33. Classification methods play a very important role in the development of chemistry, the following classification criteria are reasonable
(1) According to the number of hydrogen atoms contained in the acid molecule will be divided into mono-acids, dibasic acids, etc.
(2) Chemical reactions are categorized into redox reactions and non-redox reactions according to whether there is a transfer of electrons in the reaction.
(3) According to whether the dispersion system has the Tyndall phenomenon, the dispersion system is divided into solution, colloid and turbid liquid.
(4) classify oxides into acidic and basic oxides according to the presence or absence of metal elements in the oxides
(5) electrolytes are classified into strong and weak electrolytes according to whether the electrolyte can be completely ionized in the molten state.
- A. A. (1) (2) (5)
- B. B. (2) (4)
- C. C. (1) (3) (5)
- D. D. (2)
Answer: D
Solution: (1) It is wrong to classify acids into mono acids, di acids, etc. on the basis of the number of hydrogen ions that can be ionized from the acid molecule and not on the basis of the number of hydrogen atoms. (2) Correct. (3) Classification of dispersions into solutions, colloids and turbidites on the basis of the size of the diameter of the dispersions in the dispersion system is incorrect. (4) Classification of oxides into metallic and nonmetallic oxides based on the presence or absence of metallic elements in the oxides, incorrect.
(5) Electrolytes are divided into strong and weak electrolytes according to whether they can be completely ionized in aqueous solution or in the molten state. Therefore, only (2) is correct.
$34 . \mathrm { B }$
[Knowledge Points] Four basic reaction types, chemical formula and valency
[Analysis]According to the diagram, the reaction equation is $\mathrm { CO } _ { 2 } + 4 \mathrm { H } _ { 2 } = \mathrm { CH } _ { 4 } + 2 \mathrm { H } _ { 2 } \mathrm { O }$.
A. $\mathrm { CO } _ { 2 } + 4 \mathrm { H } _ { 2 } = \mathrm { CH } _ { 4 } + 2 \mathrm { H } _ { 2 } \mathrm { O }$ is a reaction between a monomer and a compound to form two compounds, not a replacement reaction, so A is wrong;
B. A is carbon dioxide, carbon valence is + 4; C is methane, carbon valence is - 4, so B is correct;
C. The equation of the reaction is $\mathrm { CO } _ { 2 } + 4 \mathrm { H } _ { 2 } = \mathrm { CH } _ { 4 } + 2 \mathrm { H } _ { 2 } \mathrm { O }$, and the ratio of the number of carbon dioxide and hydrogen molecules in the reaction is $1 : 4$, so C is wrong;
D. A is carbon dioxide and C is methane, the mass ratio of carbon dioxide to methane in the reaction is $11 : 4$, so D is wrong;
B.
$35 . \mathrm { B }$
[Knowledge Points] Evaporation and crystallization, laboratory production of chlorine gas, properties and applications of colloids
[Detailed Explanation] A. The evaporation operation to obtain NaCl crystals from salt water, evaporation needs to be stirred with a glass rod, the lack of glass rods, can not complete the experiment, A does not fit the question;
B. Sediment particles can not pass through the filter paper, colloidal particles can pass through the filter paper, aluminum hydroxide colloidal sediment can be removed by filtration, the use of instruments have funnel (with filter paper), beaker, glass rod, B meets the title;
C. The steps for preparing $30 \%$'s sodium chloride solution with NaCl solids are: calculating, weighing, measuring, dissolving, bottling, etc., and the instruments needed are: balance, medicine spoon, beaker, glass rod, measuring cylinder, and rubber-tipped burette, etc., and the lack of a medicine spoon and rubber-tipped burette in the instruments provided can't complete the preparation of the solution, and C doesn't fit the meaning of the question;
D. Hydrogen chloride is volatile, and the chlorine gas produced is mixed with hydrogen chloride and water, so it is necessary to remove the impurities with a gas-washing bottle $\mathrm { HCl } , \mathrm { H } _ { 2 } \mathrm { O }$, and finally use a gas collection bottle to collect the dry, pure $\mathrm { Cl } _ { 2 }$, and the lack of a gas-washing bottle, a gas collection bottle, it is impossible to complete the experiment, and the D is inconsistent with the meaning of the question; so the answer is B.