Answer: D
Solution: A. Crude salt contains sediment, $\mathrm { Ca } ^ { 2 + } , \mathrm { Mg } ^ { 2 + } , \mathrm { SO } ^ { 2 - }$ and other impurities, first add $\mathrm { BaCl } _ { 2 } , \mathrm { Na } _ { 2 } \mathrm { CO } _ { 3 }$, NaOH to remove $\mathrm { SO } ^ { 4 } , \mathrm { Ca } ^ { 2 + } , \mathrm { Mg } ^ { 2 + }$, and then filtration to remove the sediment and precipitation, and finally add dilute hydrochloric acid to adjust the pH, to remove the excessive $\mathrm { Na } _ { 2 } \mathrm { CO } _ { 3 } , \mathrm { NaOH }$, so as to obtain refined saturated brine, and then electrolysis to obtain chlorine gas, that is: $2 \mathrm { NaCl } + 2 \mathrm { H } _ { 2 } \mathrm { O }$. FORMULA_3]], so as to obtain refined saturated brine, and then electrolyze to obtain chlorine gas, that is: $2 \mathrm { NaCl } + 2 \mathrm { H } _ { 2 } \mathrm { O }$
$\xlongequal { \text { electrolysis } } 2 \mathrm { NaOH } + \mathrm { H } _ { 2 } \uparrow + \mathrm { Cl } _ { 2 } \uparrow$, and the resulting $\mathrm { Cl } _ { 2 }$ reacts with milk of lime to produce bleach, i.e., $2 \mathrm { Cl } _ { 2 } + 2 \mathrm { Ca } ( \mathrm { OH } ) _ { 2 } = \mathrm { CaCl } _ { 2 } + \mathrm { Ca } ( \mathrm { ClO } ) _ { 2 } + 2 \mathrm { H } _ { 2 } \mathrm { O }$, A is correct;
B. Bitter brine contains $\mathrm { Br } ^ { - }$, which is acidified and passed through chlorine gas to obtain bromine water ($\mathrm { Cl } _ { 2 } + 2 \mathrm { Br } ^ { - } = 2 \mathrm { Cl } ^ { - } + \mathrm { Br } _ { 2 }$), and then passed through hot air to $\mathrm { SO } _ { 2 }$ aqueous solution ($\mathrm { Br } _ { 2 } + \mathrm { SO } _ { 2 } + 2 \mathrm { H } _ { 2 } \mathrm { O } = \mathrm { H } _ { 2 } \mathrm { SO } _ { 4 } + 2 \mathrm { HBr }$), and finally passed through chlorine gas to obtain crude bromine ($\mathrm { SO } _ { 2 }$). Finally, chlorine is added and distilled to obtain crude bromine ( $2 \mathrm { HBr } + \mathrm { Cl } _ { 2 } = 2 \mathrm { HCl } + \mathrm { Br } _ { 2 }$), B is correct;
C. Dried kelp is cauterized and leached with water to obtain a solution containing iodine ions, then $\mathrm { H } _ { 2 } \mathrm { O } _ { 2 }$ is added to obtain iodine water, and finally iodine monomers are obtained by extraction, partitioning, and distillation, C is correct;
D. Alum ionization can react with water to produce colloids just adsorption of suspended impurities in water precipitation, can not remove seawater in the $\mathrm { Mg } ^ { 2 + } , \mathrm { Na } ^ { + } , \mathrm { Br } ^ { - } , \mathrm { Cl } ^ { - }$ plasma, can not get more pure drinking water, D error;