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Next exam on November 14 – 15, 2026:
All concepts

Steady Current and DC Circuits

恒定电流与直流电路

The definition and microscopic expression of current, Ohm's law, voltage and resistance in series and parallel circuits, and reading current–voltage characteristic curves.

11 real-exam questions · 4 sittings19 in mock papers43 practice

Formulas

  • Definition of electric current

    Definition
    I=qtI=\frac{q}{t}

    Applies when:q is the charge crossing a section in time t; microscopically I=nqSv

  • Ohm's law

    Law
    I=URI=\frac{U}{R}

    Applies when:Linear ohmic elements only; non-linear ones need their I–V characteristic curve

  • Resistors in series

    Formula
    R=R1+R2+⋯+RnR=R_1+R_2+\cdots+R_n

    Applies when:The current is the same throughout; voltage divides in proportion to resistance

  • Resistors in parallel

    Formula
    1R=1R1+1R2+⋯+1Rn\frac{1}{R}=\frac{1}{R_1}+\frac{1}{R_2}+\cdots+\frac{1}{R_n}

    Applies when:The voltage is the same across each; current divides inversely with resistance

How the real exam tests it

Questions from real CSCA papers that test this concept. Work each one out before you open the answer.

  1. CSCA Physics December 2025 Past Paper
    The total resistance when two resistors of 200Ω200 \Omega and 300Ω300 \Omega are connected in parallel is ( ).
    • A.500Ω500 \Omega
    • B.600Ω600 \Omega
    • C.100Ω100 \Omega
    • D.120Ω120 \Omega
    Show answer & solution

    Answer: D

    1 Parallel resistors: 1/R=1/200+1/300=(3+2)/600=5/6001 / \mathrm { R } = 1 / 200 + 1 / 300 = ( 3 + 2 ) / 600 = 5 / 600. 2 R=600/5=120Ω\mathrm { R } = 600 / 5 = 120 \Omega.
    See it in the full CSCA Physics December 2025 Past Paper
  2. CSCA Physics March 2026 Past Paper
    Two resistors ( 2Ω2 \Omega and 8Ω8 \Omega ) connected in parallel have a total resistance of
    • A.1.6Ω1.6 \Omega
    • B.2Ω2 \Omega
    • C.4Ω4 \Omega
    • D.10Ω10 \Omega
    Show answer & solution

    Answer: A

    1/R=1/2+1/8=5/8,R=1.6Ω1 / R = 1 / 2 + 1 / 8 = 5 / 8 , R = 1.6 \Omega. Parallel resistance is always less than the smallest resistor ( 2Ω2 \Omega ), eliminating B, C, D. Answer: A.
    Take the full CSCA Physics March 2026 Past Paper — timed & graded
  3. CSCA Physics April 2026 Past Paper
    A 100Ω100 \Omega resistor and a 200Ω200 \Omega resistor are connected in parallel. Their equivalent resistance is
    • A.150Ω150 \Omega
    • B.50Ω50 \Omega
    • C.300Ω300 \Omega
    • D.66.7Ω66.7 \Omega
    Show answer & solution

    Answer: D

    1R=1100+1200=3200\frac { 1 } { R } = \frac { 1 } { 100 } + \frac { 1 } { 200 } = \frac { 3 } { 200 }, so R=2003≈66.7ΩR = \frac { 200 } { 3 } \approx 66.7 \Omega.
    Take the full CSCA Physics April 2026 Past Paper — timed & graded

Real-exam evidence

Recorded past-paper appearances are listed below; online verification is labelled separately.

11 questions across 4 sittings1 of 4 sittings available to verify free online

19 questions across 6 mock papers — our own papers, so a coverage signal rather than real-exam evidence

43 related practice questions availablePractise free: DC Circuits

Sitting evidence comes from the CSCA past papers on record; questions whose original paper is missing are excluded, and sprint papers are deliberately not counted.

Glossary

Related concepts