Circular Motion

How the real exam tests it

Questions from real CSCA papers that test this concept. Work each one out before you open the answer.

1. CSCA Physics December 2025 Past Paper
   A point moves in uniform circular motion with a speed of $\mathrm { v } = 6 \mathrm {~m} \cdot \mathrm {~s} ^ { - 1 }$. The radius of the circular path is $R = 3 \mathrm {~m}$. The angular velocity of the point is ().
   • A．$2 \pi \mathrm { rad } / \mathrm { s }$
   • B．$3 \pi \mathrm { rad } / \mathrm { s }$
   • C．$2 \mathrm { rad } / \mathrm { s }$
   • D．$3 \mathrm { rad } / \mathrm { s }$
   Show answer & solution

   Answer: C

   1 For uniform circular motion: $\omega = v / R = 6 / 3 = 2 \mathrm { rad } / \mathrm { s }$.
   See it in the full CSCA Physics December 2025 Past Paper
2. CSCA Physics March 2026 Past Paper
   An object in uniform circular motion has radius 0.5 m and period 2 s . Its linear speed is
   • A．$0.5 \pi \mathrm {~m} / \mathrm { s }$
   • B．$\pi \mathrm { m } / \mathrm { s }$
   • C．$1.5 \pi \mathrm {~m} / \mathrm { s }$
   • D．$2 \pi \mathrm {~m} / \mathrm { s }$
   Show answer & solution

   Answer: A

   $\mathrm { v } = 2 \pi \mathrm { r } / \mathrm { T } = 2 \pi \times 0.5 / 2 = 0.5 \pi \mathrm {~m} / \mathrm { s }$. Answer: A．
   Take the full CSCA Physics March 2026 Past Paper — timed & graded
3. CSCA Physics April 2026 Past Paper
   A particle undergoes uniform circular motion with linear speed $v = 4 \mathrm {~m} / \mathrm { s }$ and radius $R = 2 \mathrm {~m}$. Its angular velocity is
   • A．$2 \mathrm { rad } / \mathrm { s }$
   • B．$8 \mathrm { rad } / \mathrm { s }$
   • C．$4 \mathrm { rad } / \mathrm { s }$
   • D．$1 \mathrm { rad } / \mathrm { s }$
   Show answer & solution

   Answer: A

   $\omega = \frac { v } { R } = \frac { 4 } { 2 } = 2 \mathrm { rad } / \mathrm { s }$.
   Take the full CSCA Physics April 2026 Past Paper — timed & graded