } \mathrm { CH } _ { 2 } \mathrm { CH } _ { 3 }$ ,碳原子的原子半径大于氢原子,球棍模型为 <img class="imgSvg" id = "mi1mzfx7pg3ufw2jndp" src="data:image/svg+xml;base64,<svg id="smiles-mi1mzfx7pg3ufw2jndp" xmlns="http://www.w3.org/2000/svg" viewBox="0 0 220 85.02986591688266" style="width: 220.39899049303781px; height: 85.02986591688266px; overflow: visible;"><defs><linearGradient id="line-mi1mzfx7pg3ufw2jndp-1" gradientUnits="userSpaceOnUse" x1="151.11920087681455" y1="48.2798475519855" x2="178.39899049303781" y2="64.02986591688266"><stop stop-color="currentColor" offset="20%"></stop><stop stop-color="currentColor" offset="100%"></stop></linearGradient><linearGradient id="line-mi1mzfx7pg3ufw2jndp-3" gradientUnits="userSpaceOnUse" x1="135.36921924171884" y1="21.00003672980148" x2="151.11920087681455" y2="48.2798475519855"><stop stop-color="currentColor" offset="20%"></stop><stop stop-color="currentColor" offset="100%"></stop></linearGradient><linearGradient id="line-mi1mzfx7pg3ufw2jndp-5" gradientUnits="userSpaceOnUse" x1="151.11920087681455" y1="48.2798475519855" x2="166.8692192417117" y2="21.000057935762243"><stop stop-color="currentColor" offset="20%"></stop><stop stop-color="currentColor" offset="100%"></stop></linearGradient><linearGradient id="line-mi1mzfx7pg3ufw2jndp-7" gradientUnits="userSpaceOnUse" x1="123.83939005463051" y1="64.02982918708118" x2="151.11920087681455" y2="48.2798475519855"><stop stop-color="currentColor" offset="20%"></stop><stop stop-color="currentColor" offset="100%"></stop></linearGradient><linearGradient id="line-mi1mzfx7pg3ufw2jndp-9" gradientUnits="userSpaceOnUse" x1="96.55960043840727" y1="48.27981082218402" x2="123.83939005463051" y2="64.02982918708118"><stop stop-color="currentColor" offset="20%"></stop><stop stop-color="currentColor" offset="100%"></stop></linearGradient><linearGradient id="line-mi1mzfx7pg3ufw2jndp-11" gradientUnits="userSpaceOnUse" x1="80.80961880331157" y1="21" x2="96.55960043840727" y2="48.27981082218402"><stop stop-color="currentColor" offset="20%"></stop><stop stop-color="currentColor" offset="100%"></stop></linearGradient><linearGradient id="line-mi1mzfx7pg3ufw2jndp-13" gradientUnits="userSpaceOnUse" x1="96.55960043840727" y1="48.27981082218402" x2="112.30961880330443" y2="21.000021205960763"><stop stop-color="currentColor" offset="20%"></stop><stop stop-color="currentColor" offset="100%"></stop></linearGradient><linearGradient id="line-mi1mzfx7pg3ufw2jndp-15" gradientUnits="userSpaceOnUse" x1="69.27978961622325" y1="64.0297924572797" x2="96.55960043840727" y2="48.27981082218402"><stop stop-color="currentColor" offset="20%"></stop><stop stop-color="currentColor" offset="100%"></stop></linearGradient><linearGradient id="line-mi1mzfx7pg3ufw2jndp-17" gradientUnits="userSpaceOnUse" x1="42" y1="48.27977409238254" x2="69.27978961622325" y2="64.0297924572797"><stop stop-color="currentColor" offset="20%"></stop><stop stop-color="currentColor" offset="100%"></stop></linearGradient></defs><mask id="text-mask-mi1mzfx7pg3ufw2jndp"><rect x="0" y="0" width="100%" height="100%" fill="white"></rect><circle cx="178.39899049303781" cy="64.02986591688266" r="7.875" fill="black"></circle><circle cx="135.36921924171884" cy="21.00003672980148" r="7.875" fill="black"></circle><circle cx="166.8692192417117" cy="21.000057935762243" r="7.875" fill="black"></circle><circle cx="123.83939005463051" cy="64.02982918708118" r="7.875" fill="black"></circle><circle cx="96.55960043840727" cy="48.27981082218402" r="7.875" fill="black"></circle><circle cx="80.80961880331157" cy="21" r="7.875" fill="black"></circle><circle cx="112.30961880330443" cy="21.000021205960763" r="7.875" fill="black"></circle><circle cx="69.27978961622325" cy="64.0297924572797" r="7.875" fill="black"></circle><circle cx="42" cy="48.27977409238254" r="7.875" fill="black"></circle></mask><style>
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            "></text><text x="130.11921924171884" y="26.25003672980148" class="element-mi1mzfx7pg3ufw2jndp" fill="currentColor" style="text-anchor: start; writing-mode: horizontal-tb; text-orientation: mixed; letter-spacing: normal; direction: ltr;"><tspan>O</tspan><tspan style="unicode-bidi: plaintext;">H</tspan></text><text x="135.36921924171884" y="21.00003672980148" class="debug" fill="#ff0000" style="
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            "></text><text x="161.6192192417117" y="26.250057935762243" class="element-mi1mzfx7pg3ufw2jndp" fill="currentColor" style="text-anchor: start; writing-mode: horizontal-tb; text-orientation: mixed; letter-spacing: normal; direction: ltr;"><tspan>O</tspan><tspan style="unicode-bidi: plaintext;">H</tspan></text><text x="166.8692192417117" y="21.000057935762243" class="debug" fill="#ff0000" style="
                font: 5px Droid Sans, sans-serif;
            "></text><text x="123.83939005463051" y="56.15482918708118" class="element-mi1mzfx7pg3ufw2jndp" fill="currentColor" style="text-anchor: start; glyph-orientation-vertical: 0; writing-mode: vertical-rl; text-orientation: upright; letter-spacing: -1px; direction: ltr;"><tspan>O</tspan></text><text x="123.83939005463051" y="64.02982918708118" class="debug" fill="#ff0000" style="
                font: 5px Droid Sans, sans-serif;
            "></text><text x="96.55960043840727" y="40.40481082218402" class="element-mi1mzfx7pg3ufw2jndp" fill="currentColor" style="text-anchor: start; glyph-orientation-vertical: 0; writing-mode: vertical-rl; text-orientation: upright; letter-spacing: -1px; direction: ltr;"><tspan>P</tspan><tspan style="unicode-bidi: plaintext;">H</tspan></text><text x="96.55960043840727" y="48.27981082218402" class="debug" fill="#ff0000" style="
                font: 5px Droid Sans, sans-serif;
            "></text><text x="75.55961880331157" y="26.25" class="element-mi1mzfx7pg3ufw2jndp" fill="currentColor" style="text-anchor: start; writing-mode: horizontal-tb; text-orientation: mixed; letter-spacing: normal; direction: ltr;"><tspan>O</tspan><tspan style="unicode-bidi: plaintext;">H</tspan></text><text x="80.80961880331157" y="21" class="debug" fill="#ff0000" style="
                font: 5px Droid Sans, sans-serif;
            "></text><text x="107.05961880330443" y="26.250021205960763" class="element-mi1mzfx7pg3ufw2jndp" fill="currentColor" style="text-anchor: start; writing-mode: horizontal-tb; text-orientation: mixed; letter-spacing: normal; direction: ltr;"><tspan>O</tspan><tspan style="unicode-bidi: plaintext;">H</tspan></text><text x="112.30961880330443" y="21.000021205960763" class="debug" fill="#ff0000" style="
                font: 5px Droid Sans, sans-serif;
            "></text><text x="69.27978961622325" y="56.1547924572797" class="element-mi1mzfx7pg3ufw2jndp" fill="currentColor" style="text-anchor: start; glyph-orientation-vertical: 0; writing-mode: vertical-rl; text-orientation: upright; letter-spacing: -1px; direction: ltr;"><tspan>O</tspan></text><text x="69.27978961622325" y="64.0297924572797" class="debug" fill="#ff0000" style="
                font: 5px Droid Sans, sans-serif;
            "></text><text x="47.25" y="53.52977409238254" class="element-mi1mzfx7pg3ufw2jndp" fill="currentColor" style="text-anchor: start; writing-mode: horizontal-tb; text-orientation: mixed; letter-spacing: normal; direction: rtl; unicode-bidi: bidi-override;"><tspan>O</tspan><tspan style="unicode-bidi: plaintext;">H</tspan></text><text x="42" y="48.27977409238254" class="debug" fill="#ff0000" style="
                font: 5px Droid Sans, sans-serif;
            "></text></g></svg>"/> 故B正确; C.中子数为 20 的 ${ } ^ { \mathrm { Cl } }$ 的质量数 $= 20 + 17 = 37$ ,该核素可以表示为 ${ } ^ { 37 } \mathrm { Cl }$ ,故 C 错误; D.次氯酸属于共价化合物,中心原子为 O 原子,结构式为 $\mathrm { H } - \mathrm { O } - \mathrm { Cl }$ ,故 D 正确;故选C。

Question 18: 21.下列化学用语使用正确的是() $H : O ̈ : : O ̈ : H$

21.下列化学用语使用正确的是() $H : O ̈ : : O ̈ : H$

  • A. A. $\mathrm { SiO } _ { 2 }$ 的结构式: $\mathrm { O } - \mathrm { Si } = \mathrm { O }$
  • B. B. $\mathrm { H } _ { 2 } \mathrm { O } _ { 2 }$ 的电子式:
  • C. C. $\mathrm { BaSO } _ { 4 }$ 的电离方程式: $\mathrm { BaSO } _ { 4 } = { } ^ { \mathrm { SO } _ { 4 } ^ { 2 - } } + \mathrm { Ba } ^ { 2 + }$
  • D. D. ${ } ^ { 12 } \mathrm { C }$ 与 ${ } ^ { 14 } \mathrm { C }$ 互为同素异形体

Answer: C

Solution: A. $\mathrm { SiO } _ { 2 }$ 是共价晶体,在该晶体中每个 Si 原子与 4 个 O 原子形成 4 个 $\mathrm { Si } - \mathrm { O }$ 键, $\mathrm { Si } -$ O 键构成的是正四面体结构,每个 O 原子与 2 个 Si 原子形成 $\mathrm { Si } - \mathrm { O }$ 单键, A 错误; B. $\mathrm { H } _ { 2 } \mathrm { O } _ { 2 }$ 的分子中, 2 个 O 原子形成 $\mathrm { O } - \mathrm { O }$ 键,每个 O 原子再分别与 H 原子形成 1 个 $\mathrm { H } - \mathrm { O }$ 键, 使分子中各个原子都达到最外层 2 个或 8 个电子的稳定结构,其电子式为 $\mathrm { H } \% { } ^ { \circ } { } _ { \circ } ^ { \circ } \times { } _ { \times } ^ { \times \times } \times \mathrm { H }$ , B 错误 ; C. $\mathrm { BaSO } _ { 4 }$ 难溶于水,但溶于水的部分完全电离产生自由移动的 $\mathrm { Ba } ^ { 2 + } 、 \mathrm { SO } _ { 4 } ^ { 2 - }$ ,故其电离方程式为 $\mathrm { BaSO } _ { 4 } = \mathrm { SO } _ { 4 } ^ { 2 - } + \mathrm { Ba } ^ { 2 + }$ ,C正确; D.${ } ^ { 12 } \mathrm { C }$ 与 ${ } ^ { 14 } \mathrm { C }$ 的质子数都是 6 ,中子数分别是 $6 、 8$ ,可见二者质子数相同而中子数不同, 因此二者互为同位素,D 错误 ; 故答案是 C 。

Question 19: 22. $\mathrm { H } _ { 2 } \mathrm {~S} 、 \mathrm { CH } _ { 4 }$ 热解重整制 $\mathrm { H } _ { 2 }$ 过程中的...

22. $\mathrm { H } _ { 2 } \mathrm {~S} 、 \mathrm { CH } _ { 4 }$ 热解重整制 $\mathrm { H } _ { 2 }$ 过程中的主要反应为 $2 \mathrm { H } _ { 2 } \mathrm {~S} = 2 \mathrm { H } _ { 2 } + \mathrm { S } _ { 2 } 、 2 \mathrm { H } _ { 2 } \mathrm {~S} + \mathrm { CH } _ { 4 } = \mathrm { CS } _ { 2 } + 4 \mathrm { H } _ { 2 }$ 。下列有关说法正确的是( ) ![](/images/questions/chem-nomenclature/image-014.jpg)

  • A. A. $\mathrm { CH } _ { 4 }$ 分子的球棍模型 :
  • B. B. $\mathrm { S } _ { 2 }$ 与 $\mathrm { S } _ { 8 }$ 互为同系物
  • C. C. $\mathrm { CS } _ { 2 }$ 分子呈角形
  • D. D. 中子数为 16 的硫原子:${ } ^ { 32 } \mathrm {~S}$

Answer: D

Solution: $\mathrm { A } . \mathrm { CH } _ { 4 }$ 分子的球棍模型是 $\bigcirc$ , B. $\mathrm { S } _ { 2 }$ 与 $\mathrm { S } _ { 8 }$ 是硫的两种不同单质,互为同素异形体,B 错误; C. $\mathrm { CS } _ { 2 }$ 的结构与 $\mathrm { CO } _ { 2 }$ 类似,都是直线形分子,C错误; D.S 质子数为 16 ,若中子数为 16 ,则质量数为 32 ,D 正确; 故答案为:D。

Question 20: 23.下列关于乙醇的说法正确的是() ![](/images/questions/chem-nomenclature/image-015.jpg)

23.下列关于乙醇的说法正确的是() ![](/images/questions/chem-nomenclature/image-015.jpg)

  • A. A. 分子的球棍模型为 :
  • B. B. 常温下为无色无味的液体
  • C. C. 与乙酸互为同分异构体
  • D. D. 能使紫色的石蕊试液变红

Answer: A

Solution: A.乙醇结构简式为 ![](/images/questions/chem-nomenclature/image-016.jpg) ,A 正确 ; B.乙醇常温下为无色有特殊香味的液体,B错误; C.乙醇分子式为 $\mathrm { C } _ { 2 } \mathrm { H } _ { 5 } \mathrm { OH }$ ,乙酸分子式为 $\mathrm { CH } _ { 3 } \mathrm { COOH }$ ,两者分子式不同,不互为同分异构体,C错误; D.乙醇显中性,不能使紫色石蕊溶液变红,D 错误;

Question 21: 25.下列有关化学用语正确的是 ![](/images/questions/chem-nomenclature/image-017.jpg) <img class="imgSvg" id = "m...

25.下列有关化学用语正确的是 ![](/images/questions/chem-nomenclature/image-017.jpg) <img class="imgSvg" id = "mi1mzfvx68krowfpmi" src="data:image/svg+xml;base64,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"/> ![](/images/questions/chem-nomenclature/image-018.jpg)

  • A. A. 氯离子的结构示意图:
  • B. B. 醛基(- CHO )的电子式:
  • C. C. $\mathrm { CH } _ { 4 }$ 的球棍模型:
  • D. D. 乙烯分子的结构式: $\mathrm { CH } _ { 2 } = \mathrm { CH } _ { 2 }$

Answer: B

Solution: A.氯是 17 号元素,氯离子的结构示意图为: ![](/images/questions/chem-nomenclature/image-019.jpg) B.醛基中碳与氧原子间形成碳氧双键,故电子式为: ![](/images/questions/chem-nomenclature/image-020.jpg) C. ![](/images/questions/chem-nomenclature/image-021.jpg) 是甲烷的比例模型,甲烷的球棍模型为 <img class="imgSvg" id = "mi1mzfxapvxj28fwncb" src="data:image/svg+xml;base64,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"/> ,C 错误 ; D.乙烯的结构式,应该用短线表示出所有的共用电子对,为 <img class="imgSvg" id = "mi1mzfxb1cgeu0cockni" src="data:image/svg+xml;base64,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"/> 答案选B。

Question 22: 26.下列化学用语表达正确的是

26.下列化学用语表达正确的是

  • A. A. 胆矾的化学式: $\mathrm { CuSO } _ { 4 }$
  • B. B. 气体的摩尔体积为 $22.4 \mathrm {~L} / \mathrm { mol }$
  • C. C. Ti :中子数为 26
  • D. D. 钠离子的结构示意图 :

Answer: C

Solution: A.胆矾为硫酸铜晶体,化学式为 $\mathrm { CuSO } _ { 4 } \cdot 5 \mathrm { H } _ { 2 } \mathrm { O }$ ,故 A 错误; B.标准状况下气体的摩尔体积约为 $22.4 \mathrm {~L} / \mathrm { mol }$ ,状况未知,不一定为 $22.4 \mathrm {~L} / \mathrm { mol }$ ,故 B 错误; C.质子数 + 中子数 $=$ 质量数,则中子数为 $48 - 22 = 26$ ,故 C 正确; D.钠离子的质子数为 11 ,核外电子数为 10 ,其离子结构示意图为(+11) 28 /,故 D 错误;

Question 23: 27.下列化学用语表示正确的是 ![](/images/questions/chem-nomenclature/image-022.jpg)

27.下列化学用语表示正确的是 ![](/images/questions/chem-nomenclature/image-022.jpg)

  • A. A. 乙烯的结构简式: $\mathrm { CH } _ { 2 } \mathrm { CH } _ { 2 }$
  • B. B. 四氯化碳的电子式: $\mathrm { Cl } : \underset { \underset { \mathrm { Cl } } { \mathrm { Cl } } } { \stackrel { \mathrm { Cl } } { \mathrm { Cl } } } \mathrm { Cl }$
  • C. C. $\mathrm { CO } _ { 2 }$ 的比例模型 :
  • D. D. HClO 的结构式 : $\mathrm { H } - \mathrm { O } - \mathrm { Cl }$

Answer: D

Solution: A.乙烯中的官能团为碳碳双键,乙烯的结构简式为 $\mathrm { CH } _ { 2 } = \mathrm { CH } _ { 2 } , \mathrm {~A}$ 错误; B.漏写 Cl 原子上的孤电子对, $\mathrm { CCl } _ { 4 }$ 的电子式为 C.碳的原子半径大于氧的原子半径,C 错误; D. HClO 的结构式为 $\mathrm { H } - \mathrm { O } - \mathrm { Cl }$ ,D 正确; 答案选D。

Question 24: 28.氮及其化合物的转化过程如图所示。下列分析合理的是 ![](/images/questions/chem-nomenclature/image-023.jpg)

28.氮及其化合物的转化过程如图所示。下列分析合理的是 ![](/images/questions/chem-nomenclature/image-023.jpg)

  • A. A. 催化剂 a 作用下,${ } ^ { \mathrm { N } _ { 2 } }$ 和 ${ } ^ { \mathrm { H } _ { 2 } }$ 能100\%转化为 $\mathrm { NH } _ { 3 }$
  • B. B. 催化剂 a 通过降低 ${ } ^ { \mathrm { N } _ { 2 } }$ 的键能,加快了化学反应速率
  • C. C. 在催化剂 b 表面形成 $\mathrm { N } - \mathrm { O }$ 键时,存在元素化合价的变化
  • D. D. 两步反应都属于氮的固定

Answer: C

Solution: A.氮气与氢气的反应为可逆反应,反应物不能完全转化为生成物,则催化剂 a作用下,${ } ^ { \mathrm { N } _ { 2 } }$ 和 ${ } ^ { \mathrm { H } _ { 2 } }$ 不能 $100 \%$ 转化为 ${ } ^ { \mathrm { NH } _ { 3 } }$ , A 错误; B.催化剂a通过降低反应的活化能,进而加快反应速率,但不能降低物质的键能,即不能降低 ${ } ^ { \mathrm { N } _ { 2 } }$ 的键能,B 错误; C.在催化剂 b 表面形成氮氧键时, N 元素的化合价从 - 3 价变为 + 2 ,存在元素化合价的变化,C正确; D.氮的固定是指游离态的氮转化为氮的化合物的过程,则第 1 步反应属于氮的固定,第 2步反应不属于氮的固定,D 错误;

Question 25: 29.下列有关化学用语使用正确的是 ![](/images/questions/chem-nomenclature/image-024.jpg) 根据下列实验信息,完成下面小题: 用下图装置...

29.下列有关化学用语使用正确的是 ![](/images/questions/chem-nomenclature/image-024.jpg) 根据下列实验信息,完成下面小题: 用下图装置进行实验验证浓硫酸与木炭在加热后得到的气体中含有 $\mathrm { SO } _ { 2 } 、 \mathrm { CO } _ { 2 }$ 和 $\mathrm { H } _ { 2 } \mathrm { O }$ 。实验过程中分别观察到无水硫酸铜变蓝、品红溶液褪色、酸性高锰酸钾溶液颜色变浅、澄清石灰水中出现白色浑浊。 ![](/images/questions/chem-nomenclature/image-025.jpg)

  • A. A. 纯碱的电离方程式: $\mathrm { NaHCO } _ { 3 } = \mathrm { Na } ^ { + } + \mathrm { HCO } ^ { 3 }$
  • B. B. 氯原子的结构示意图 :
  • C. C. $\mathrm { H } _ { 2 } \mathrm {~S}$ 的结构式: $\mathrm { H } - \mathrm { S } - \mathrm { H }$
  • D. D. 过氧化氢的电子式: $\mathrm { H } ^ { + } \left( : \ddot { \mathrm { O } } : \ddot { \mathrm { O } } ^ { : } \right) ^ { 2 - } \mathrm { H } ^ { + }$

Answer: C

Solution: A.纯碱是碳酸钠,电离方程式为: $\mathrm { Na } _ { 2 } \mathrm { CO } _ { 3 } = 2 \mathrm { Na } ^ { + } + \mathrm { CO } ^ { 3 - }$ ,故 A 错误; B.氯质子数为 17 ,原子结构示意图为:(+17) 287 /故 B 错误; C. $\mathrm { H } _ { 2 } \mathrm {~S}$ 中 S 与两个 H 以单键相连,结构式为: $\mathrm { H } - \mathrm { S } - \mathrm { H }$ ,故 C 正确; D.过氧化氢为共价化合物,电子式为: $\mathrm { H } : \ddot { \mathrm { O } } : \ddot { \mathrm { O } } : \mathrm { H }$ ,故 D 错误;

Question 26: 30.下列化学用语表示正确的是 $\mathrm { S } ^ { 2 - }$ ![](/images/questions/chem-nomenclature/image-026.jpg) ...

30.下列化学用语表示正确的是 $\mathrm { S } ^ { 2 - }$ ![](/images/questions/chem-nomenclature/image-026.jpg) ${ } _ { 6 } ^ { 8 } \mathrm { C }$

  • A. A. $\mathrm { H } _ { 2 } \mathrm { O }$ 的电子式为 $\mathrm { H } : \mathrm { O } : \mathrm { H }$
  • B. B. $\mathrm { H } _ { 2 } \mathrm { SO } _ { 4 }$ 的摩尔质量为 $98 \mathrm {~g} \cdot \mathrm {~mol} ^ { - 1 }$
  • C. C. 的结构示意图为 +
  • D. D. 中子数为 8 的碳原子可表示为

Answer: B

Solution:

Question 27: 31.下列有关说法不正确的是

31.下列有关说法不正确的是

  • A. A. $\mathrm { H } _ { 2 } \mathrm { SO } _ { 4 }$ 中只存在共价键
  • B. B. 用光照射 $\mathrm { KMnO } _ { 4 }$ 溶液会产生光路
  • C. C. $\mathrm { SO } _ { 2 }$ 属于酸性氧化物
  • D. D. 澄清石灰水变浑浊过程中分散质粒子变大

Answer: B

Solution:

Question 28: 32 .下列有关实验现象分析不正确的是 明气体中有 $\mathrm { CO } _ { 2 }$

32 .下列有关实验现象分析不正确的是 明气体中有 $\mathrm { CO } _ { 2 }$

  • A. A. 无水硫酸铜变蓝证明气体中有 $\mathrm { H } _ { 2 } \mathrm { O } ( \mathrm { g } )$
  • B. B. 品红溶液褪色证明气体中有 $\mathrm { SO } _ { 2 }$
  • C. C. 酸性高锰酸钾溶液颜色变浅证明 $\mathrm { SO } _ { 2 }$ 有漂白性
  • D. D. 澄清石灰水中出现白色浑浊证

Answer: C

Solution:

Question 29: 33.下列有关反应表示正确的是

33.下列有关反应表示正确的是

  • A. A. 木炭与浓硫酸反应: $2 \mathrm { H } _ { 2 } \mathrm { SO } _ { 4 } ($ 浓 $) + \mathrm { C } \triangleq 2 \mathrm { SO } _ { 2 } \uparrow + \mathrm { CO } _ { 2 } \uparrow + 2 \mathrm { H } _ { 2 } \mathrm { O }$
  • B. B. 二氧化硫溶于水: $\mathrm { SO } _ { 2 } + \mathrm { H } _ { 2 } \mathrm { O } \rightleftharpoons \mathrm { H } _ { 2 } \mathrm { SO } _ { 4 }$
  • C. C. 酸性高锰酸钾溶液颜色变浅: $2 \mathrm { MnO } _ { 4 } ^ { - } + 5 \mathrm { SO } _ { 2 } + 4 \mathrm { OH } ^ { - } = 2 \mathrm { Mn } ^ { 2 + } + 5 \mathrm { SO } _ { 4 } ^ { 2 - } + 2 \mathrm { H } _ { 2 } \mathrm { O }$
  • D. D. 澄清石灰水中出现白色浑浊 : $2 \mathrm { OH } ^ { - } + \mathrm { CO } _ { 2 } = \mathrm { CO } _ { 3 } ^ { 2 - } + \mathrm { H } _ { 2 } \mathrm { O }$

Answer: A

Solution:

Question 30: 34.下列化学用语表述错误的是 $$ \mathrm { CH } _ { 2 } = \mathrm { CH } _ { 2 } $$ $\mathrm { Cl } ^ { - }$

34.下列化学用语表述错误的是 $$ \mathrm { CH } _ { 2 } = \mathrm { CH } _ { 2 } $$ $\mathrm { Cl } ^ { - }$

  • A. A. 乙烯的结构简式
  • B. B. 的结构示意图 :+17) 288
  • C. C. 乙炔分子中的共价键由 3 个 $\sigma$ 键和 2 个 $\pi$ 键组成
  • D. D. $\mathrm { CO } _ { 2 }$ 的电子式:$\because \cdots \cdots 0$ .

Answer: D

Solution: A.碳碳双键不能省略,乙烯的结构简式为: $\mathrm { CH } _ { 2 } = \mathrm { CH } _ { 2 }$ ,故 A 正确; B.已知 Cl 是 17 号元素,氯离子核外有 18 个电子,故氯离子的结构示意图正确,B正确; C.乙炔分子的结构式为 $\mathrm { H } - \mathrm { C } \equiv \mathrm { C } - \mathrm { H }$ ,故其共价键由 3 个 $\sigma$ 键和 2 个 $\pi$ 键组成,故 C 正确; D. $\mathrm { CO } _ { 2 }$ 的电子式为:$\because \therefore \mathrm { C } \because \because$ ,故 D 错误;

Question 31: 35.下列化学用语或图示表达正确的是 ## $\stackrel { \mathrm { O } } { : }$ <br> A.醛基的电子式:$\because \dot { \mathrm { ...

35.下列化学用语或图示表达正确的是 ## $\stackrel { \mathrm { O } } { : }$ <br> A.醛基的电子式:$\because \dot { \mathrm { C } } : \mathrm { H }$ <img class="imgSvg" id = "mi1mzfw0h1vqo48lf3f" src="data:image/svg+xml;base64,PHN2ZyBpZD0ic21pbGVzLW1pMW16ZncwaDF2cW80OGxmM2YiIHhtbG5zPSJodHRwOi8vd3d3LnczLm9yZy8yMDAwL3N2ZyIgdmlld0JveD0iMCAwIDE3OCA0Mi4wMDAwNDI0MTE5MjE1NCIgc3R5bGU9IndpZHRoOiAxNzguNDk5OTk5OTk5OTkwNDhweDsgaGVpZ2h0OiA0Mi4wMDAwNDI0MTE5MjE1NHB4OyBvdmVyZmxvdzogdmlzaWJsZTsiPjxkZWZzPjxsaW5lYXJHcmFkaWVudCBpZD0ibGluZS1taTFtemZ3MGgxdnFvNDhsZjNmLTEiIGdyYWRpZW50VW5pdHM9InVzZXJTcGFjZU9uVXNlIiB4MT0iMTA0Ljk5OTk5OTk5OTk5MzY1IiB5MT0iMjEuMDAwMDI4Mjc0NjE0MzY1IiB4Mj0iMTM2LjQ5OTk5OTk5OTk5MDQ4IiB5Mj0iMjEuMDAwMDQyNDExOTIxNTQiPjxzdG9wIHN0b3AtY29sb3I9ImN1cnJlbnRDb2xvciIgb2Zmc2V0PSIyMCUiPjwvc3RvcD48c3RvcCBzdG9wLWNvbG9yPSJjdXJyZW50Q29sb3IiIG9mZnNldD0iMTAwJSI+PC9zdG9wPjwvbGluZWFyR3JhZGllbnQ+PGxpbmVhckdyYWRpZW50IGlkPSJsaW5lLW1pMW16ZncwaDF2cW80OGxmM2YtMyIgZ3JhZGllbnRVbml0cz0idXNlclNwYWNlT25Vc2UiIHgxPSI3My41MDAwMDE2OTY0NzM2OSIgeTE9IjE3LjIyMDAxNDEzNzMwNzU1OCIgeDI9IjEwNS4wMDAwMDE2OTY0NzA1MiIgeTI9IjE3LjIyMDAyODI3NDYxNDc0OCI+PHN0b3Agc3RvcC1jb2xvcj0iY3VycmVudENvbG9yIiBvZmZzZXQ9IjIwJSI+PC9zdG9wPjxzdG9wIHN0b3AtY29sb3I9ImN1cnJlbnRDb2xvciIgb2Zmc2V0PSIxMDAlIj48L3N0b3A+PC9saW5lYXJHcmFkaWVudD48bGluZWFyR3JhZGllbnQgaWQ9ImxpbmUtbWkxbXpmdzBoMXZxbzQ4bGYzZi01IiBncmFkaWVudFVuaXRzPSJ1c2VyU3BhY2VPblVzZSIgeDE9IjczLjQ5OTk5ODMwMzUxOTk2IiB5MT0iMjQuNzgwMDE0MTM3MzA2NzkzIiB4Mj0iMTA0Ljk5OTk5ODMwMzUxNjc4IiB5Mj0iMjQuNzgwMDI4Mjc0NjEzOTgzIj48c3RvcCBzdG9wLWNvbG9yPSJjdXJyZW50Q29sb3IiIG9mZnNldD0iMjAlIj48L3N0b3A+PHN0b3Agc3RvcC1jb2xvcj0iY3VycmVudENvbG9yIiBvZmZzZXQ9IjEwMCUiPjwvc3RvcD48L2xpbmVhckdyYWRpZW50PjxsaW5lYXJHcmFkaWVudCBpZD0ibGluZS1taTFtemZ3MGgxdnFvNDhsZjNmLTciIGdyYWRpZW50VW5pdHM9InVzZXJTcGFjZU9uVXNlIiB4MT0iNzMuNDk5OTk5OTk5OTk2ODIiIHkxPSIyMS4wMDAwMTQxMzczMDcxNzYiIHgyPSIxMDQuOTk5OTk5OTk5OTkzNjUiIHkyPSIyMS4wMDAwMjgyNzQ2MTQzNjUiPjxzdG9wIHN0b3AtY29sb3I9ImN1cnJlbnRDb2xvciIgb2Zmc2V0PSIyMCUiPjwvc3RvcD48c3RvcCBzdG9wLWNvbG9yPSJjdXJyZW50Q29sb3IiIG9mZnNldD0iMTAwJSI+PC9zdG9wPjwvbGluZWFyR3JhZGllbnQ+PGxpbmVhckdyYWRpZW50IGlkPSJsaW5lLW1pMW16ZncwaDF2cW80OGxmM2YtOSIgZ3JhZGllbnRVbml0cz0idXNlclNwYWNlT25Vc2UiIHgxPSI0MiIgeTE9IjIxIiB4Mj0iNzMuNDk5OTk5OTk5OTk2ODIiIHkyPSIyMS4wMDAwMTQxMzczMDcxNzYiPjxzdG9wIHN0b3AtY29sb3I9ImN1cnJlbnRDb2xvciIgb2Zmc2V0PSIyMCUiPjwvc3RvcD48c3RvcCBzdG9wLWNvbG9yPSJjdXJyZW50Q29sb3IiIG9mZnNldD0iMTAwJSI+PC9zdG9wPjwvbGluZWFyR3JhZGllbnQ+PC9kZWZzPjxtYXNrIGlkPSJ0ZXh0LW1hc2stbWkxbXpmdzBoMXZxbzQ4bGYzZiI+PHJlY3QgeD0iMCIgeT0iMCIgd2lkdGg9IjEwMCUiIGhlaWdodD0iMTAwJSIgZmlsbD0id2hpdGUiPjwvcmVjdD48L21hc2s+PHN0eWxlPgogICAgICAgICAgICAgICAgLmVsZW1lbnQtbWkxbXpmdzBoMXZxbzQ4bGYzZiB7CiAgICAgICAgICAgICAgICAgICAgZm9udDogMTRweCBIZWx2ZXRpY2EsIEFyaWFsLCBzYW5zLXNlcmlmOwogICAgICAgICAgICAgICAgICAgIGFsaWdubWVudC1iYXNlbGluZTogJ21pZGRsZSc7CiAgICAgICAgICAgICAgICB9CiAgICAgICAgICAgICAgICAuc3ViLW1pMW16ZncwaDF2cW80OGxmM2YgewogICAgICAgICAgICAgICAgICAgIGZvbnQ6IDguNHB4IEhlbHZldGljYSwgQXJpYWwsIHNhbnMtc2VyaWY7CiAgICAgICAgICAgICAgICB9CiAgICAgICAgICAgIDwvc3R5bGU+PGcgbWFzaz0idXJsKCN0ZXh0LW1hc2stbWkxbXpmdzBoMXZxbzQ4bGYzZikiPjxsaW5lIHgxPSIxMDQuOTk5OTk5OTk5OTkzNjUiIHkxPSIyMS4wMDAwMjgyNzQ2MTQzNjUiIHgyPSIxMzYuNDk5OTk5OTk5OTkwNDgiIHkyPSIyMS4wMDAwNDI0MTE5MjE1NCIgc3R5bGU9InN0cm9rZS1saW5lY2FwOnJvdW5kO3N0cm9rZS1kYXNoYXJyYXk6bm9uZTtzdHJva2Utd2lkdGg6MS4yNiIgc3Ryb2tlPSJ1cmwoJyNsaW5lLW1pMW16ZncwaDF2cW80OGxmM2YtMScpIj48L2xpbmU+PGxpbmUgeDE9IjczLjUwMDAwMTY5NjQ3MzY5IiB5MT0iMTcuMjIwMDE0MTM3MzA3NTU4IiB4Mj0iMTA1LjAwMDAwMTY5NjQ3MDUyIiB5Mj0iMTcuMjIwMDI4Mjc0NjE0NzQ4IiBzdHlsZT0ic3Ryb2tlLWxpbmVjYXA6cm91bmQ7c3Ryb2tlLWRhc2hhcnJheTpub25lO3N0cm9rZS13aWR0aDoxLjI2IiBzdHJva2U9InVybCgnI2xpbmUtbWkxbXpmdzBoMXZxbzQ4bGYzZi0zJykiPjwvbGluZT48bGluZSB4MT0iNzMuNDk5OTk4MzAzNTE5OTYiIHkxPSIyNC43ODAwMTQxMzczMDY3OTMiIHgyPSIxMDQuOTk5OTk4MzAzNTE2NzgiIHkyPSIyNC43ODAwMjgyNzQ2MTM5ODMiIHN0eWxlPSJzdHJva2UtbGluZWNhcDpyb3VuZDtzdHJva2UtZGFzaGFycmF5Om5vbmU7c3Ryb2tlLXdpZHRoOjEuMjYiIHN0cm9rZT0idXJsKCcjbGluZS1taTFtemZ3MGgxdnFvNDhsZjNmLTUnKSI+PC9saW5lPjxsaW5lIHgxPSI3My40OTk5OTk5OTk5OTY4MiIgeTE9IjIxLjAwMDAxNDEzNzMwNzE3NiIgeDI9IjEwNC45OTk5OTk5OTk5OTM2NSIgeTI9IjIxLjAwMDAyODI3NDYxNDM2NSIgc3R5bGU9InN0cm9rZS1saW5lY2FwOnJvdW5kO3N0cm9rZS1kYXNoYXJyYXk6bm9uZTtzdHJva2Utd2lkdGg6MS4yNiIgc3Ryb2tlPSJ1cmwoJyNsaW5lLW1pMW16ZncwaDF2cW80OGxmM2YtNycpIj48L2xpbmU+PGxpbmUgeDE9IjQyIiB5MT0iMjEiIHgyPSI3My40OTk5OTk5OTk5OTY4MiIgeTI9IjIxLjAwMDAxNDEzNzMwNzE3NiIgc3R5bGU9InN0cm9rZS1saW5lY2FwOnJvdW5kO3N0cm9rZS1kYXNoYXJyYXk6bm9uZTtzdHJva2Utd2lkdGg6MS4yNiIgc3Ryb2tlPSJ1cmwoJyNsaW5lLW1pMW16ZncwaDF2cW80OGxmM2YtOScpIj48L2xpbmU+PC9nPjxnPjx0ZXh0IHg9IjEzNi40OTk5OTk5OTk5OTA0OCIgeT0iMjEuMDAwMDQyNDExOTIxNTQiIGNsYXNzPSJkZWJ1ZyIgZmlsbD0iI2ZmMDAwMCIgc3R5bGU9IgogICAgICAgICAgICAgICAgZm9udDogNXB4IERyb2lkIFNhbnMsIHNhbnMtc2VyaWY7CiAgICAgICAgICAgICI+PC90ZXh0Pjx0ZXh0IHg9IjEwNC45OTk5OTk5OTk5OTM2NSIgeT0iMjEuMDAwMDI4Mjc0NjE0MzY1IiBjbGFzcz0iZGVidWciIGZpbGw9IiNmZjAwMDAiIHN0eWxlPSIKICAgICAgICAgICAgICAgIGZvbnQ6IDVweCBEcm9pZCBTYW5zLCBzYW5zLXNlcmlmOwogICAgICAgICAgICAiPjwvdGV4dD48dGV4dCB4PSI3My40OTk5OTk5OTk5OTY4MiIgeT0iMjEuMDAwMDE0MTM3MzA3MTc2IiBjbGFzcz0iZGVidWciIGZpbGw9IiNmZjAwMDAiIHN0eWxlPSIKICAgICAgICAgICAgICAgIGZvbnQ6IDVweCBEcm9pZCBTYW5zLCBzYW5zLXNlcmlmOwogICAgICAgICAgICAiPjwvdGV4dD48dGV4dCB4PSI0MiIgeT0iMjEiIGNsYXNzPSJkZ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![](/images/questions/chem-nomenclature/image-027.jpg) ![](/images/questions/chem-nomenclature/image-028.jpg)

  • A. A. $\stackrel { \mathrm { O } } { : }$ <br> A.醛基的电子式:$\because \dot { \mathrm { C } } : \mathrm { H }$
  • B. B. 2-丁炔的键线式:
  • C. C. 顺-2-丁烯的球棍模型:
  • D. D. 溴乙烷的空间填充模型:

Answer: D

Solution: A.醛基的电子式为 :$\stackrel { : \mathrm { O } : } { : \stackrel { : } { \mathrm { C } } : \mathrm { H } }$ ,故 A 错误 ; B.2-丁炔分子中 4 个碳原子共线,键线式为:故 B 错误; C.顺-2-丁烯的两个甲基在同一侧,球棍模型为: ![](/images/questions/chem-nomenclature/image-029.jpg) ,故 C 错误; D.溴乙烷中溴原子半径最大,空间填充模型为: ![](/images/questions/chem-nomenclature/image-030.jpg) ,故 D 正确; 答案选D。

Question 32: 36.2019年,我国青年化学家雷晓光被遴选为"青年化学家元素周期表"氮元素的代言人。下列与氮元素有关的说法正确的是

36.2019年,我国青年化学家雷晓光被遴选为"青年化学家元素周期表"氮元素的代言人。下列与氮元素有关的说法正确的是

  • A. A. ${ } ^ { 14 } \mathrm {~N}$ 与 ${ } ^ { 14 } \mathrm { C } _ { \text {互为同位素 } }$
  • B. B. $\mathrm { Si } _ { 3 } \mathrm {~N} _ { 4 }$ 中 N 为 ${ } ^ { + 3 }$ 价
  • C. C. $\mathrm { NH } _ { 3 }$ 的热稳定性比 HF 的强
  • D. D. $\mathrm { N } _ { 2 }$ 的电子式为: $\mathrm { N } : : \mathrm { N }$ :

Answer: D

Solution: A.同一元素的不同核素互为同位素,${ } ^ { 14 } \mathrm {~N}$ 与 ${ } ^ { 14 } \mathrm { C }$ 是不同元素的不同核素,不是同 位素,A 错误; B.根据化学式书写原则及非金属性强弱可知, $\mathrm { Si } _ { 3 } \mathrm {~N} _ { 4 }$ 中 N 为 ${ } ^ { - 3 }$ 价,B 错误; C.元素的非金属性越强,对应的氢化物的热稳定性越强,氮的非金属性小于氟,故 $\mathrm { NH } _ { 3 }$的热稳定性比 HF 的弱,C 错误; D.氮气形成氮氮三键,其电子式为: $\mathrm { N } : : \mathrm { N } :$ ,D正确;

Question 33: 37 .下列表示正确的是 ![](/images/questions/chem-nomenclature/image-031.jpg)

37 .下列表示正确的是 ![](/images/questions/chem-nomenclature/image-031.jpg)

  • A. A. ${ } ^ { 14 } \mathrm {~N} _ { 2 }$ 与 ${ } ^ { 15 } \mathrm {~N} _ { 2 }$ 互为同位素
  • B. B. 正丁烷的球棍模型:
  • C. C. NaClO 的电子式: $\mathrm { Na } : \ddot { \mathrm { O } } : \ddot { \mathrm { C } } \mathrm { l } :$
  • D. D. $\mathrm { NaHCO } _ { 3 }$ 水解的离子方程式: $\mathrm { HCO } ^ { 3 } + \mathrm { H } _ { 2 } \mathrm { O } ^ { \hat { \ddagger } } + \mathrm { H } _ { 3 } \mathrm { O } ^ { + } + \mathrm { CO } ^ { 3 - }$

Answer: B

Solution: A.${ } ^ { 14 } \mathrm {~N} _ { 2 }$ 与 ${ } ^ { 15 } \mathrm {~N} _ { 2 }$ 均表示分子,不是原子,不互为同位素,故 A 错误; B.正丁烷分子中含有 2 个甲基和 2 个亚甲基,其球棍模型为 ![](/images/questions/chem-nomenclature/image-032.jpg) ,故 B ,故 B ,故 B 正确; C. NaClO 是离子化合物,由 $\mathrm { Na } ^ { + }$离子和 $\mathrm { ClO } ^ { - }$离子构成, NaClO 的电子式为 $\mathrm { Na } + [ \ddot { \mathrm { O } } : \ddot { \mathrm { C } } \mathrm { l } : ] ^ { - }$,故 C 错误 ; D. $\mathrm { NaHCO } _ { 3 }$ 水解的离子方程式为 $\mathrm { HCO } ^ { 3 } + \mathrm { H } _ { 2 } \mathrm { O } \rightleftharpoons \mathrm { H } _ { 2 } \mathrm { CO } _ { 3 } + \mathrm { OH } ^ { - }$,故 D 错误;

Question 34: 38 .下列物质的电子式书写正确的是 $[ \mathrm { H } : \ddot { O } : ] _ { 2 }$

38 .下列物质的电子式书写正确的是 $[ \mathrm { H } : \ddot { O } : ] _ { 2 }$

  • A. A. $\mathrm { HCl } \quad \mathrm { H } ^ { + } [ : \ddot { C l } : ] ^ { - }$
  • B. B. $\mathrm { HClO } \quad \mathrm { H } : \ddot { \mathrm { Cl } } : \ddot { \mathrm { O } }$ :
  • C. C. $\mathrm { H } _ { 2 } \mathrm { O } _ { 2 }$
  • D. D. $\mathrm { Na } _ { 2 } \mathrm { O } _ { 2 } \mathrm { Na } ^ { + } [ : O : O : ] ^ { 2 - } \mathrm { Na } ^ { + }$

Answer: D

Solution: A. HCl 是共价化合物,其电子式为 $\mathrm { H } \dot { \times } \dot { \mathrm { Cl } } \dot { \cdot }$ ,故 A 错误;B.HClO 的电子 式为 $\left. H \cdot \dot { \sim } _ { \cdot } ^ { \cdot } \dot { C ^ { \prime } } \right] _ { \cdot } ^ { \cdot }$ ,故 B 错误 ;C . $\mathrm { H } _ { 2 } \mathrm { O } _ { 2 }$ 的电子式为 ${ } _ { \mathrm { H } : \dddot { \mathrm { o } } _ { \cdot } : \ddot { \mathrm { o } } _ { \cdot \mathrm { H } } }$ ,故 C 错误;D. $\mathrm { Na } _ { 2 } \mathrm { O } _ { 2 }$ 是离子化合物,其电子式为 $\mathrm { Na } ^ { + } \left[ \begin{array} { l l l } \because & 0 & 0 \end{array} \right] ^ { 2 - } \mathrm { Na } ^ { + }$,故 D 正确;答案为 D。 点睛 :解决这类问题过程中需要重点关注的有:(1)书写电子式时应特别注意如下几个方面: 阴离子及多核阳离子均要加"[ ]"并注明电荷,书写共价化合物电子式时,不得使用"[]",没有成键的价电子也要写出来。(2)书写结构式、结构简式时首先要明确原子间结合顺序(如 HClO 应是 $\mathrm { H } - \mathrm { O } - \mathrm { Cl }$ ,而不是 $\mathrm { H } - \mathrm { Cl } - \mathrm { O }$ ),其次是书写结构简式时,碳碳双键、碳碳三键应该写出来。(3)比例模型、球棍模型要能体现原子的相对大小及分子的空间结构。

Question 35: 41.下列化学用语表述正确的是( ) ᄃ. HCl 的电子式: $\mathrm { H } ^ { + } [ : \ddot { \mathrm { C } } 1 : ] ^ { - }$ ...

41.下列化学用语表述正确的是( ) ᄃ. HCl 的电子式: $\mathrm { H } ^ { + } [ : \ddot { \mathrm { C } } 1 : ] ^ { - }$ ![](/images/questions/chem-nomenclature/image-033.jpg)

  • A. A. Na 的原子结构示意图:(+11) 281
  • B. B. $\mathrm { N } _ { 2 }$ 分子的结构式: $\mathrm { N } = \mathrm { N }$
  • C. C. HCl 的电子式: $\mathrm { H } ^ { + } [ : \ddot { \mathrm { C } } 1 : ] ^ { - }$
  • D. D. $\mathrm { H } _ { 2 } \mathrm { O }$ 分子的球棍模型 :

Answer: A

Solution: 试题分析 :A.Na的原子序数是 11,其原子结构示意图为(+11)281/,A正确; B. $\mathrm { N } _ { 2 }$ 分子中存在三键,结构式为 $\mathrm { N } \equiv \mathrm { N } , \mathrm { B }$ 错误; $\mathrm { C } . \mathrm { HCl }$ 是共价化合物,电子式为 $\mathrm { H } \times \ddot { \mathrm { C } } \mathrm { l } :$ ,C 错误;D. $\mathrm { H } _ { 2 } \mathrm { O }$ 分子的比例模型为 ![](/images/questions/chem-nomenclature/image-034.jpg) ,D 错误,答案选 A。 考点:考查化学用语判断

Question 36: 42.对下列化学用语的理解正确的是() <img class="imgSvg" id = "mi1mzfw1yqxeudhajd" src="data:image/svg+xml;base64,PH...

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            "></text></g></svg>"/> ![](/images/questions/chem-nomenclature/image-035.jpg) ![](/images/questions/chem-nomenclature/image-036.jpg) 既可以表示甲烷分子,也可以表示四氯化碳分子

  • A. A. 苯的分子式
  • B. B. 丙烷分子的球棍模型
  • C. C. 甲酸乙酯的结构简式 $\mathrm { CH } _ { 3 } \mathrm { COOCH } _ { 3 }$
  • D. D. 空间充填模型

Answer: B

Solution: A.苯的分子式为 $\mathrm { C } _ { 6 } \mathrm { H } _ { 6 }$ ,苯的结构简式为 <img class="imgSvg" id = "mi1mzfxe6x8ntm57kok" src="data:image/svg+xml;base64,<svg id="smiles-mi1mzfxe6x8ntm57kok" xmlns="http://www.w3.org/2000/svg" viewBox="0 0 147 96.55962871301199" style="width: 146.99999999997465px; height: 96.55962871301199px; overflow: visible;"><defs><linearGradient id="line-mi1mzfxe6x8ntm57kok-1" gradientUnits="userSpaceOnUse" x1="85.91461646735897" y1="69.9966456972478" x2="98.51463605658134" y2="48.17281683173448"><stop stop-color="currentColor" offset="20%"></stop><stop stop-color="currentColor" offset="100%"></stop></linearGradient><linearGradient id="line-mi1mzfxe6x8ntm57kok-3" gradientUnits="userSpaceOnUse" x1="89.24997551344667" y1="75.55962871301199" x2="104.99999999997463" y2="48.279842631120346"><stop stop-color="currentColor" offset="20%"></stop><stop stop-color="currentColor" offset="100%"></stop></linearGradient><linearGradient id="line-mi1mzfxe6x8ntm57kok-5" gradientUnits="userSpaceOnUse" x1="89.25002448651524" y1="21.000028274614326" x2="104.99999999997463" y2="48.279842631120346"><stop stop-color="currentColor" offset="20%"></stop><stop stop-color="currentColor" offset="100%"></stop></linearGradient><linearGradient id="line-mi1mzfxe6x8ntm57kok-7" gradientUnits="userSpaceOnUse" x1="57.74997551345936" y1="75.55960043839765" x2="89.24997551344667" y2="75.55962871301199"><stop stop-color="currentColor" offset="20%"></stop><stop stop-color="currentColor" offset="100%"></stop></linearGradient><linearGradient id="line-mi1mzfxe6x8ntm57kok-9" gradientUnits="userSpaceOnUse" x1="60.9000193970961" y1="26.670002827459147" x2="86.10001939708594" y2="26.67002544715061"><stop stop-color="currentColor" offset="20%"></stop><stop stop-color="currentColor" offset="100%"></stop></linearGradient><linearGradient id="line-mi1mzfxe6x8ntm57kok-11" gradientUnits="userSpaceOnUse" x1="57.75002448652795" y1="21" x2="89.25002448651524" y2="21.000028274614326"><stop stop-color="currentColor" offset="20%"></stop><stop stop-color="currentColor" offset="100%"></stop></linearGradient><linearGradient id="line-mi1mzfxe6x8ntm57kok-13" gradientUnits="userSpaceOnUse" x1="48.485364135517" y1="48.17277192511958" x2="61.0853445462845" y2="69.99662341032437"><stop stop-color="currentColor" offset="20%"></stop><stop stop-color="currentColor" offset="100%"></stop></linearGradient><linearGradient id="line-mi1mzfxe6x8ntm57kok-15" gradientUnits="userSpaceOnUse" x1="42" y1="48.27978608189166" x2="57.74997551345936" y2="75.55960043839765"><stop stop-color="currentColor" offset="20%"></stop><stop stop-color="currentColor" offset="100%"></stop></linearGradient><linearGradient id="line-mi1mzfxe6x8ntm57kok-17" gradientUnits="userSpaceOnUse" x1="42" y1="48.27978608189166" x2="57.75002448652795" y2="21"><stop stop-color="currentColor" offset="20%"></stop><stop stop-color="currentColor" offset="100%"></stop></linearGradient></defs><mask id="text-mask-mi1mzfxe6x8ntm57kok"><rect x="0" y="0" width="100%" height="100%" fill="white"></rect></mask><style>
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            "></text></g></svg>"/> ,A 错误 ; B.丙烷分子的球棍模型为 ![](/images/questions/chem-nomenclature/image-037.jpg) ,B正确; C.甲酸乙酯的结构简式为 $\mathrm { HCOOCH } _ { 2 } \mathrm { CH } _ { 3 } \mathrm { CH } _ { 3 } \mathrm { COOH } _ { 3 } { } _ { \text {是乙酸甲酯 } }$ ,C 错误; D.氯原子半径大于碳原子半径,空间充填模型不能表示四氯化碳分子,D 错误 ; 答案选 B。

Question 37: 43.下列化学用语使用正确的是() <img class="imgSvg" id = "mi1mzfw29pijnkzfp7d" src="data:image/svg+xml;base64,PHN...

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  • A. A. 乙烯分子中碳原子之间的 $\sigma$ 键电子云图:
  • B. B. 二氧化碳分子的空间填充模型:
  • C. C. $\mathrm { H } ^ { - }$的结构示意图为(+1)$\frac { 1 } { 2 }$
  • D. D. 的电子式为 | $: \overline { \mathrm { F } } : \overline { \mathrm { B } } : \overline { \mathrm { F } } :$ |

Answer: C

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化学用语与方程式

37 练习题

知识点概述

化学用语与方程式是化学学科的基础语言,主要包括元素符号、化学式、化合价、离子符号及化学方程式的书写与配平。在考试中,这部分内容常以选择题形式出现,重点考查对基本规则的掌握和细节判断能力,如化合价计算、化学式正误辨析、方程式配平等。

题目数量:37

重点内容

  • 1常见元素符号与化合价的计算规则
  • 2化学式(分子式、结构式、电子式)的正确书写与命名
  • 3离子符号与原子结构示意图的识别
  • 4化学方程式的配平与反应类型判断

学习建议

建议通过分类记忆常见元素化合价,并结合具体化合物练习书写,注意区分相似化学式的命名规则。

会做单题 ≠ 会考试

按官方大纲编写的完整模拟卷,多知识点综合出题