Skip to main content
Next exam on November 14 – 15, 2026:
Back to glossary
physicalDifficulty: Basicacid-basesolutioninorganic
Share

碱jiǎn

base
4 min read
Updated August 25, 2026
Complete

Core Concept

A base (碱) is a compound that ionizes in water to produce OH−\mathrm{OH^-} as its only anion.

It is the mirror image of the acid definition, and the same trap applies: producing OH−\mathrm{OH^-} is not enough — it must be the only anion. Cu2(OH)2CO3\mathrm{Cu_2(OH)_2CO_3} releases OH−\mathrm{OH^-} but also CO32−\mathrm{CO_3^{2-}}, so it is a basic salt (碱式盐), not a base.

NaOH→Na++OH−\mathrm{NaOH \rightarrow Na^+ + OH^-}

Ba(OH)2→Ba2++2OH−\mathrm{Ba(OH)_2 \rightarrow Ba^{2+} + 2OH^-}

Strong vs Weak

Strong base 强碱Weak base 弱碱
Ionizationcompletepartial, reversible
Arrow→\rightarrow⇌\rightleftharpoons
ExamplesNaOH\mathrm{NaOH}, KOH\mathrm{KOH}, Ba(OH)2\mathrm{Ba(OH)_2}, Ca(OH)2\mathrm{Ca(OH)_2}NH3⋅H2O\mathrm{NH_3 \cdot H_2O}, Cu(OH)2\mathrm{Cu(OH)_2}, Fe(OH)3\mathrm{Fe(OH)_3}

A distinction CSCA loves: Ca(OH)2\mathrm{Ca(OH)_2} is a strong base but only slightly soluble. "Strong" describes how completely the dissolved portion ionizes; "soluble" describes how much dissolves. They are independent properties, and confusing them is a marked error.

Solubility Rules Worth Memorising

Only NaOH\mathrm{NaOH}, KOH\mathrm{KOH}, Ba(OH)2\mathrm{Ba(OH)_2} and NH3⋅H2O\mathrm{NH_3 \cdot H_2O} are freely soluble. Ca(OH)2\mathrm{Ca(OH)_2} is slightly soluble; all other common hydroxides are insoluble precipitates — which is exactly why they show up in 沉淀 questions.

Characteristic precipitate colours: Cu(OH)2\mathrm{Cu(OH)_2} blue, Fe(OH)3\mathrm{Fe(OH)_3} red-brown, Fe(OH)2\mathrm{Fe(OH)_2} white turning grey-green then red-brown in air.

Characteristic Reactions

  1. With indicators: turns red litmus blue; phenolphthalein turns pink
  2. With acids (neutralization): NaOH+HCl→NaCl+H2O\mathrm{NaOH + HCl \rightarrow NaCl + H_2O}
  3. With acidic oxides: 2NaOH+CO2→Na2CO3+H2O\mathrm{2NaOH + CO_2 \rightarrow Na_2CO_3 + H_2O}
  4. With certain salts: 2NaOH+CuSO4→Cu(OH)2↓+Na2SO4\mathrm{2NaOH + CuSO_4 \rightarrow Cu(OH)_2\downarrow + Na_2SO_4}

Reaction 3 is the basis of CO2\mathrm{CO_2} absorption questions; reaction 4 drives most precipitate-identification items.

CSCA Practice Problems

💡 Note: These problems follow the CSCA exam syllabus and Chinese standardized test formats.

Example 1: Basic (Difficulty ★★☆☆☆)

Which statement about Ca(OH)2\mathrm{Ca(OH)_2} is correct?

Options:

  • A. It is a weak base because it is only slightly soluble
  • B. It is a strong base even though it is only slightly soluble
  • C. It is not a base because it is a solid
  • D. It produces H+\mathrm{H^+} in solution

Detailed Solution:

Solubility and strength are separate properties:

  • Solubility — how much dissolves. Ca(OH)2\mathrm{Ca(OH)_2} is only slightly soluble.
  • Strength — how completely the dissolved portion ionizes. The part that does dissolve ionizes completely, so it is a strong base.

Option A is the intended trap, conflating the two.

Answer: B


Example 2: Intermediate (Difficulty ★★★☆☆)

NaOH\mathrm{NaOH} solution is added dropwise to a solution containing both FeCl3\mathrm{FeCl_3} and CuSO4\mathrm{CuSO_4}. What is observed?

Options:

  • A. A white precipitate only
  • B. A blue precipitate only
  • C. A red-brown precipitate and a blue precipitate
  • D. No precipitate forms

Detailed Solution:

  1. Both Fe(OH)3\mathrm{Fe(OH)_3} and Cu(OH)2\mathrm{Cu(OH)_2} are insoluble, so both precipitate: FeCl3+3NaOH→Fe(OH)3↓+3NaCl\mathrm{FeCl_3 + 3NaOH \rightarrow Fe(OH)_3\downarrow + 3NaCl} CuSO4+2NaOH→Cu(OH)2↓+Na2SO4\mathrm{CuSO_4 + 2NaOH \rightarrow Cu(OH)_2\downarrow + Na_2SO_4}

  2. Colours: Fe(OH)3\mathrm{Fe(OH)_3} is red-brown, Cu(OH)2\mathrm{Cu(OH)_2} is blue.

Answer: C

Exam habit worth building: whenever a hydroxide precipitates, state its colour — colour is frequently the actual thing being marked.

Common Mistakes

❌ Mistake 1: Equating "strong" with "soluble"

Ca(OH)2\mathrm{Ca(OH)_2} is strong but sparingly soluble; NH3⋅H2O\mathrm{NH_3 \cdot H_2O} is very soluble but weak.

❌ Mistake 2: Calling any OH−\mathrm{OH^-}-producing compound a base

Basic salts release OH−\mathrm{OH^-} too. The anion must be only OH−\mathrm{OH^-}.

❌ Mistake 3: Writing →\rightarrow for ammonia solution

NH3⋅H2O⇌NH4++OH−\mathrm{NH_3 \cdot H_2O \rightleftharpoons NH_4^+ + OH^-} — weak, so reversible.

❌ Mistake 4: Omitting the ↓\downarrow symbol

Precipitates must be marked, and their colour stated when asked for observations.

Study Tips

  1. ✅ Learn acid and base definitions as a matched pair — cation test vs anion test
  2. ✅ Memorise the four soluble bases; everything else precipitates
  3. ✅ Keep "strong/weak" and "soluble/insoluble" on separate axes
  4. ✅ Learn precipitate colours — they are worth marks by themselves
  5. ✅ Write full ionic equations to make the classification obvious

💡 Exam Tip: 碱 appears 28 times in the sampled CSCA chemistry papers, right alongside 酸 and 盐. Most items are classification or precipitate-observation questions.

How the real exam tests it

Questions from real CSCA papers that test this term. Work each one out before you open the answer.

  1. CSCA Chemistry April 2026 Past Paper
    At room temperature, which of the following aqueous solutions has a pH greater than 7? ( )
    • A. CH3COONa\mathrm{CH_{3}COONa}
    • B. NaCl
    • C. NH4Cl\mathrm{NH_{4}Cl}
    • D. NH4NO3\mathrm{NH_{4}NO_{3}}
    Show answer & solution

    Answer: A

    Answer: A CH3COONa\mathrm{CH_{3}COONa} is the salt of a strong base and a weak acid; it hydrolyzes to give a basic solution, pH > 7.
    Take the full CSCA Chemistry April 2026 Past Paper — timed & graded
  2. CSCA Chemistry March 2026 Past Paper
    Which aqueous solution has pH>7\mathrm { pH } > 7 at room temperature?
    • A.KCl
    • B.Na2CO3\mathrm { Na } _ { 2 } \mathrm { CO } _ { 3 }
    • C.NH4Cl\mathrm { NH } _ { 4 } \mathrm { Cl }
    • D.Al2(SO4)3\mathrm { Al } _ { 2 } \left( \mathrm { SO } _ { 4 } \right) _ { 3 }
    Show answer & solution

    Answer: B

    Na2CO3:CO32−\mathrm { Na } _ { 2 } \mathrm { CO } _ { 3 } : \mathrm { CO } _ { 3 } { } ^ { 2 - } hydrolysis → basic ( pH>7\mathrm { pH } > 7 ). A: neutral. C/D: acidic. Answer: B.
    Take the full CSCA Chemistry March 2026 Past Paper — timed & graded
  3. CSCA Chemistry April 2026 Past Paper
    Given the reaction Cl2\mathrm{Cl_{2}} + 2NaOH = NaCl + Y + H2O\mathrm{H_{2}O}, the molecular formula of Y is ( ).
    • A. HCl
    • B. NaClO
    • C. HClO
    • D. NaClO3\mathrm{NaClO_{3}}
    Show answer & solution

    Answer: B

    Answer: B Balancing by conservation of atoms: Cl2\mathrm{Cl_{2}} + 2NaOH = NaCl + NaClO + H2O\mathrm{H_{2}O}, so Y is NaClO.
    Take the full CSCA Chemistry April 2026 Past Paper — timed & graded

Practice Exercises

Practice to reinforce your understanding