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Next exam on November 14 – 15, 2026:
All concepts

Galvanic Cells

原电池

How a galvanic cell turns chemical energy into electrical energy, how to identify the two electrodes, and how to write the half-equations.

2 real-exam questions · 2 sittings1 in mock papers

How the real exam tests it

Questions from real CSCA papers that test this concept. Work each one out before you open the answer.

  1. CSCA Chemistry December 2025 Past Paper
    Scientists developed a room-temperature Na-O₂ rechargeable battery. NaClO₄ is dissolved in an organic solvent as the electrolyte. Metallic sodium and Pt/C-loaded carbon cloth are used as electrode materials. The overall cell reaction is: O₂ + 2Na = Na₂O₂. Which statement is correct? ( )
    • A. During discharge, ClO₄- moves toward the positive electrode
    • B. During discharge, O₂ is released; during charge, O₂ is absorbed
    • C. During discharge, the negative electrode reaction is: Na+ + e- → Na
    • D. During charge, the positive electrode reaction is: Na₂O₂ - 2e- → 2Na+ + O₂
    Show answer & solution

    Answer: D

    Answer: D Discharge: Na is oxidized at the negative electrode, Na − e⁻ → Na⁺, and O₂ is reduced to form Na₂O₂. Charging reverses this: Na₂O₂ loses electrons at the positive electrode and releases O₂, so the positive electrode reaction is Na₂O₂ − 2e⁻ → 2Na⁺ + O₂.
    See it in the full CSCA Chemistry December 2025 Past Paper
  2. CSCA Chemistry March 2026 Past Paper
    Pb+PbO2+2H2SO4⇌2PbSO4+2H2O\mathrm { Pb } + \mathrm { PbO } _ { 2 } + 2 \mathrm { H } _ { 2 } \mathrm { SO } _ { 4 } \rightleftharpoons 2 \mathrm { PbSO } _ { 4 } + 2 \mathrm { H } _ { 2 } \mathrm { O }. Which is correct?
    • A.During discharge, PbO2\mathrm { PbO } _ { 2 } undergoes reduction
    • B.During discharge, cathode reaction: Pb2++2e−→Pb\mathrm { Pb } ^ { 2 + } + 2 \mathrm { e } ^ { - } \rightarrow \mathrm { Pb }
    • C.During charging, anode connects to power source's negative terminal
    • D.During charging, [H+]\left[ \mathrm { H } ^ { + } \right]in solution increases
    Show answer & solution

    Answer: A

    Discharge: PbO2\mathrm { PbO } _ { 2 } at cathode, Pb(+4→+2)\mathrm { Pb } ( + 4 \rightarrow + 2 ) gains electrons == reduction ✓\checkmark . B\mathrm { B } : anode is oxidation. C: anode connects to positive terminal. Answer: A.
    Take the full CSCA Chemistry March 2026 Past Paper — timed & graded

Real-exam evidence

Recorded past-paper appearances are listed below; online verification is labelled separately.

2 questions across 2 sittings1 of 2 sittings available to verify free online

1 question across 1 mock paper — our own papers, so a coverage signal rather than real-exam evidence

Related topic practice:Practise free: Redox Reactions

Sitting evidence comes from the CSCA past papers on record; questions whose original paper is missing are excluded, and sprint papers are deliberately not counted.

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