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Hingga ujian berikutnya 14–15 November 2026:
Semua konsep

Velocity and Acceleration

速度与加速度

Average versus instantaneous velocity, the defining equation for acceleration and its vector nature, and how change in velocity relates to acceleration.

6 soal ujian asli · 4 kali ujian15 soal tryout7 soal latihan

Ujian CSCA dikerjakan dalam bahasa Mandarin atau Inggris — peserta memilih sendiri. Karena itu konsep dan rumus di sini disajikan dalam kedua bahasa tersebut; halaman ini menampilkan versi bahasa Inggris.

Rumus

  • Average velocity

    Definisi
    vˉ=ΔxΔt\bar{v}=\frac{\Delta x}{\Delta t}

    Berlaku bila:Δx is the displacement; average velocity is a vector along the displacement

  • Definition of acceleration

    Definisi
    a=ΔvΔt=v−v0ta=\frac{\Delta v}{\Delta t}=\frac{v-v_0}{t}

    Berlaku bila:Directed along the change in velocity Δv, not necessarily along the velocity itself

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Soal dari ujian CSCA sebenarnya yang menguji konsep ini. Kerjakan sendiri dulu sebelum membuka jawabannya.

  1. CSCA Physics December 2025 Past Paper
    As shown in the figure, an object moves from point AA through point BB to point CC along two semicircles with radius R=6 mR = 6 \mathrm {~m}, taking a time of t=4 st = 4 \mathrm {~s}. The magnitude of its average velocity is (). Question 13 diagram
    • A.6 m/s6 \mathrm {~m} / \mathrm { s }
    • B.12 m/s12 \mathrm {~m} / \mathrm { s }
    • C.6π m/s6 \pi \mathrm {~m} / \mathrm { s }
    • D.3π m/s3 \pi \mathrm {~m} / \mathrm { s }
    Lihat jawaban & pembahasan

    Jawaban: A

    1 Displacement is the straight line from A to C. The two semicircles each have diameter 2R=12 m2 R = 12 \mathrm {~m}, so the displacement is x=4R=24 mx = 4 R = 24 \mathrm {~m}. 2 Average velocity =x/t=24 m/4 s=6 m/s= x / t = 24 \mathrm {~m} / 4 \mathrm {~s} = 6 \mathrm {~m} / \mathrm { s }, option A. 3 Note: the path length is 2πR=12π m2 \pi R = 12 \pi \mathrm {~m}, so 3π m/s3 \pi \mathrm {~m} / \mathrm { s } (option D) is the average speed, not the average velocity.
    Lihat di CSCA Physics December 2025 Past Paper lengkap
  2. CSCA Physics March 2026 Past Paper
    The x-t graph for a toy car in linear motion is shown. Which statement is correct? Question 12 diagram
    • A.Displacement from 0−4 s0 - 4 \mathrm {~s} is 8 m
    • B.Velocity from 0−4 s0 - 4 \mathrm {~s} is 1.0 m/s1.0 \mathrm {~m} / \mathrm { s }
    • C.Average velocity from 0−5 s0 - 5 \mathrm {~s} is 0.8 m/s0.8 \mathrm {~m} / \mathrm { s }
    • D.Velocity from 4−5 s4 - 5 \mathrm {~s} is 0.8 m/s0.8 \mathrm {~m} / \mathrm { s }
    Lihat jawaban & pembahasan

    Jawaban: B

    From graph: 0−4 s,x0 - 4 \mathrm {~s} , x goes from 0 to 4 m linearly. A: displacement is 4 m , not 8 . B:v=4/4=1.0 m/sB : v = 4 / 4 = 1.0 \mathrm {~m} / \mathrm { s }, correct. C: at 5 s position returns to 0 , average velocity =0/5=0= 0 / 5 = 0. D: 4−5 s4 - 5 \mathrm {~s}, displacement =4 m= 4 \mathrm {~m} in 1 s , speed =4 m/s= 4 \mathrm {~m} / \mathrm { s }. Answer: B.
    Kerjakan CSCA Physics March 2026 Past Paper lengkap — berwaktu & dinilai
  3. CSCA Physics April 2026 Past Paper
    As shown in the figure, an object travels along a path consisting of two semicircles end-to-end (each of radius 4 m ) from AA through BB to CC. Points A,B,CA , B , C are collinear along the east-west direction. The travel takes 2 s . The magnitude of the average velocity is Question 14 diagram
    • A.4 m/s4 \mathrm {~m} / \mathrm { s }
    • B.0 m/s0 \mathrm {~m} / \mathrm { s }
    • C.2 m/s2 \mathrm {~m} / \mathrm { s }
    • D.8 m/s8 \mathrm {~m} / \mathrm { s }
    Lihat jawaban & pembahasan

    Jawaban: D

    Each semicircle has diameter 2R=8 m2 R = 8 \mathrm {~m}, so ∣AB∣=∣BC∣=8 m| A B | = | B C | = 8 \mathrm {~m}. Because AA, B,CB , C are collinear, the total displacement is ∣AC∣=16 m| A C | = 16 \mathrm {~m}. Average velocity =∣AC∣t=162=8 m/s= \frac { | A C | } { t } = \frac { 16 } { 2 } = 8 \mathrm {~m} / \mathrm { s }.
    Kerjakan CSCA Physics April 2026 Past Paper lengkap — berwaktu & dinilai

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